Whenever I solve a rational equation, when using the zero product property, if a factor matches with at least one of the denominators of the original rational equation, I underline it to show that this factor can be ignored because it would have a value that is not permissible in the original rational equation. For example if (x + 7) is in one of the denominator at least and is in the equation (x + 7)(x - 8) = 0, I would underline the (x + 7) and ignore it because it would cause an extraneous solution to the original rational equation. Hope this explains how I solve rational equations.
@Greenemath
5 ай бұрын
Some books will show it that way as well by putting the domain out first. {x | x ≠ -7, 8}
@ivmm3340
4 жыл бұрын
Thanks😊👍
@Greenemath
4 жыл бұрын
You are welcome! :)
@adelinamarasigan2147
3 жыл бұрын
Thank u so much. God bless!
@Greenemath
3 жыл бұрын
You are so welcome! Good luck with your studies :)
@reydichos8560
4 жыл бұрын
in the first example. where do you get the "add 10" and the "-2" pls comment hehe
@Greenemath
4 жыл бұрын
What's the time marker?
@reydichos8560
4 жыл бұрын
3:49
@Greenemath
4 жыл бұрын
@@reydichos8560 In order to solve the equation for x, you need x by itself on one side. 2x - 10 = x + 4, so to get rid of the 10, we add 10 to both sides. 2x - 10 + 10 = x + 4 + 10 The -10 + 10 becomes 0, so you just have 2x on the left. 2x = x + 14 So from there, you can subtract x away from each side: 2x - x = x - x + 14 x = 14, which is the solution; Not sure where you saw a -2, need a time stamp on that one? If you are struggling with theses steps, might I suggest you start at the beginning of the course? My website is completely free: GreeneMath.com
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