It's been 5 years since I've taken thermo and this question popped in my head. Great explanation.
@kaana8421
Жыл бұрын
I'm retaking this class after failing it last year, and you've been quite helpful with my preparations for retake
@Azakadune
Жыл бұрын
Oh my god, I’m usually a very good student, but reading the textbook is so much to take in; it leaves so much unsaid when giving me the formulas, this is an excellent example of that; my textbook and professor said squat about this. Thank you/
@kylecatman7738
Ай бұрын
This is the most important video to watch, thanks Dr ????? whoever you are... it explains why you use enthalpy on closed systems, which i kept seeing done on some problems and i was like why????? This tells you why, very useful video!!
@FerasBiyikli
11 ай бұрын
Dude this is an amazing video btw, people need to understand the beauty of these equations. The cool thing about this video that it is timeless too. Good job sir, thank you
@kylecatman7738
Ай бұрын
Flow work, like Boundary work is included in enthalpy, just wanted to clarify why we use enthalpy for flow systems as well as closed systems at constant pressure (boundary work like in pistons or balloons).
@nicolascaleroarteaga4461
2 жыл бұрын
Thanks a lot for all the videos, you made this class soooo easy!
@s4ulyaniv35
9 ай бұрын
Hi, thank you very much for your video. I don't grasp why we add the boundary work, isn't it comprised in work out?
@kensonmalupande2424
4 ай бұрын
Great explaination
@natasyakhaidir9380
2 жыл бұрын
I cant understand before this you said expansion is positive then why now expansion is negative and out?
@gooddeedsleadto7499
5 ай бұрын
Boundary work & work out should be the same thing? Boundary work (PV) eventually becomes the shaft work? Why is it being subtracted twice from Q to get change in internal energy?
@sethwilliams3683
2 жыл бұрын
How about turbine problems or any problems with a mass flow rate? They always seem to use enthalpy and I'm not sure why...
@engineeringdeciphered
2 жыл бұрын
Yes, any time you have a moving fluid, use H because that takes the energy to move it into account.
@sethwilliams3683
2 жыл бұрын
@@engineeringdeciphered thank you for your quick response!! This video helped tremendously.
@aasiqkumar732
Жыл бұрын
@@engineeringdeciphered what? Can u explain little more
@shankarpalamootil8688
3 жыл бұрын
So just to make sure, we minus expansion from your main equation because it is Wb out?
@sunmichoi6888
2 жыл бұрын
Thank you so much!
@dremr2038
2 жыл бұрын
Expansion is work out. Everything is positive if it "in".
@selinaydemir9453
2 жыл бұрын
someone have should this!!!!! gracias mucho
@mysticvaulttv
9 ай бұрын
i love your lectures but i hate how u changed all the signs of work in and work out, makes it soo confusing
@engineeringdeciphered
9 ай бұрын
I like to teach Q+W=deltaH and then everything “in” is positive and everything “out” is negative. But it’s perfectly fine if you want to use Q-W=deltaH, so then you would say work “out” is positive and work “in” is negative. But you would still keep Q and energy as “in” being positive and “out” being negative.
@mysticvaulttv
9 ай бұрын
@@engineeringdeciphered ok thank you. You're lectures are helping so much. Thank you again 🙏
@fatsow3639
3 жыл бұрын
Thank you!!!!
@khaledshebani8111
Жыл бұрын
Thank you... A clear and simple explanation. Can we connect via email or WhatsApp?
@sevgipnar5261
6 ай бұрын
I dont undertstand in 4:08 shouldnt it be the equation is Q-W=H2-H1 ı mean why work becomes positive?? We derived the equation from negative Wout
@mebawubeshet6729
5 ай бұрын
I DONOT UNDERSTAND WHY U DO NOT USE Q out or W in ur equation
@absolutcloud
Жыл бұрын
For the third equation, How do i calculate Qin individually ?
@solounomas0
Жыл бұрын
Maybe you could calculate Qin=mass*Cp*(T2-T1)
@solounomas0
Жыл бұрын
where cp is the specific heat capacity
@jorgelevario3478
4 жыл бұрын
Hey what about isothermal process ????
@engineeringdeciphered
4 жыл бұрын
It depends: if it is a constant temp AND constant pressure then use the first box. If it is constant temp AND constant volume then use the second box. But it is probably constant temp and neither const pressure or volume so you would use the last box. (I’m talking about the three boxed in equations at the 6:00-7:00 mark in the video).
@jorgelevario3478
4 жыл бұрын
@@engineeringdeciphered love the fact reply!!!!
@jorgelevario3478
4 жыл бұрын
fast*
@jorgelevario3478
4 жыл бұрын
Thank you so much!!! basically Isothermal does not dictate the behavior or which one to use. From my understanding.
@jorgelevario3478
4 жыл бұрын
I have exam Teusday and I have spent all semester looking for this exact video on the world wide web THANK YOU AGAIN!!
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