Not everybody knows secant line theorem. So if you can show your less experienced viewers how to solve these types of problems using widely-known method then you’re catering to a variety of audience from beginners to the more sophisticated. You’re doing a fine job!
@soli9mana-soli4953
11 ай бұрын
Solving with two secant theorem is easy and fast! You have only to write and solve this: (9+8) : (15+r) = (15-r) : 9
@PS-mh8ts
Жыл бұрын
If PT is a tangent to the circle (T being the point of tangency with the circle), it can be shown that PT²=PQ*PR (This is known as secant-tangent theorem, more details can be found at: en.wikipedia.org/wiki/Tangent%E2%80%93secant_theorem ) You can use this result to find the radius. i.e., PT²=PQ*PR=9*(9+8)=9*17=153 Now, PT²+TS²=PS² i.e., 153+TS²=15² i.e., TS²=r²=15²-153=225-153=72 Therefore r=√72=6√2
@GrayYeonMath
Жыл бұрын
You are awesome! Nice.
@hadigayar6786
Жыл бұрын
other method pq x pr=(15-r)(15+r) 9 x 17=225-r^2 r^2=72 r=6root 3 thank u sir that was amazing video
@GrayYeonMath
Жыл бұрын
You're welcome. Thank you also for watching.
@crkr1955
Жыл бұрын
9x17=(15+r)×(15-r) Solve for r
@rampathak8204
Жыл бұрын
Alternatively we can draw a tangent from from point P and by using secant tangent thm and Pythagoras thm radius can be found more easily.
@rey-dq3nx
Жыл бұрын
By secant line theorem 9(17)=(15-r)(15+r) 153=225-r^2 r^2=225-153 r^2=72 r=6root2
@liliyakaloyanova377
Жыл бұрын
RS= r r^2= 4^2 +x^2= 16+56=72 r= 6.V2
@crkr1955
Жыл бұрын
It can be solved in fewer steps
@crkr1955
Жыл бұрын
Use secant secant theorem
@tommypaterson
Жыл бұрын
If there is a hard way of solving a problem you will find it
Пікірлер: 19