i wish he was my teacher,to be honest i hate math i am very weak but i understand from him but i dont understand from my sir and he makes math look fun
@saimamuqeet4242
7 ай бұрын
Same for my teacher. 😂😂 I seriously need him ❤❤❤
@matylinth3qu33n6
6 жыл бұрын
Where has this been all my life 😂
@ifecojahs8151
3 жыл бұрын
i now feel so stupid, the solution was very obvious. OMG
@iceye1333
3 жыл бұрын
This guy saved my education.
@creativedevil4222
Жыл бұрын
same bro
@Nchongwei1singapore
Ай бұрын
perfect teacher..
@ellapurdon3136
3 жыл бұрын
thanks king my hsc exam is tomorrow
@trinityw3964
3 жыл бұрын
Yo what? I’m doing this in year 9
@danielzhao296
2 жыл бұрын
Bruh I'm doing it in year 4 .__.
@joshuasylvester8754
3 жыл бұрын
Reiner hehehe
@24kprncess23
3 жыл бұрын
Broo if anyone were to cough that much in 2020 ppl would be like:😷🏃🏾♀️💨🧼🏃🏾♀️💨🤸🏾♀️🤸🏾♀️🪑
@truly5858
4 жыл бұрын
Beauty, elegance, PERFECTION
@Rana-zh7yx
4 жыл бұрын
I don't understand the line 7x + 80 - 16x=53, where did he get the 80 and the 16x from? I got so confused after that.
@briannapreston1825
4 жыл бұрын
He expanded the brackets by multiplying 8x10=80 and 8x2=16
@itsjohn6939
4 жыл бұрын
he expanded the bracket, so essentially he just multiplied 8 x 10=80 and 8 x 2 = 16
@midwestrailroadproductions8116
6 жыл бұрын
There are also systems of equations with 3 variables, Mr. Woo. You get 3 equations, and you can solve by elimination by choosing 2 of either equations. It doesn't matter which one.
@hiiamunkown4129
3 жыл бұрын
i wish it had more teacher like him
@harshithgowni1528
5 жыл бұрын
My teacher told me that we have to substitute x in the second equation after finding the value of x.
@envision136
5 жыл бұрын
it doesnt matter which equation you sub x into, its up to you, they chose the first one
@midwestrailroadproductions8116
6 жыл бұрын
I love Wootube, and Woo's Wonderful World of Maths.
@Klaizee
5 жыл бұрын
5:05 where do u get 6 from can u tell me ive got a exam and need helped on this as fast u can thank u
@ettebagu7835
5 жыл бұрын
Since we know that x = 3 if we sub it into equation (1), then 2x (which is 2 times x) would equal 6
@Klaizee
5 жыл бұрын
@@ettebagu7835 thanxxx my friend
@zzng0
4 жыл бұрын
multiple 3 with 2
@yuvrajbhasha7654
4 жыл бұрын
u must be in like grade 4-7 i guess, ngl thats really easy to solve
@Tiffany-nk8np
3 жыл бұрын
LMAO preach, I've got exam block next week
@goody3shoes543
Ай бұрын
this channel will never not be useful
@Keepintheflow
3 жыл бұрын
Shoutout to the twins
@youngcashmoney.2323
3 жыл бұрын
how did you get x = 3 from -9x = -27 ?
@mifeke6149
3 жыл бұрын
Step 1) Divide each side by -9 to leave x on its own. Therefore x=-27/-9 Step 2) -27 divided by -9 = 3 Therefore x=3
@madblox252
Жыл бұрын
Bring - 9 to other side which will give you x = -9/-27 which is x = 3 (since the numerator and denomenator is negative thay cancle)
@thememelifechoseme5429
7 жыл бұрын
Great Video :) Helped me for sure!
@godchild7490
2 жыл бұрын
EXCELLENT TEACHER !!!!! & PATIENT !!! ..... SOME VERY RUDE STUDENTS ..AT FIRST.
@waterisgood5023
3 жыл бұрын
Thank you man helped me
@nanyanzidorah7477
2 жыл бұрын
How do I solve dis sir (x-4y)2 =11 and 3x+8y=11 but 2 is squared
@carultch
Жыл бұрын
You'll end up needing to solve a quadratic formula, when you have squared variables. Solve the linear equation for x: x = (11 - 8*y)/3 Substitute it in to the equation with stuff squared: ((11 - 8*y)/3 - 4*y)^2 = 11 Expand: 400*y^2 - 440*y + 121 = 99 Move the 99 to the left, so we have zero on the right: 400*y^2 - 440*y + 22 = 0 Apply quadratic formula: y = (440 +/- sqrt(440^2 - 4*400*22))/(2*400) y = 11/20 +/- (3 sqrt(11))/20
@babyporkchop122
2 жыл бұрын
Epic eddie woo clutch
@podkyo
2 жыл бұрын
i love you
@zacayerst6731
3 жыл бұрын
helped heaps cheers
@andrewkim1333
3 жыл бұрын
Thank you.👍
@Klaizee
5 жыл бұрын
is this foundation plzz tell me
@xxsunflowerxx9295
3 жыл бұрын
I wish I had him as my math teacher
@yamicrbxl6641
3 жыл бұрын
why is everyone coughing in the class
@kiino213
6 жыл бұрын
Plesse help me with these y=3-5x 2y²-x²=1+3xy
@JMTVYoutube
5 жыл бұрын
{TH}Tran PS gay
@carultch
Жыл бұрын
Take the first equation, and substitute it in to the second equation: 2*(3 - 5*x)² - x²= 1 + 3*x*(3 - 5*x) Expand and gather to the left hand side: 64*x^2 - 69*x + 17 = 0 Use the quadratic formula: (69 +/- sqrt(69^2 - 4*17*64)/128 Solutions: x = 69/128 - sqrt(409)/128 x = 69/128 + sqrt(409)/128
Пікірлер: 57