During conventional swing you say the turbulent layer sticks to the ball longer, then why does the turbulent layer separate earlier during reverse swing?
@inderjeetsingh7641
4 жыл бұрын
I think because the side on which turbulent flow occurs is rough and air separates quicker by striking roughness
@-CricketLover
2 жыл бұрын
@@inderjeetsingh7641 because turbulent has no limit no can predict turbulent behaviour just can observe through experiment,Swing occurs at medium pace but in case of reverse bowling at high pace ,On seam angled side more turbulent and shiny side (relatively rough than new ball) also has Turbulent but on seam angled side early separation due to more turbulent twisted air due to high pace . Difference in time separation cause movement,but pace factor cause difference
@semmarikeda8036
5 жыл бұрын
super sir
@osamashami
2 жыл бұрын
If the one side is not shinny. After 30 overs boths side are not shinny for sure. Theb ???
@usmankhurram5057
6 жыл бұрын
Good
@shrijeetdeshmukh8543
3 жыл бұрын
Explanation looks logically incorrect.. Shiney side generates laminar flow which separates earlier than rough side induced turbulent flow
@UncoverTheTruth
3 жыл бұрын
Thank you for your comment. Reverse swing happens when the ball is old. So when you say the 'shiny side', it means to say that it is relatively shinier than the rough side. The rough side is rougher than in a new ball. As it's too rough, now the turbulent flow can't stick to the surface longer. So it separates earlier.
@tz3925
2 жыл бұрын
he said for reverse swing. in conventional swing your logic is right. but when the ball is around 40 overs old the roughness separates quicker
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