The PDF of session will attached to the link pinned in the Telegram Channel:- t.me/JEEnexus
@SakshamKR-zy1wi
3 ай бұрын
Thank you bhai ❤
@IITIAN_IAS_Motivation
2 ай бұрын
sir iska PDF nahin mil raha hai pls help team pls tg bhi check kiya content wala bhi
@novazx5193
7 күн бұрын
Sir pdf nhi hai telegram pe
@Sassy_657
3 ай бұрын
1:36:00 method to find equivalence relation 2:32:01 must revise 2:50:55 trick 2:54:57 revise 2:57:04 imp 2:58:45 definition question 3:02:51 checking true value
@zaramuhx
2 күн бұрын
doing the lords work
@Vedant-x2q
3 ай бұрын
Quality learning better than most of the other coachings
@Nitin_9998
2 ай бұрын
1:09:05 sir correct answer is option a only reflexive
@MohanaPriya-qn1rm
Ай бұрын
Yes, he's right
@Abhi-w9b
26 күн бұрын
But x/2 should be less than x so it is not reflexive as sir said in starting y>or equal to x
@StudyModeActived
3 ай бұрын
Sir , rather than making one shot , a series of lectures covering all topics in detail for a chapter will be useful..(just a humble request)
@akashs7524
3 ай бұрын
Yes , I agree...
@Palakpukku
3 ай бұрын
I also agree
@GaganDwivedi-os5td
3 ай бұрын
Koi n Bhai One shot isiliye best h kyuki one shot dekhle jee main ke 80-90 percentage to ho hi jate h Isliye pehle focus on jee main😊
@HITANSH_JEE2
3 ай бұрын
@@GaganDwivedi-os5td maths ke 80-90%? Air 100< vale ho kya? Kuch bhi ?? 😂
@GaganDwivedi-os5td
3 ай бұрын
@@HITANSH_JEE2 bhai main ke to itne bn hi jate h bas advance mein thodi problem ati h
@abouttech7728
3 ай бұрын
Sir Homework : Both reflexive and symmetric so sir ek matrix bana liya A*A kyunki reflexive hai to diagonal to aayega hi relation mai For symmetric(Considering with respect to upper triangle) : ham kisi bhi ek element in upper triangle ko leyenge to uske corresponding ek element lower triangle wala aajayega so ham kisi bhi upper triangle wale element ko le sakta hai ya nahi le sakta baki kaam ho jayega so 2 choices per element of upper or lower triangle . Total no. of element in matrix = n**2 no. of element in diagonal is n no. of element in each triangle equal as square matrix so no. of elements are (n**2-n)/2 So number of relations are 2 raised to power (nsquare - n)/2
@kaliaiit
3 ай бұрын
Bahuuut badhya shera.... Keep it up❤❤❤❤
@noobi539
3 ай бұрын
is it helpful for someone who doesn't know A of functions?
@jay_ff_1883
2 ай бұрын
Sir why you not covered even odd fn and periodic fn
@mathsioqm
Ай бұрын
UDA DIYA SIR NE
@ultimatefactsff1785
Ай бұрын
This is covered by sir in 11th class lecture
@gauranggupta4176
10 күн бұрын
Which one @@ultimatefactsff1785
@sagniksarkar8570
6 күн бұрын
@@ultimatefactsff1785 kisme? standard functions waali mein?
@Aiims_Kalyani11255
3 ай бұрын
1:25 you will find rajwant sir
@FTGUY10
2 ай бұрын
😂😅
@Sachingurjar20072
Ай бұрын
Yeah!!
@FocusonSolution780
28 күн бұрын
41:13
@AparnaBaudh
3 ай бұрын
Lots of love to you dearest sir from my core of pure heart ❤! THANK YOU
@TGplayz007
3 ай бұрын
Sir Please Take ITF chapter
@ei-kun2212
14 күн бұрын
the only teacher who reminds me how beautiful maths can be. planning to drop this subject due to extremely hard questions... but nah its amazing
@Paarth-g6q
3 ай бұрын
I was searching for this chapter today morning and sir uploaded it today itself thank you sir
@noobi539
3 ай бұрын
Is it helpful for someone who doesn't know A or function?
@vihaansrivastava4956
3 ай бұрын
@@noobi539 you should just know set theory for relations. nothing else is required
@fiteasy001
2 ай бұрын
Sir odd even and periodic function nhi padhaya
@aryanverma297
Ай бұрын
Thank you so much sir❤❤😊
@ajay_master_mind4002
3 ай бұрын
Sir iss baar lecture ki starting mein nature of chapter and weightage index kyu nhai hai
@KyoichiShido-ph7ez
3 ай бұрын
When will be the next lecture ???
@VaishnaviAgrawal-ji1vg
Ай бұрын
Very great lecture thanks bhai 🎉❤
@veeraraghavanpandurangan7148
21 күн бұрын
You can understand and appreciate it well If you study ncert by yourself And solved 75% the exercise
@adityakushwaha602
Ай бұрын
2:34 personal reference
@PrathmeshKulkarni-iu8jb
3 ай бұрын
Sir jee aap hi physics and chemistry padhao
@karnikatrivedi
3 ай бұрын
Sir is this sufficient can we solve pyqs and all kind of questions after this??
@arnavvhhhh
3 ай бұрын
yuh
@sarangg5348
3 ай бұрын
lol this is not board this is jee man
@JaskaranSingh-hg5bn
3 ай бұрын
Sir physics ke bhi detailed one shots chahiye 😢
@18football18
3 ай бұрын
Bhai coordinate kab karwaoge adv level?!🥹
@creativecraft15
3 ай бұрын
1 ghante se important and main cheej .......🙏🙏🙏🙏
@panchalgamer4178
2 ай бұрын
1:04:37 sir a=2,b=½,c=-½ {(2,½),(½,-½),(2,-½)}
@Rockyboy16-ol3ky
Ай бұрын
a=-2 b=0 and c=4 best way
@Ayush-r8t
10 күн бұрын
ODD EVEN PERIODIC?
@simranbhadani3052
3 ай бұрын
Thank you so much sir 😊😊
@THEEND-y1x
2 ай бұрын
Tum kahi dekha dekha lag raha hai
@AKSHAY-1290
26 күн бұрын
@@THEEND-y1xtera mother hain 😂😂😂
@suhaniverma6583
3 ай бұрын
Sir 11th plus 12th limits pe lecture bnaiye please sir ,aap bhot jyada acha padhate hai 🙏
@kynsign
3 ай бұрын
absolutely love your efforts sir that you do for us, just another humble request to you that, please do something about physics too...physics oneshot would be a blessing for us!!
@noobi539
3 ай бұрын
Is it helpful for someone who doesn't know A of functions
@kynsign
3 ай бұрын
@@noobi539 totally!
@ABHISHEKBYAHUT05
14 күн бұрын
1:24 par find elements related to 3 bilkul bhi samjh nhi aaya
@adityakushwaha602
Ай бұрын
3:10 concept building ques
@poonamtiwari-fx5xr
10 күн бұрын
Thanks sir, am dropper prayas batch students 😊
@SharvilJoshi-bc7nm
3 ай бұрын
love u bhai , here from class 11th
@hrithikroshan2565
3 ай бұрын
sir functional equation choot gaya hai
@Hitman-256
3 ай бұрын
Sir kya 11-12 pcm ka sara syllabus starting se detail me kraoge na plz 🙏🙏🙏 sir reply
@manangupta2509
3 ай бұрын
Only maths and chemistry
@Hitman-256
3 ай бұрын
@@manangupta2509 physics ni hogi?
@JaskaranSingh-hg5bn
3 ай бұрын
Pata nhi @@Hitman-256
@MohitSingh-ud2wi
2 ай бұрын
2:40:08
@Sheersh-j5e
3 ай бұрын
Sir Please provide class notes for revision and practice 😢
@KanwarWorld
3 ай бұрын
es lecture koo dekhne ke baad unacademy ka module solve hoo jaye gaa kya
@agnidiptasarkar3024
3 ай бұрын
1:34:35 Sir proved 3rd part
@shsbsvsb
2 ай бұрын
2:30:00
@SarthakGautam-eb3wf
3 ай бұрын
Sir, The third part proved👍👍👍🙏🙏
@yashsoni8714
2 ай бұрын
Thank you sir 🥹🙏🏻🙏🏻🥹
@KunalPatil91
3 ай бұрын
Mera bhai Mera bhai 🥺🥺🥹🥹💗💓❤️🩹❤️🩹❤️❤️❤️🫶🫶🫶🫶🫶🫶🫶🫶
@sanjaykumarsingh3388
3 ай бұрын
Sir upcoming class 12 th video kon se chapter ka hoga
@RakeshGupta-nj1pq
3 ай бұрын
Sir ye video meins level ko lekar chal sakte he. ,advance me ye chapter bhout lendi he😊
@RahulSharma-n3c
3 ай бұрын
Third part answer is =2⁶ [1,4],[1,3] and [1,1 ],[2,2] [3,3] [4,4] 😊 sir proved third part ❤
@Lovely-418
3 ай бұрын
Sir physics ka bhi krwa do one shorts😢
@ALLENITE343
3 ай бұрын
sir doubt plz plz reply i have exam tomorrow at 50.25 here in this relation there is ac already then why have you written ca .................. agar ac relation me he toh ca likh ne ki kya jarurat he sir plz reply sir iska answer toh 5 aana chahiyea fir sir plzzzzzzzzzzzzzzzzzz replyzzzzzzzzzzzzzzzzzzzzzzz
@gunmattac4621
3 ай бұрын
nahi mila reply , hahahahhhahahaah
@spacethug1795
2 ай бұрын
air 01 thanks bhai love you
@sarangg5348
3 ай бұрын
this is 12th relation and function only?not 11th included?
@Hemalatha-yu7ht
2 ай бұрын
Yes only 12th
@ndaandrr653
3 ай бұрын
Sir I'm preparing for the nda exam.
@Wperception
3 ай бұрын
I m in 11, can i watch this for portions of this chapter that are useful for 11 pov
@devvishwakarma9838
2 ай бұрын
just open relations for 11 th class bro??
@HritikSahoo-c2x
2 ай бұрын
Sir why you teach better than in app?
@allgamerharshit7261
3 ай бұрын
sir 41 . 43 vala dubaraa smjhnaaa
@arpit_pradhan9592
2 ай бұрын
very nice video
@KanwarWorld
3 ай бұрын
Thanku Bhai ❤
@adityakushwaha602
Ай бұрын
sir aapne graphical transformation to kra hi nhi
@aarushgupta1789
2 ай бұрын
proved
@Sanjarhussain5397
3 ай бұрын
Sir is it sufficient for board
@sarangg5348
3 ай бұрын
this is for jee for board they dont ask question like this board is so easy
@ManishPandey-oc2br
3 ай бұрын
Finally completed
@Education-35
3 ай бұрын
Total no. of reflexive and symmetric relaⁿ :- For reflexive = 1×1×1 For symmetric = 2×2×2•(1) hence, 2³ ● This is for [n = 3] *_Bhai_* sabhi teachers direct formula bata dete hai no. of relaⁿs ka but aapne too..... 😃😃😃 Iss tarike se too kabhi kisi ne padaya hee nahi 😶😶😶 JEE aspirant 2025 🔥🔥🔥
@JEEnexus
3 ай бұрын
Well done shera... Keep it up...❤️❤️
@cherryblossom8959
3 ай бұрын
Agreed 💯👍
@Education-35
3 ай бұрын
@@JEEnexus 😊😊😊
@ItxAbhay416
3 ай бұрын
Bhai physics kaha se krna h brother plz bta de
@Education-35
3 ай бұрын
@@ItxAbhay416 Sorry, But me competition nahi badana chahata
@Avengers-do9yf
3 ай бұрын
Does this lecture cover everything? like all concepts? plss can anyone verify? it'll be very helpful if anyone would answer
@agnidiptasarkar3024
3 ай бұрын
Look except odd and even functions it covers most of the part. So if you are learning Relation and Function you can surely watch this. This video also contains a few small tricks which will help you while solving questions of other chapters.
@Avengers-do9yf
3 ай бұрын
Thank u sooo much!! Also if it isn't any trouble, could u tell me where to learn the small topics like odd and even functions from? Thanks for the reply again!
@Maths_is_love3.14
2 ай бұрын
@@Avengers-do9yffunctional equation too didnt cover Number of functions And many more didnt cover here
@ArotoNamikaze
3 ай бұрын
Love you bhai ❤❤❤❤ so much
@JeeAdvance-c6h
2 ай бұрын
Proved third part
@Benzoic-IITian
3 ай бұрын
1:58:00
@SparkFF38
3 ай бұрын
jai sri ram
@SparkFF38
3 ай бұрын
ram ram ji
@aarushgupta1789
2 ай бұрын
2:26:00 sir isme C option bhi toh glt hai
@Garvit-LookatthisDuude
Ай бұрын
kaha bhai 2006/2008 aaega toh 1003/1004 ho toh gya Correct
@Garvit-LookatthisDuude
Ай бұрын
Incorrect poocha hai
@aarushgupta1789
Ай бұрын
@@Garvit-LookatthisDuude thnk u i got it in last but forgot to delete the comment
@sourishdutta0999
2 ай бұрын
third part proved
@perfectinparam
3 ай бұрын
🔥
@grewknowledge8750
3 ай бұрын
sir 11th first
@_Paras._editz
3 ай бұрын
Vote for limit ✅
@priaysnhu077
2 ай бұрын
bhai
@IITJEE-r8l
Ай бұрын
Jee ka title lagane se ye jee level Nehi ho jata. Isse acche lecture KZitem PE hai Ashish sir ka one shot Jake dekho
@user-om8fy2io9r
Ай бұрын
Sachi?
@Krixu000
9 күн бұрын
Nehi bhai ye complete toh nehi hai but jee aur boards ke hisab se thik hai Mu jhe lagta hai functions pe ek dedicated lecture bad mein ayega Ye un bacho ke kam mein bhi ayega Jo school exam ke liye padh rahe hein
@amzn__108
3 ай бұрын
love you sir
@syeddark2318
2 ай бұрын
😂
@bablurajak1441
3 ай бұрын
Sir board level ka ve kariye na plz❤
@yoongislipgloss7001
3 ай бұрын
channel ka naam jee nexus hai...
@paramtiwaripoint9694
3 ай бұрын
11 Wale dekh sakte hai ya rehne de
@gauranggupta4176
3 ай бұрын
Nhi 12 th ka hai
@aditi31245
3 ай бұрын
Dekhlo 12 me asani hogi
@vedagyamishra4650
3 ай бұрын
Rehne de
@vidyeshvaidya1669
3 ай бұрын
Rehen dekh 11th kahi kar pehle
@grewknowledge8750
3 ай бұрын
nope
@shivanisuraj6425
2 ай бұрын
3:08:41
@arjunsagar-s8n
3 ай бұрын
Sir Even/Odd Functions Nahi Padhaya Aur Periodic Bhi Nahi Padhaya
@ganeshgouda6507
12 күн бұрын
Ha bhai 😢
@target__iit
5 күн бұрын
functional equation, onto into function, range of function,counting of finction kuch nahi padhaya
@IITD-or6fw
2 ай бұрын
Bhai pdf upload NHI hui hai , pls karva dijiye.
@ajit6250
3 ай бұрын
Sir ITF ka next chapter laye pls Love you Bhai❣️❣️
@GamingWorld-ke3jj
3 ай бұрын
Sir Gaming World Me hi Hu😂 Mera naam Abhay hai😅 46:21 & 1:04:00 Thank You sir.
@RajvardhanShrivastav
3 ай бұрын
Name change Kar na bhai to
@GamingWorld-ke3jj
3 ай бұрын
Arey Nahi bhai, Name se kya ho jayega
@GamingWorld-ke3jj
3 ай бұрын
@@RajvardhanShrivastavAbhi 12th me ho kya? Kaise chal rahi h prep?
@RajvardhanShrivastav
3 ай бұрын
@@GamingWorld-ke3jj ha bhai Chal rahi he prep
@kaliaiit
3 ай бұрын
Theek hai shera....❤❤
@AurochandanRana
Ай бұрын
❤
@Kushmakadia
11 күн бұрын
1:35:57 proved
@Ueuehehsjystwywhsyywyw2
3 ай бұрын
Thank You Jii 💕
@Avengers-do9yf
3 ай бұрын
sir what about even odd fns and periodic fns? does anyone know abt these topics?
@ShivamGupta-oy2rc
2 ай бұрын
Very important
@freedelahoya6531
3 ай бұрын
sir why u dont solve jee advanced questions
@aniruddha287
3 ай бұрын
Bro this is a one shot, where he explains all concepts and does high level jee mains questions to strengthen the concept and its application, and as for advanced questions, after watching this lecture, if you practice any standard book( like cengage for instance) and do jee mains pyqs, then you'll be easily able to solve advanced pyqs too. Also, sir has conducted some solving sessions, where he selects about 20 important advanced mcqs and solves them. U can find those in the playlist section of the channel.
@OrganicChemistry-kt1qr
3 ай бұрын
@@aniruddha287 bro I'm Only Focusing On Jee Mains Can For Maths Sir One shots Are Enough?
@aniruddha287
3 ай бұрын
@@OrganicChemistry-kt1qr yes bro, this one shot is more than enough for mains, you just have to practice properly after watching this session
@anuragmondal
2 күн бұрын
The only JEE teacher who makes complex maths topics simple and beautiful!
@target__iit
3 күн бұрын
*Τimestamps* 4:12 *Topics* 4:48 Critical Topics 5:44 *RELATIONS* 5:54 Cartesian Product of two sets 7:43 Definition of Relation 9:12 Remark (Relation on A) 10:03 Description of Relations 14:57 Domain, Codomain & Range 18:32 *Total Number of Relations* 20:23 *Inverse of Relation* 23:43 *Types of Relations* 24:38 1️⃣ Empty Relation 24:57 2️⃣ Universal Relation 25:09 3️⃣ Identity Relation 25:55 4️⃣ Reflexive Relation 29:25 5️⃣ Symmetric Relation 31:10 6️⃣ Τransitive Relation 30:28 NOTE 47:50 _QUESTION: Minimum number of elements that need to be added_ 1:14:59 7️⃣ Equivalence Relation 1:15:13 _Checking Type of Relation Theoretically_ 1:24:03 👉 Equivalence Class 1:26:04 *Number of Relations* 1:36:07 *Number of Equivalence Relation* 1:38:04 8️⃣ Antisymmetric Relation
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