I learned more about Ohm's Law from these 5 videos than ever. Excellent!
@sparkytech8787
10 жыл бұрын
I can't thank you enough you are the best, I learned heaps more than my TAFE in a very short time in the comfort of my home, and the option to replay thank you so much great video.
@maximpulse
10 жыл бұрын
Daniel, thanks for your videos on electricity. You have helped to clear up some concepts that have eluded my for years. It occurred to me one way to understand why the 100 ohm resistor drops 10x the voltage of a 10 ohm resistor is to imagine the 100 ohm resistor as ten 10 ohm resistors. In other words, imagining 11 resistors in a row where each one drops 1/11th of the voltage. Then I mentally group ten of them as one and it becomes much clearer what is going on. So thanks again for what you have done here.
@boredgonewild386
8 жыл бұрын
Also, Thank you very much for taking the time to make these videos. Extremely helpful.
@bivideo7
11 жыл бұрын
Wattage can be calculated in several ways. V^2÷Ω, A^2xΩ, or AxV. Each device dissipates its own heat - series or parallel - so you simply use the amps, voltage drop and resistance of each device and calculate.
@selfmademan09
11 жыл бұрын
Thank u ! Im an hvac student. You made ohms law "come alive " thanks !
@ColeenDove
10 жыл бұрын
These videos are the best! This, along the with Series video make things so clear! Great models.Thank you!!
@jpol3808
5 жыл бұрын
If you learn the formula using your symbols V, A and Ω In the same layout as the standard ohms law formul ______E_____ over I x R than remembering the three individual formulas to find each letter is easy. Just pick the letter your looking for and either divide or multiply the other two letters that are left, depending on what side of the line they are left on. Instead of trying to remember each formula individually like you were trying to do in the beginning of the video. Makes remembering easy. Just remember E over I times R or your letters, V over A times Ω. Now we can also do the standard Watts law formula and figure out _____P_____ over I x E or PIE. (Not math pie 3.1416...) Where P would be W or watts, I would be A or amps and E would be V or volts, in your letters. Just Remember the P over I times E or your letters W over A x V and now pick a letter to solve for, by using the two remaining letters and what side of the line their left on, do the math. Remember if both remaining letters are left below the line than you multiply them together and if they are on either side of the line you divide the top letter by the bottom letter. You can now figure out the wattage of those bulbs or resistors in your circuits. Now, and I'm not going there, but you can combine Ohms law and Watts law and lay all the 12 possible combinations of formulas together in the shape of a clock and find the value of any of the letters E Volts, I Amps, R resistance and W watts, by knowing the values of any two letters of either formula. Just remember that, I is the intensity (size or amount) of current flow measured in Amps and E is the electrolomotive force (push or pressure) of current flow measured in Voltage. Ohms Ω is the measurement of the Resistance to current flow of anything in a circuit and Watts is the actual power available in an electric circuit. Now you have learned the correct formulas, what the letters really stand for and understand the definitions of each letter. You understand that each thing or device has its own resistance value and will only pass through it a certain amount or intensity of current flow in Amps before burning up. It runs on a specific flow of electrolomotive force measured in voltage and uses up or consumes a certain amount of watts of power to do what it's supposed to do, like make your toast, or your coffee, weed whipping your yard, or filtering your pool water, lighting your brake lights when you stop, or heating your home with warmth. The electric company calculates your usage in k (thousands) of watts called kilowatts. See, You have now mastered each law and how to use them the proper way, for all electrical things, the same way everyone in college has been taught to learn it, since Mr. Ohm -resistance and Mr. Watt -power, figured out those laws that apply to electricity many many years ago. Besides, think of how silly you'll look on an interview or talking to your mechanic about your slow running fuel pump, If when he mentions resistance, you pipe up and say oh yea, V equals A times Ohms! Silly to learn the wrong way when the right way isn't very hard at all. Have fun calculating stuff. Then try BTU's if you dare. Just don't call them H for heat, please. Jpol. Just use T for temperature rise instead! ;)
@pakistantribunetv
8 жыл бұрын
very many thanks .. very lovely way to teach every thing .. thnks again ..
@bivideo7
11 жыл бұрын
Different calculation. I use W=AV (wave) instead of the other engineering variables because I teach what will be seen on the meter. The formulas are still valid - W=AV, W=A^2Ω, W=v^2/Ω.
@jesseruiz4367
7 жыл бұрын
great videos bought the book and the load pro but can't seem to just find the tmx meter by itself. does it only come in the combo package u have?
@lucdumouchel3864
10 жыл бұрын
I really appreciate your teaching. I finally understand Ohm's Law. My only problem is, I try'd many times 1/x and it never works. What do I do wrong? I used one of scientific calculator on internet. If ever you can help me, I would appreciate. Thank you
@bivideo7
10 жыл бұрын
Luc - Remember to hit the 1/x AGAIN at the end, after you hit the (=) sign. It's an easy mistake. Try with numbers you know will work. 120Ω is a good one. 2 x 120Ω is 60Ω. 3 x 120Ω = 40Ω, 4 x 120Ω = 30Ω, 6 x 120Ω = 20Ω, and 12 x 120Ω = 10Ω. So - here it is -- 120(1/x) + 120(1/x) = (1/x) ===> 60Ω. Let me know if that does or doesn't work. DS
@nasir7811
11 жыл бұрын
Great job thank u
@mikeadler434
Жыл бұрын
👍👍
@lucdumouchel3864
10 жыл бұрын
Thank you so much to answer me. You know, I tried like 100 more times and finally the problem was the calculator that I choose on internet. I tried few more, and finally I found one that worked. So, for anyone who wants to use calculator on line, don't discourage, try another . www.math.com/students/calculators/source/scientific.htm This is a link where it works. Thank you
@fatih3194
8 жыл бұрын
is really more resistance in parallel make less money then less resistance ?
@stealthsilen
10 жыл бұрын
Daniel, when you use the amp meter it's dangerous right? Is using the loadpro also dangerous since you're applying amps too?
@edwaggonersr.7446
9 жыл бұрын
+stealthsilen I'm pretty sure the LoadPro applies ohms of resistance not amps.
@boredgonewild386
8 жыл бұрын
In your closing statement, your amp meter reads .72... that threw me off for a minute because the circuit was .38 amps
@bivideo7
8 жыл бұрын
Can you give me a min:sec location so I can review?
@boredgonewild386
8 жыл бұрын
17:20 it clearly reads .38, at 17:24 theres a cut scene and it then suddenly reads .72
@bivideo7
8 жыл бұрын
I have no idea. It's a steady 0.72A, which is essentially double 0.38A. If it's the same set of resistors, what could I/might I have done (and edited out for time) that would have doubled the amperage?
@henrypoul
11 жыл бұрын
What about calculating watts
@user-de9dn8kx9x
9 жыл бұрын
What is the brass material you used and how did you secure it to the board? Thanks.
@bivideo7
9 жыл бұрын
kzitem.info/news/bejne/u3qEl6aGoJ-WYGU
@afterdark6822
9 жыл бұрын
For some reason when I try to manually calculate the ohms I fail to get 32.2.
@bivideo7
9 жыл бұрын
NY Mogul What do you mean by "manually"? Calculator? Remember to use the [1/x] key for all individual resistors AND again after you get a total.
@afterdark6822
9 жыл бұрын
Daniel Sullivan Taking the formula at 8:43 when I divide one by each load then add them up and then do one divided by that sum I don't get 32.2.
@bivideo7
9 жыл бұрын
NY Mogul 50Ω[1/x] + 90Ω[1/x] = 0.031111[1/x] = 32.14Ω --- is this not what you get?
@afterdark6822
9 жыл бұрын
Daniel Sullivan On the calculator yes but using the formula at 8:43 no.
@afterdark6822
9 жыл бұрын
Daniel Sullivan Unless you mean 1/x takes the place of the formula every time you use 1/x. So if you were to calculate it by hand it would be 50Ω[1/ (1/R1 + 1/R2 + 1/R3)]
Пікірлер: 36