I was searching like four days in row about a good explanation.. and here we are.. thank you so much professor
@dmcguckian
2 жыл бұрын
You’re welcome, and thanks for the kind words!
@Mmichel07
2 жыл бұрын
Thank you for the explanation. Spent and embarrassing amount of time looking at this problem with no idea what to do.
@dmcguckian
2 жыл бұрын
It’s not an easy problem, so it’s normal to find it a challenge.
@emmanuelwhite7272
2 жыл бұрын
i haven't finished watching this lecture to the end, I already gave it a like. beautiful explanation!
@dmcguckian
2 жыл бұрын
Wonderful!
@exlipse717
3 жыл бұрын
Very well explained. thinking through the problem is excellent. The explanation of the last choice of 48 possibilities in both ways is great.
@dmcguckian
3 жыл бұрын
Thank you!
@faisalmashrur1876
2 жыл бұрын
Dude! You're a freaking hero.
@dmcguckian
2 жыл бұрын
Happy I could help!
@frankied.2828
3 жыл бұрын
Thank you, I learned a lot. I was recently trying to get into probability math and this really helped me. Thank you!
@dmcguckian
3 жыл бұрын
Great to hear!
@FatimaMartinez-dr2dq
3 жыл бұрын
WOW! the way that you explain it's awesome!!! thanks a lot. Saludos desde Mexico!
@dmcguckian
3 жыл бұрын
Thank you 😊 I’m glad it was helpful. I have close friends from Cuernavaca 🇲🇽
@MrNkashani
2 жыл бұрын
Super clear explanation! thank you so much for the video...
@dmcguckian
2 жыл бұрын
You’re welcome
@samirezk1241
Жыл бұрын
If I have three of a kind... What probability is best.. to get rid of one card or two cards?
@Megaheropap
3 жыл бұрын
How can I calculate the probability of getting 4 kings when choosing 13 cards?
@dmcguckian
3 жыл бұрын
Assuming order doesn’t matter, it should be (4C4)*(48C9)/(52C13)
@dmcguckian
3 жыл бұрын
In case your calc freezes up, this should reduce to 13*12*11*10/(52*51*50*49) double check this though bc right now I don’t have a proper pencil and paper
@Megaheropap
3 жыл бұрын
@@dmcguckian How about the probability of getting 2 aces when picking 13 cards from the deck? I don't really understand how you got (4C4)*(48C9).
@Megaheropap
3 жыл бұрын
@@dmcguckian On your other video titled "The Probability of a Four-of-a-Kind", you used 13 and 48
@dmcguckian
3 жыл бұрын
@@Megaheropap think about the fact that the 4 kings is a special case of the four of a kind (if we were choosing 5 cards). There would be 13 of these hands. That’s how you get from four kings to a generic four of a kind
@BlitzHitz
5 ай бұрын
Thank you.
@josemeza1840
2 жыл бұрын
Does this apply to poker? Because I got 4 cards with the same picture.
@josemeza1840
2 жыл бұрын
It's supposed to be for of a kind Wright?
@dmcguckian
2 жыл бұрын
Yes, this is the calculation for the probability of randomly selecting 5 cards from a shuffled deck and choosing a four of a kind. This is not that same as the probability of getting four of a kind in the normal play of a game of poker because you get to swap out cards even in a single hand of poker, let alone in a full game with several hands.
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