Correct me if I’m wrong, but shouldn’t integrating -n^2 * 2(x - c) be -n^2(x^2 - 2cx)?
@jamesjamatia7565
2 жыл бұрын
How does integrating -n^2 2(x-c)= -n^2 (x-c)^2? Doesn't it suppose to be (x^2 -2cx). Can anyone please reply?
@chaiburashka
2 жыл бұрын
those are essentially equivalent. (x-c)^2 = x^2 - 2cx + c^2 and since c is a constant, c^2 is a constant and can be discarded when taking a definite integral. that's why taking the derivative of both (x-c)^2 and (x^2 - 2cx) with respect to x will return the same expression, 2(x-c) = (2x-2c).
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