@17:39, my result is a*b is globally identifiability. All steps are the same as yours. Why?
@glebpogudin3882
Жыл бұрын
Hi! I am not sure I understand the exact computation you perform. Both a + b and a * b should be identifiable in that model as they are invariant under the transposition of a and b. If something is still unclear, feel free to email me
@ThanhNguyen-bs3xl
Жыл бұрын
@@glebpogudin3882 You are true. I found my mistake. Thank you.
Пікірлер: 4