in the second equation (2x = 6 mod 20) when you divide both side by 2, you must divide 20 by GCD(2,20) so the result would be (x=3 mod 10)
@technoflash77
7 ай бұрын
Yes I too felt the same ...Hope he will reply and clarify doubts of thousands @nesoacademy
@technoflash77
7 ай бұрын
15 = 5 mod 10 if we common out 5 then it will be 3 = 1 mod 2 and not 3 = 1 mod 10.... so getting answer correct at the end of video is just a coincidence .... in short we are right 4
@rajeshprajapati4863
2 жыл бұрын
Answer to H.W. : X = 122 For Verification : 5 mod 3 is reducible to 2 mod 3. So, X = 122 holds for given congruent equations.
@preeti4534
2 жыл бұрын
In Homework question, please tell me what is the value of M1^-1, M2^-1 and M3^-1?
@rajeshprajapati4863
2 жыл бұрын
@@preeti4534 1,2,3 respectively.
@harshavardhanas5799
Жыл бұрын
BUT 122 IS NOT THE PRIME NUMBER
@pandarikathera8418
Жыл бұрын
@@preeti4534 m1 inverse=1,m2inverse=2,m3=25.
@nazansari9902
9 ай бұрын
HOw can we reduce the 5 mod 3 to 2 mod 3
@utilizator1701
2 жыл бұрын
5:26 sorry, but x=3 mod 20 is just one of the 2 solutions. The other one is 13 mod 20.
@md.nomanibnehabib3395
2 ай бұрын
The given problem states that \( X = 122 \) for mod 3, 5, and 11. We can't get \( a1, a2, a3 \) as 5, 2, and 1, respectively. Therefore, the question is incorrect. The correct values for \( a1, a2, a3 \) should be 2, 2, and 1. hope you understand , if i am wrong than let me know the correction..
@bolisettyshashank9754
2 ай бұрын
Clear explanation ❤
@SrisailamNavuluri
Ай бұрын
In the second set equations 4x=9q1+5,2x=20q2+6 x=53 is the minimum value
@donthusravya2026
2 жыл бұрын
I got X=122 for home work sum but in verification for first equation i.e 122 mod 3=2 but in question it is 5.How is it possible??
@hazemkak
2 жыл бұрын
because 5(mod3)=2(mod3)
@aluvaja9653
Жыл бұрын
5%3 == 2%3
@partharora356
Жыл бұрын
@5:38 , the equation written is wrong , it should be x= 3 mod10 , we also have to divide inside the mod, eg. 10=2mod8 implies 5=1mod4 , not 5=1mod8 , so the solution is wrong
@GreatDG
3 ай бұрын
It's incomplete, there will be 2 solutions 3mod20 and 13mod20
@kumar-bi2ef
11 ай бұрын
You explained clearly sir... Keep putting new vedios.. Keep going up.. Continue rocking.. Put more vedios.. Continue I will always support you sir. .. Very soon you will reach more & more subscribers... 🎉 All the best...
@kajal5217
Жыл бұрын
2nd equation should be X=3(mod 10) Because cancel 2 from mod as well Final answer is 53
@amlansaikia235
Жыл бұрын
Yes I have the same doubt
@raghusinni
Жыл бұрын
Correct.
@toveyfan5097
Жыл бұрын
Yea when I saw the equation just now, I immediately went to the comment section.
@bijeshk.s9709
Жыл бұрын
5:27 i feel like we can't cancel 2 there. We can only do that if 2 and 20 are relatively prime but they are not.
@sanjaymandal1698
Жыл бұрын
Yes wrong it will be x=3(mod10)
@poojasaxena41
20 күн бұрын
Yes , you both are correct@@sanjaymandal1698
@pavankumarm5809
Ай бұрын
Hello can anyone tell, what if we get zero as reminder while we are finding the multiplicative inverse of the number.....
@mdnuzmolislam6450
8 ай бұрын
Sir, 143*4 mod 9 also congruent to 5 mod 9. so why should i have to do 4^-1 in both sides? while i found X then we need to just multiply the X into 4 or the value that is given. Simple.
@JarppaGuru
6 ай бұрын
1:45 yes we can, but what X is? what we are calculating. where those other come? like this is private key and this cipher and x answer is private key. like real example not just this numbers. what they are?. this was exact same video but use diff numbers that other. what have to do network security?
@KidSite409
Жыл бұрын
Best teacher 👍
@user-bm4mm8fw9e
19 күн бұрын
Great teach ❤
@thanmaijami8962
2 жыл бұрын
X=122
@SequinBrain
7 ай бұрын
HW: X = 122, but when 122 is divided by 3, we get 2 as the remainder, not 5 Which doesn't fit for x = 5 (mod 3). Or is X = 5 (mod 3) equivalent to X = 2 (mod 3) since 5 / 3 = r2?
@pathumdilharadissanayake5032
7 ай бұрын
its correct. 5(mod 3) can be further reduced to 2(mod 3); and you can also think it as this way; 122 = 120 + 2 = 120 -3 +3 +2 = 117 +5 = 3*39 +5 which is also correct.
@SequinBrain
7 ай бұрын
@@pathumdilharadissanayake5032 thx, cuz I rechecked my math, didn't see anything wrong, saw 122 in another comment, then was confused by the 5.
why i am getting M I of 20 mod 9 equal to 9 using extended euclidian theorem instead of 5
@preeti4534
2 жыл бұрын
Please give the explanation of homework question.
@rohakdebnath8985
4 ай бұрын
53 is the smallest positive solution. Increments by 90 will be valid as well
@senugege
Жыл бұрын
my freind, thank you so much, you explain everything pretty simple and understandable...
@_AnujJangra
2 жыл бұрын
sir what is the meaning of neso ? it is a simple name ?
@mnnsi
2 жыл бұрын
no it's a SO SIMPLE name
@jeevithar9700
8 ай бұрын
Thank u sir
@manishaballa2720
2 жыл бұрын
thank u so much sir🙏
@adonis450
Жыл бұрын
M1 and M1 inverse gets cancelled right
@monicabattacharya6416
2 жыл бұрын
😃😃😃thanks sir
@UsamaEnan
10 ай бұрын
122
@Chandu-ls5jf
2 жыл бұрын
thanks
@pandarikathera8418
Жыл бұрын
m3 inverse for homework is 25??
@faveuryoumbi393
Жыл бұрын
Im not able to find M3 inverse
@faveuryoumbi393
Жыл бұрын
Well explained
@utilizator1701
2 жыл бұрын
Homework answer: 122.
@vamshireddy3830
2 жыл бұрын
please share solution pic
@rohitsai4995
2 жыл бұрын
please upload next videos also ASAP
@andrewgalbraith1858
11 ай бұрын
I went through the problem but fixed the error at 5:25 and got x = 53 (mod 90). Which works, but it would nice for the modulus to be 180. Here's what I did: x = 53 (mod 90) x = 90k + 53 for some integer k. k is either even or odd, in other words leaves a remainder of 0 or 1 when divided by 2. If k is even: x = 90k + 53 = 90(2m) + 53 = 180m + 53, where m is another integer. So, x = 53 (mod 180) is a solution. If k is odd: x = 90k + 53 = 90(2n + 1) + 53 = 180n + 90 + 53 = 180n + 143, where n is an integer. So, x = 143 (mod 180) is the second solution.
@KrishnaTripathi1709
7 ай бұрын
THANKU FOR SHARING WRONG INFO 😊😊😊😊 I LOST MY 4 MARKS BEACUSE OF YOU JUST REALISED U CANT JUST DIVIDE BOTH SIDES BY 2 THANKU FOR YOUR EFFORTS
@rashmimantri8250
3 ай бұрын
😂😂
@ultrainstinct4482
3 ай бұрын
I think the correct ans of 2nd last (6:00) quo is 11
@baranbeytemur5451
Жыл бұрын
answer is 53
@serfreshvlogs4119
Жыл бұрын
x = 122
@user-tm6li7vh2v
5 ай бұрын
Hw. Ans. 287
@user-ef6st2kf6q
6 ай бұрын
Home question: Change 1st equation X=1(mod 3) then X will be 67 holds true for all
@justpaulo
2 жыл бұрын
Sir, I think there is an error in this video. X=143 indeed solves the problem, but X=53 does it also, and it is smaller. I think the issue is in the simplification step @ 5:26. You see, X = 13 solves the original equation 2X ≡ 6 (mod 20), but it's not a solution to X ≡ 3 (mod 20). I believe the 2nd equation simplifies to X ≡ 3 (mod 10) instead.
@smilealways7344
2 жыл бұрын
Yes.
@smilealways7344
2 жыл бұрын
Can I have your phone number please?
@rywen1
2 жыл бұрын
2.X=6(mod20) X=13 , a1=8,a2=13,m1=9,m2=20,M=180,M1=20,M2=9 ==> 20.M1i=1(mod9) , M1i=5 and 9.M2i=1 , M2i=9 as equation X=(8.20.5+13.9.9)mod180 , 1853 (mod180)=53 so X=53
@amlansaikia235
Жыл бұрын
Yes this must be correct
@Princesstherine
2 жыл бұрын
Good
@vivekkalyan7885
5 ай бұрын
Sir ji 😢 mere se m1×m inverse nhi nikal rha h solution btao please 😢
@AmazingAtoms
Жыл бұрын
for hw question im getting 98mod15
@JarppaGuru
6 ай бұрын
1:10 we can read. there no need this1 this2 this thre bladiblabla
@sagarbarman4106
2 жыл бұрын
Formula ka Sign Wrong hai 🙂 Congruent sign hoga, Equal sign nahi hoga
@nazansari9902
9 ай бұрын
Just ignore that brother
@heershah434
Жыл бұрын
2x=6mod20 -> x=3mod10 not 3mod20
@heavenhitter74
Жыл бұрын
h/w ans is 137
@dronamrajuchanda3262
28 күн бұрын
ans 53
@mamatayeul1394
10 ай бұрын
Home work answer is=122
@kowshik_reddy_iguturi
Жыл бұрын
113
@stacydevries4241
7 ай бұрын
Maybe 7?
@Sarifyakkha
8 ай бұрын
H/W Answer is x = 40 .
@hendriii1991
Ай бұрын
X=368
@saisaladi5151
2 жыл бұрын
X=12
@ANUJTANEJA-gc1jp
10 ай бұрын
bro doesn't know how to pronounce a simple a and x, what the hell is yae yex?
@lidwinekamdoum6714
2 жыл бұрын
X=77
@pavani8943
2 жыл бұрын
❤🥰🥰❤🥰🥰❤🥰🥰❤
@saadahmedkhan7017
Жыл бұрын
Sir apne mod toh niklana sikhaya hi nhi
@vamshireddy3830
2 жыл бұрын
112
@junmonirunjun1798
2 жыл бұрын
This video is wrong
@manas-tapas-Art
Жыл бұрын
Lovely❤🎉🎉🎉thank sir🎉
@thotakurisaiamithchowdary849
2 жыл бұрын
X=122
@justpaulo
2 жыл бұрын
HW: X=122
@vamshireddy3830
2 жыл бұрын
I am getting 112
@justpaulo
2 жыл бұрын
@@vamshireddy3830 112 ≡ 2 (mod 11) since 10 x 11 = 110.
@utilizator1701
2 жыл бұрын
Same answer for me, but 122 mod 3 is 2, not 5. Edit: Nevermind. 5 mod 3 is 2.
Пікірлер: 111