Glad to hear that! Thank you for your feedback! Cheers! You are awesome Govinda😀 Love and prayers from the USA!
@zmz1405
2 жыл бұрын
@@HackedPC I don't think calculator is allowed for this question
@bombaytovegas802
2 жыл бұрын
@@PreMath sir what is wrong in these 👉👉 5^a×7^b=5^4×7^2 a=4 b=2
@GalBrow
2 жыл бұрын
This equation has a problem because : 1225= 7^y =5^x and this is equal to 35^2 so (7x5)^2 . Then √(7^y) x √(5^x)= 7^2x5^2 so the only solution is y=4 and x=4 or, x≠y because 7^y=5^x . However, with my method we of course fall back to xy/x+y=0.5 I got stuck on it for an hour, please tell me if there is another solution than x=4=y.
@GalBrow
2 жыл бұрын
@@PreMath This equation has a problem because : 1225= 7^y =5^x and this is equal to 35^2 so (7x5)^2 . Then √(7^y) x √(5^x)= 7^2x5^2 so the only solution is y=4 and x=4 or, x≠y because 7^y=5^x . However, with my method we of course fall back to xy/x+y=0.5 I got stuck on it for an hour, please tell me if there is another solution than x=4=y.
@regisvaganet2463
2 жыл бұрын
hi. Thanks for your problems, explanations and solutions. I solved this one using logarithms. x =ln (1225) / ln (5) ; y = ln (1225) / ln(7) . then i had to use 7*5 = 35 and 35² = 1225. my ending was xy / (x+y) = ln(1225)/ln 35) = 2 ln(35) / ln (35) = 2.
@cavity131
2 жыл бұрын
Same took no time with ln
@mario7501
2 жыл бұрын
Same here. Took me about 30 seconds to solve.
@arekkrolak6320
2 жыл бұрын
you can solve it even faster if you do not use common base as: xy/(x+y) = log5(1225)*log7(1225)/(log5(1225)+log7(1225)) :)
@dizzyd7315
2 жыл бұрын
@@mario7501 good for you boy
@PeterLE2
2 жыл бұрын
@@arekkrolak6320 Thats the way I did it too. The hardest thing was to find (5×7)²=1225 but you can guess it because this kind of question thend to fall apart and becone something simple
@iZAPMath
2 жыл бұрын
You are doing an incredible service to all students around the world! Diligent. Patient. Caring.
@PreMath
2 жыл бұрын
So nice of you. Thank you for your feedback! Cheers! You are awesome Dr. Kelly 😀
@user-tt7wu2zh7h
2 жыл бұрын
I have found another way to solve this. 1225=7^2•5^2 So knowing 5^x=7^y=1225, dividing first by 5^2 gives us 5^(x-2)=7^2 Put every number in this sequence to the y’th power and you get 5^y(x-2)=7^2y Now replace 7^y by 5^x as it is equal. We now are left with the equation 5^(yx-2y)=5^2x . Since the base is the same we have a^c=a^d and we know that c=d or in this case xy-2y=2x Now set the 2y to the other side and we have xy=2x+2y or xy=2(x+y) Thus we know that x+y is half xy so xy/x+y= 2 Keep up making these videos , greetings from Greece 🇬🇷
@user-zx8dr1fo7p
2 жыл бұрын
Спосіб у відео кращий.
@PreMath
2 жыл бұрын
Excellent! There are many ways to solve this problem. Thank you for your feedback! Cheers! You are awesome 😀 Love and prayers from the USA!
@user-tt7wu2zh7h
2 жыл бұрын
@@user-zx8dr1fo7p I know but this one is easier
@aishkatara
2 жыл бұрын
You made it very complicated
@aishkatara
2 жыл бұрын
Now look at this
@divyanshuraghav6921
2 жыл бұрын
Sir, I try to solve this question about of 30 minutes but when i see your solution. I understand perfectly. Thank you Sir😁👍🙏
@PreMath
2 жыл бұрын
Welcome 👍 Excellent! Thank you for your feedback! Cheers! You are awesome Raghav 😀
@Jackrobert28
2 жыл бұрын
@@PreMath please state if calculators are allowed
@PreMath
2 жыл бұрын
@@Jackrobert28 Hi Jack, in Olympiad questions, normally calculators are not permitted! Thanks for asking. Keep it up 😀
@dafureveerbhadra2772
2 жыл бұрын
Its 1 minute question
@rahul.g566
2 жыл бұрын
Sir,, actually in your channel one of the first things I like is comments,, bec different people expressing there different approaches and diff methods,,this makes me interesting ☺☺
@Gargaroolala
2 жыл бұрын
I used logarithm! I first realized that the RECIPROCAL of xy/x+y is x+y/xy = 1/x + 1/y. x = lg 1225/lg 5. y = lg 1225/lg 7. 1/x + 1/y = lg 5/lg 1225 + lg 7/lg 1225 = lg 35/lg 1225. (Since 1225 = 35 x 35), 1/x + 1/y = lg 35/(lg 35^2) = lg 35 / (2 lg 35) = 1/2. Taking reciprocal of 1/2 to obtain answer to original equation = 2.
@PreMath
2 жыл бұрын
Excellent! There are many ways to solve this problem. Thank you for your feedback! Cheers! You are awesome Garrick 😀
@GiuseppeAriano
2 жыл бұрын
I took this way: (5^x) ^y=1225^y; (7^y)^x=1225^x, so we have 5^(xy)*7^(xy)=1225^(x+y) and finally 35^(xy)=35^[2*(x+y)]. Consequently, we obtain the result in easy way. Compliments for your work.
@pravaalreddy2050
2 жыл бұрын
Woah
@elias69420
2 жыл бұрын
We used the same method independently from each other. Amazing
@GiuseppeAriano
2 жыл бұрын
@@elias69420 Cool!
@242math
2 жыл бұрын
your solution is easy to follow and understand, thanks for sharing this Olympiad question
@mathsdone2265
2 жыл бұрын
Brilliantly explained. Awesome presentation . 👍👍
@abdulalam3310
2 жыл бұрын
Ek ghante kosis ki magar nhi bana...lekin solution dekh ke crystal clear samajh me aaya🤗🤗 ...aur maine subscribe bhi kr diya aur amazing videos dekhne k liye
@brunococchietto7496
2 жыл бұрын
Very neat solution,I made a mess of it,but your mathematic skill is very good, especially saying 35^2=1225,from this the solution is simpler.
@pratimadevi2214
2 жыл бұрын
Your videos are very very useful! It's a great day when you upload!
@PreMath
2 жыл бұрын
Glad to hear that! Thank you for your feedback! Cheers! You are awesome Pratima 😀 Love and prayers from the USA!
@hichamitani6433
2 жыл бұрын
Great method prof Need to know if it works by logarithms
@deepakbisht4685
2 жыл бұрын
Awesome👍👍👍
@tombufford8659
2 жыл бұрын
Nice way to learn the power rule
@ellyjauharaha8190
2 жыл бұрын
Thank you so much, Sir
@smartube4828
2 жыл бұрын
Nice one, thanks!
@SumanSingh-wj9en
2 жыл бұрын
i have just multiplied the equation 5^x × 7^y = 1225×1225 5^x × 7^y = 35 ^4 5^x × 7^y = 5^4 ×7^4 x =4 y=4 xy/x+y 4×4/4+4=16/8 =2
@SeBros
2 жыл бұрын
A Very nice math video!!
@aybenizaliyeva3118
2 жыл бұрын
Thanks very much.
@imnitinnagar
2 жыл бұрын
Behtreen koshan
@Yash1729dhomdhara
2 жыл бұрын
35=1225^{x+y/xy} can be written by x+y/xy = log base-1225 X 35 which gives 1225^x+y/xy=35 or 35^2(x+y/xy)= 35 such x+y/xy became 1/2 and it's reciprocal became 2
@nicogehren6566
2 жыл бұрын
nice question sir thank u
@davidfromstow
2 жыл бұрын
another great question and solution - thank you
@PreMath
2 жыл бұрын
Very welcome David Glad to hear that! Thank you for your feedback! Cheers! You are awesome 😀
@mahatmapodge
2 жыл бұрын
Can you do a few more log questions please?
@makehimobsessedwithyou6412
2 жыл бұрын
Can we use log
@MukeshGakhar
2 жыл бұрын
Keep it up 👌
@cemuncu8379
2 жыл бұрын
Thanks for solution. You can also solve it by using logarithm.
@KAvi_YA666
2 жыл бұрын
Thanks for video. Good luck!!!!!!! Nice problem. From-sri Lanka.
@PreMath
2 жыл бұрын
Thanks and welcome So nice of you. You are awesome AKD 😀 Love and prayers from the USA!
@gamer122333444455555
2 жыл бұрын
Is finding the possible values of x and y considered wrong since the answer to the question stops the math process?
@PS-eg2bn
2 жыл бұрын
Awesome
@crustyoldfart
2 жыл бұрын
I think we can move to the final answer by noting that 1/x + 1/y is the same as ( x + y ) / ( x*y ) and that 1225 = 5^2 * 7^2 and the result follows quickly.
@diptiagrawal4462
2 жыл бұрын
Sir i was able to solve it by other method it is also easy You just need to equate everything to k then just write a equation in k And in the end by comparing powers you will get the same answer
@meghdeep584
2 жыл бұрын
Super problem. It's given in K.C.Nag in the chapter laws of indicies.
@dhrubajyotidaityari9240
2 жыл бұрын
x log5=2log 35, x=2log35/log5, & y=2log35/log7. The given expression 1/{1/x +1/y}=log35 ÷ 2log35=2
@PreMath
2 жыл бұрын
Excellent! There are many ways to solve this problem. Thank you for your feedback! Cheers! You are awesome 😀
@LuizFernando23250
2 жыл бұрын
Yesssssssssss. I got it, very nice. I really like this question with a very simple answer Edit: I think that I solve in a more easy way. I used logs, so x = log_5 (1225) and y = log_7 (1225). 1225 = 5² × 7², so I use this to brake the logs for x and y using the log properties to get x = 2 + 2 log_5 (7) and y = 2 + 2 log_7 (5). After this, just put the x and y in the xy/(x+y), do the distribution for xy and you can simplify nicely at the end.
@PeterLE2
2 жыл бұрын
This is way easier. BUT This is for math olympics. There you are only allowed to use what you already had in school. If you use anything else you have to proof it. So I guess it was for 8 or 9 graders. Otherwise it would be way to easy for math olympics
@LuizFernando23250
2 жыл бұрын
@@PeterLE2 Hmm, I understand now. I simply thought in a easy way to do it, I don't thought in this type of limitation.
@PeterLE2
2 жыл бұрын
@@LuizFernando23250 Neither did I when I participated many many years ago 😃
@knowledgecorner9697
2 жыл бұрын
I did it in same way under 3_4 minutes
@wanwibu9291
2 жыл бұрын
@@PeterLE2 it was for 7 graders in my country
@manishkansal8260
2 жыл бұрын
It can be solve simply by visualising that xy/x+y =1/(1/x+ 1/y). x= log 1225 base 7 and y = 1225 base 5. 1/x = log 7 base 1225 and 1/y= log 5 base 1225. Adding these two will yield= log 35 base 1125 = 1/2. Inversing it will give 2 as answer
@porter3277
2 жыл бұрын
Normally, l got the value of x, y by the "ln" .thus put their in the equation.. Is That true?
@holery9215
2 жыл бұрын
i use logarithm for this but i simplify that (log_5(1225)log_7(1225))/(log_5(1225)log_7(1225)) Since y = xlog_7(5) Then substitute to equation (log_5(1225)^2 log_7(5))/(log_5(1225)+log_5(1225)log_7(5)) Factor the denominator first (log_5(1225)^2 log_7(5))/log_5(1225)(1+log_7(5)) (log_5(1225)log_7(5))/(1+log_7(5)) log_5(1225) × log_7(5)/log_7(35) log_5(1225) × log_35(5) 2log_5(35) × log_35(5) 2 × log_35(35)/log_35(5) × log_35(5) 2 × 1 = 2 More harder if you use the logarithm to get the approximate value 😂
@ahteshamalikhan3656
2 жыл бұрын
very good, sir
@wernerpohl1142
2 жыл бұрын
Hi. Thanx for this nice example to this general statement: Let a and b be positive real numbers, let n be a natural number and and let x be unequal -y. Then it always follows from the equation a^x = b^y = (a*b)^n that x*y / (x+y) = n. Proof: Same solution that PreMath showed us with a=5, b=7, n=2.
@Gilmoy
2 жыл бұрын
Yes, it generalizes. In fact, we have 5^x = 5²7², so x ln 5 = 2 ln 5 + 2 ln 7, and x = 2 (1 + ln 7/ln 5). To generalize, let r = ln 7/ln 5. Then x = 2(1 + r), and by symmetry, y = 2(1 + 1/r). Now, the pair X = (1 + r) and Y = (1 + 1/r) have the curious property that XY = X+Y, and thus XY/(X+Y) = 1, for any r ≠ 0, and this is independent of x, y, logs, exponents, and 1225. Hence, this could be worth memorizing for any prospective taker-of-future-Olympiads. Generalizing beyond this specific instance, if we had x = kX, y = kY for any k ≠ 0, then xy/(x+y) = k²XY/k(X+Y) = k. Finally, for this problem, we have k = 2.
@keithmasumoto9698
2 жыл бұрын
This was a fun one.
@pyarebatain9659
2 жыл бұрын
very well explained Thanks sir
@PreMath
2 жыл бұрын
Most welcome So nice of you. Thank you for your feedback! Cheers! You are awesome 😀
@robertbourke7935
Жыл бұрын
Excellent exercise
@PreMath
Жыл бұрын
Glad you think so!
@bhojpurishort9805
2 жыл бұрын
Very imp. Qus for ssc cgl 2021 ❣️😁😁😁🙏✌️
@nirupamasingh2948
2 жыл бұрын
V nice
@jaggisaram4914
2 жыл бұрын
Super problem , Sir.I did it by using logarithms and got the answer as 2.
@PreMath
2 жыл бұрын
Excellent! There are many ways to solve this problem. Thank you for your feedback! Cheers! You are awesome Jaggi😀
@MoRkaha
2 жыл бұрын
I would use logarithms too. The solution presented in the video requires that we see ahead that 1225 is the square of 35 and that we could manipulate the given data to get a base of 35 on the other side of the equation. Using logarithms requires not intuition or 'seeing ahead.'
@Skank_and_Gutterboy
2 жыл бұрын
Me too. Taking the logarithm route, the expression simplified down to log(1225)/(log(5)+log(7)). Punching that into a scientific calculator, it equals 2. It's a good problem, not too difficult but it takes you back to fundamentals.
@aniketjha9167
2 жыл бұрын
Let 5^x=7^y=1225 be equal to k K=5^x, 5=k^1/x, 7=k^1/y We can see that 1225=7²•5², by substituting the valus of 7 and 5 we get that 7²•5²=k^2/y•k^2/x and this is equal to 5^x or 7^y which is equal to k so we get:- K=K^2/y•K^2/x=K^2(x+y)/xy => k=k^2(x+y)/xy, hence 1/2=x+y/xy, so xy/x+y=2... Please pin this easy method🙏🙏
@social6332
2 жыл бұрын
its very geniutic!
@kmadhu2k026
2 жыл бұрын
Can we find x and y seperatly.....?
@luisalfredonarvaeznarvaez5125
2 жыл бұрын
Más claro y explicado, no se puede El idioma no me impide comprender el desarrollo del ejercicio profesor Gracias por aportar mas información a mi cerebro
@PreMath
2 жыл бұрын
¡Me alegra escuchar eso! ¡Gracias por tus comentarios! ¡Salud! Eres increíble Luis 😀 ¡Amor y oraciones desde EE. UU.!
@johnbrennan3372
2 жыл бұрын
Estoy de acuerdo contigo.
@MdFahim-of7hc
2 жыл бұрын
Nice video
@jenik6210
2 жыл бұрын
Thanks
@uchechukwuugo3526
2 жыл бұрын
Why did you take the power of 5x and 1225 as 1/x? I'm confused.
@paddle_shift
2 жыл бұрын
So what power of 5 equals to 1225? Or what power of 7 equals 1225?
@theadvancemathshub
2 жыл бұрын
Nice , and easy problem
@PreMath
2 жыл бұрын
Thanks for liking Excellent! Glad to hear that! You are awesome 😀
@kafilahmaand4323
2 жыл бұрын
So nice 🌹🌹🇮🇳😃
@mahalakshmiganapathy6455
2 жыл бұрын
Nice explanation, 🙂
@PreMath
2 жыл бұрын
Excellent! Thank you for your feedback! Cheers! You are awesome Mahalakshmi😀
@devondevon3416
2 жыл бұрын
Answer=2 I did it differently 1225= 35^2 5^x =35^2 (5^x)^1/x = (35^2)^1/x raised both to the power of 1/x 5 = 35^2/x 7^y= 35^2 (7^y)^1/y) =(35^2)^1/y raised both to the power of 1/y 7=35^2 5 x7 =(35^2/x)(35^2/y) =35^2/x+2/y multiply both equation and m^n x m^q= m^n+q 35^1 = 35^2/x +2/y 1 = 2/x +2/y equate the exponent 1 = 2(1/x +1/y) factor out 2 on the right side of the equation 1/2 = 1/x +1/y) divide both sides by 2 1/2 = (y +x)/xy add the right side of the equation xy =( x+y)2 xy/x+y =2 Answer if (n+m)/nm= 1/p then nm/(n+m)= p
@swatisingh6098
2 жыл бұрын
5^x =1225 -(i) and 7^y =1225(ii) multiply (i) and (ii) 5^X .7^y =1225^2 5^X .7^Y = 35^4 5^x .7^y = 5^4 .7^4 x=4 and y=4 xy/x+y =4.4/4+4 = 16/8 =2
@lasyasallinone6647
2 жыл бұрын
The best explain 👍👍
@davisnganga6266
2 жыл бұрын
Wonderful
@PreMath
2 жыл бұрын
Glad to hear that! Thank you for your feedback! Cheers! You are awesome Davis 😀
@pranavamali05
2 жыл бұрын
Thnx a lot
@PreMath
2 жыл бұрын
Welcome Pranav Thank you for your feedback! Cheers! You are awesome 😀
@susennath6035
2 жыл бұрын
Excellent
@PreMath
2 жыл бұрын
Thank you for your feedback! Cheers! You are awesome Susen 😀
@vinamvinam3386
2 жыл бұрын
sử dụng logarit và casio cầm tay cũng ra nhé
@Cgrmedia.
2 жыл бұрын
Nice
@sachinmaheswar3028
2 жыл бұрын
Since I felt 1225 lies between 5^5 and 5^4, I considered x as 4.5 and similarly for y as 3.5 approximately. Subs x as 4.5 n y as 3.5, I got the final answer as 2. Something like (9/2*7/2) /(9/2+7/2). Solved within 2 mins. Is it fine?
@mathe.dominio4765
2 жыл бұрын
💙🙏
@nenetstree914
2 жыл бұрын
Great explanation!! It can also use ln to solve.
@PreMath
2 жыл бұрын
Yes, definitely! Excellent! Glad to hear that! Thank you for your feedback! Cheers! You are awesome 😀
@nenetstree914
2 жыл бұрын
@@PreMath I think the form is 5^x=7^y=5^n*7^n, and the answer will be n. It's funny.
@tijanamaksimovic394
2 жыл бұрын
Hi. There is an easier way. 1225 is the 35². And 35 is 7*5. 5^x*7^y=1225^2. So basically you get that both x and y are equal to 4. Then xy/x+y=16/8=2
@learnerhimanshu5889
2 жыл бұрын
Same method i have applied
@sawyerw5715
2 жыл бұрын
I started with an invert. If z=?answer, then 1/z=1/x + 1/y= log 5/log 1225 +log7/log1225=(log5+log7)/log1225= log35/(2*log35)=1/2=>z=2
@rangaswamyks8287
2 жыл бұрын
Super sir I like you
@just_study_n_focus
2 жыл бұрын
that was cool 😎
@piknik2337
2 жыл бұрын
just use lg on both sides for each case
@RealGeorg3
2 жыл бұрын
I am a simple man. I was able to solve with logs. One day I will be clever like you.
@rumanmushtaq898
2 жыл бұрын
we can also solve it by using 'log' method
@jorgemarioochoabarrera8375
2 жыл бұрын
I made it different: 1225 =(7)²(5)². Then 5^x=(7)²(5)²=>5^x-2=7²=>x-2=(log5(7))2=>x=2(log7/log5+1). Same logic for Y. After calculate X and Y and change them in xy/(x+y), the answer is 2. Sorry if this is bad written, I speak spanish.
@w.s6124
2 жыл бұрын
I mean its very easy to understand once you know how to solve but i would never be able to do this. Its like he does some random algebra and then finds a solution
@mathsin60seconds
2 жыл бұрын
"Mathematics is greatest magic of all times" 😍🔥🔥🔥😘🔥🔥😘🔥🔥🔥😍😍
@diablo3165
2 жыл бұрын
I solved it like this first I rewrite 1225 as 5^2×7^2 then I multiplied 5 ^x and 7^x which gets equal to 5^4×7^4 then by comparing x, y = 4 then put values in question and we will get our result
@amajadali187
2 жыл бұрын
I solve it from different approach in almost 2min.😊
@ManojSingh-og8tx
2 жыл бұрын
cant we take log 🤔
@VCLegos
2 жыл бұрын
My guess is 2 Edit: yay I was right! My method was to solve for x and y graphically then plug in those values to the xy/x+y equation to get my answer.
@rinkupandit
2 жыл бұрын
Since I didn't find the value of x and y individual , I couldn't understand how 5x =7y are = 1225
@arnabdas4740
2 жыл бұрын
Sir u can do it in another way... Here it is given that 5^x=7^y=1225... First we check that 1225=5^2*7^2... So we can write in this way:- 5^x*7^y= 1225*1225. i.e. 5^x*7^y= 5^4*7^4. i.e x=4, y=4 ( comparing the powers of both 5&7). Then we can write xy/(x+y)= 4*4/(4+4)= 2
@BINYAMINWITHMATHEMATICS
2 жыл бұрын
nice sir
@PreMath
2 жыл бұрын
Thanks and welcome You are awesome Binyamin Keep rocking😀
@thegeniusyuva5662
2 жыл бұрын
By using logarithm , it can be solved easily! Answer is 2! Commenting before watching the video! I don't know what method is used in this video to solve this question.
@panvik777
2 жыл бұрын
I did by prime factorizing 1225=5×5×7×7
@chandankumargupta8174
2 жыл бұрын
I study in graduation and I want to appear the examination of math olympiad in India ,but I have no idea of olympiad examination ,please suggest me
@chandankumargupta8174
2 жыл бұрын
Please anyone or premath jii
@PreMath
2 жыл бұрын
Dear Chandan, I don't know of any good book. However, if I were you I'd watch all the premath videos! That would give you a nice practice. Thanks for asking. I wish you all the best. You are awesome 😀 Love and prayers from the USA!
@shahbazkhan6868
2 жыл бұрын
An easier way of doing this is Since 5 raise to x and 7 raise to y both equals 1225 Therefore multiply 5 raise to x to 7 raise to y and in RHS it will be square of 1225 ( which can be split in powers of 5 and 7 ie 5 to the 4 times 7 to the four ) , Therefore x =y = 4 , Now xy/x+y = 2 😉
@petereziagor4604
2 жыл бұрын
😹😹😹 nice approach Smart
@user-fv3lz4gh1y
2 жыл бұрын
3:11hey plz answer quickly plz I got an exam tomorrow. Why can you multiply5 and7 ,1225 1/x and 1225 1/y
@topian789
2 жыл бұрын
The solution is indeed excellent but how would I know by heart that 35^2=1225 🤔
@durgaprasad5427
2 жыл бұрын
Applying logarithmic gets problem more easy i.e, loga^b. = bloga
@marcosreal11
2 жыл бұрын
I don't understand the given information. How can 5x5x5x5x... be equal to 7x7x7x7x...? (Here the x is a multiplication sign.) How can 5's be equal to 7's?
@guyhoghton399
2 жыл бұрын
Here is a graphical way to solve it. Use a graph generator to plot the curve y = 1225⁽¹÷ˣ⁾. Copy it into a graphics editor like MS Paint. Draw the horizontal abscissa line from 7 on the y axis to the curve in the positive quadrant (x>0, y>0). Do the same from 5 on the y axis to meet the curve. You now have a "quadrilateral" formed by the y axis, the two abscissa lines and a portion of the curve. Draw the diagonals of the "quadrilateral". The 'x' value of the intersection point of the two diagonals is ab/(a + b), where 5ᵃ = 7ᵇ = 1225. Read off the solution as 2.
@PreMath
2 жыл бұрын
Excellent! There are many ways to solve this problem. Thank you for your feedback! Cheers! You are awesome Guy😀
@gud2you-atul508
2 жыл бұрын
Sir where you find out like this question
@PreMath
2 жыл бұрын
You can find most of them at premath channel. Thanks for asking. You are awesome Atul😀
@gud2you-atul508
2 жыл бұрын
Thanku sir but these questions very interesting with minded
@Chakravarti47
2 жыл бұрын
Sir what is x,y tell me please i am unable to understand 😭🙏
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