Exercise 8.4 question 5 part ix class 10
Prove:
(cosec A-sin A)(secA-cosA)=1/(tanA+cotA )
Or
(cosec A-sin A)(secA-cosA)(tanA+cotA )=1
Strategy 🧠
Express cosec A and sec A in terms of sin A and cos A
Hint 💡
Trigonometric identity:
cos^2 A + sin^2 A = 1
1 + tan^2 A = sec^2 A
cot^2 A + 1 = cosec^2A
Algebraic Identity
(a+b)^2 = a^2 + b^2 + 2ab
(a+b)^3 = (a+b)(a^2 -ab + b^2)
a^2 - b^2 = (a-b)(a+b)
Note📝
The above question is taken from NCERT book Ch-8 exercise 8.4 question 5 part 9 Trigonometry.
Read it 📖
Identity:
An equation is called an identity when it is true for all values of the variables involved in it.
Trigonometric identity :
Similarly, an equation involving trigonometric ratios of an angle is called a trigonometric identity, if it is true for all values of the angle(s) involved.
Practice👩🏫:
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Негізгі бет Prove (cosec A-sin A)(sec A -cos A)=1/(tan A + cot A )| Ex 8.4 Q5 part (ix)
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