bro how did he get 2.55 in the first place XD, i keep getting 0.17
@isabellapellegrini778
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@@jawadzahid24 This might be a little long but it'll be step by step, the first thing I did was to calculate the areas so Ast = pi/4*(80mm^2 - 70mm^2) -> Ast = 1178.09 mm = 1.178 m, then Acon = pi/4*(70mm^2) -> Acon = 3848.45 mm = 3.848 m
@isabellapellegrini778
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@@jawadzahid24 Then I did what he did to get Fst -> Fst=(Fcon)(200Gpa * 1.178m)/(24Gpa*3.848m) -> Fst=2.5511 Fc
@isabellapellegrini778
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After that you have another equation Fst + Fc = 80kN, in which you sustitute Fst from the previous equation getting -> 2.55Fc + Fc = 80kN, then you factorize -> Fc(2.55 + 1) = 80kN -> Fc(3.55) = 80kN, that's where the 3.55 came from
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