Thanks a lot. I have been struggling on Thevnin’s Theorem, and from watching your video I managed to pass all my exams. I have been watching all the tutorials on TT, and your tutorial is the most clear and helpful. :))
@AliRizwanMasood
5 жыл бұрын
Its been 5 Years since the Snap.... The world has not been the same since Maerina has stopped uploading videos
@genshingt7792
4 жыл бұрын
L
@AliRizwanMasood
4 жыл бұрын
@@genshingt7792 It somehow got worse
@genshingt7792
4 жыл бұрын
@@AliRizwanMasood lmaoo😂
@DenDhur
7 жыл бұрын
This was a hugh help! You explain it way better than my Uni.Teacher, thank you!
@ricardocabral3330
5 жыл бұрын
fuck, so relatable
@sathirakatugaha974
5 жыл бұрын
This video was actually very good in my opinion despite the slack it's getting. It's not a tutorial on everything, just thevenin theorem. No need to go into depth for nodal analysis; all I needed was to see how thevenin works and that's what I got. Very glad, thank you!
@aboodkareem2396
2 жыл бұрын
Many thanks my lady , I've got this lesson in the first stage ,that was in 2004 and now I have refreshed my informations ,,,
@mathewbellamy261
7 жыл бұрын
In node analysis you should explain that we must include a ground on a reference node. So if you take reference node on node which is spotted on the branch between of b and the resistor 4ohms then Vb=0. The Vth = Va - Vb, where Va=V2 which you are right. But Vb = 0 because of the ground.
@anassaifi7613
6 жыл бұрын
Agree bro
@nabanitagoswami6652
5 жыл бұрын
Thank you
@esaskhan95
8 жыл бұрын
Needed a recap of this and you cleared all my confusions! Very nicely explained, two thumbs up!
@mercystrength5477
6 жыл бұрын
Can please, explain how you got Vth as 6V? As nice as the video is, I couldn't arrive at the 6V using equation 1 at Node 1 or Equation 2 at Node 2
@TonyTv15
Жыл бұрын
Same question here.
@aurumaugmentus5991
5 жыл бұрын
"When the world needed her the most she vanished", we need ur vids
@YoAirFresh
7 жыл бұрын
There are a lot of people who doubt that Vth is 6V. Do this instead: Transform the voltage source into a current source of 2 Amps. Combine the two current sources and get 4 Amps. Transform back to a voltage source, 4 Amps * 6 Ohms = 24 Volts. Use voltage division to find the drop across the 4 Ohm. That is 24 volts * (4 / (6+6+4)) Ohms = 6 volts.
@walterbaldemor2128
7 жыл бұрын
Or you can use the two 6ohm and 4ohm in series and get the voltage across 4 ohm. With 24v as the loop source. Say 24x4/16= 6volts. I hope it helps
@The_Daya
6 жыл бұрын
YoAirFresh nice explain and here using voltage division rule may I right Voltage division rule: Vth = total voltage × opposite resistance/sum of total resistance
@321reh
6 жыл бұрын
Thank You YoAirFresh...Perfect Explanation!!!
@muballatofficial3754
5 жыл бұрын
Could the whole process be done with the superposition method?
@modibosco9287
2 жыл бұрын
i got 2v so i dont know she arrived at 6v but her explanation was excellent
@omar7amdi
5 жыл бұрын
Here is how she got 6 V. From node2: arrange the equation to get V1=5/2 v2 From node1: arrange the equation to get 4 - 2/6 V1 + 2/6 V2 =0 Substitute for V1 in the above equation: 4 - 2/6 * 5/2 V2 + 1/6 V2 => 4 = 5/6 V2 - V2/6 ==> 4= 4/6 V2 ==> multiply both side by 6/4 . The result is V2 = 6 V.
@Anbuninja840
2 жыл бұрын
still wrong she didnt include the 4ohm resistor in series with the 6 resistor
@VALIANT_Electronics
2 жыл бұрын
@@Anbuninja840 who told you 4 ohm resistor is in series with the 6 ohm resistor?, first you do series then parallel, 4 ohm is in parallel with 12 ohm.
@Anbuninja840
2 жыл бұрын
@@VALIANT_Electronics since the a and b is opened , the 4 ohm became series with the 12 ( 6 and 6 )ohm resistor
@VALIANT_Electronics
2 жыл бұрын
@@Anbuninja840 nope, opening in a and b has nothing to do with that, if they share 2 nodes that's parallel.
@kennethbanda7622
2 жыл бұрын
Where did you get 2/6V2 on Node 1: 4-2/6V1 +2/6V2 ??
@navaneethan8327
3 жыл бұрын
I am from india.Thank you very much now only I understanding the thevenin's concept by your video.Thank's a lot.....
@ibrahimahmethan3015
7 жыл бұрын
than u soo much . i had this question in my book but i couldn't slove it . then i found that u done it here . keep up the good working. god bless u
@catman8965
8 жыл бұрын
Clearing up the algebra: From node2 multiply both sides of the equation by 24. 4V1-4V2-6V2=0 Solve for V1 4V1=10V2 thus V1=(5/2)V2 From node1 multiply both sides of the equation by 6. 12-V1+12-V1+V2=0 Simplify 24-2V1+V2=0 Substitute V1 from node1: V1=(5/2)V2 24-2(5/2)V2+V2=0 24-5V2+V2=0 Simplify -4V2=-24 OR V2=6 and V1=15
@horridharry33
7 жыл бұрын
At the line where you write: '12-V1+12-V1+V2=0 Simplify', Shouldn't it be '12-V1+12-V1-(minus here instead of +)V2 = 0 if you look at her equation for node1
@kylesaucier7650
4 жыл бұрын
Where do you pull the 24 from?
@catman8965
4 жыл бұрын
Kyle Saucier Trying to remember my thinking from 3 years ago, I think I multiplied both sides of the equation by 24 to reduce the number of fractions that would be created simplifing the typing and making the reading a little bit more clear.
@standog3696
2 жыл бұрын
@@kylesaucier7650 the 24 is from 12+12
@zacharylewis3528
6 жыл бұрын
I’ve been looking all over the place for help on Thévenin equivalent circuits. This video finally helped me understand! To find V2 you just have to solve two equations with two unknowns.. it’s just algebra
@matnor1149
6 жыл бұрын
Unnecessary complication unfortunately. Better to solve this kind of problem using the source transformation technique.
@AlexPiotrowski
8 жыл бұрын
thank you! you are ten times better than my lecturer!
@timtim3084
8 жыл бұрын
really clear, thx a lot:) you made a marvelous start on my final revision! looking forward for more video!!
@s3ody9999
6 жыл бұрын
You explain the lesson better than my doctor.
@louishao2516
7 жыл бұрын
Thanks a lot .. you just make a mundane understand better
@egeuludag972
2 жыл бұрын
very helpful, clean, clear and punctuative. thank you very much.
@NvDSky
6 жыл бұрын
i have an exam tomorrow , this is a life saver
@tauqeernasir1132
5 жыл бұрын
wil u plz explain,how do we find the vth in the same circuir with mesh, your explaination about thevnin with noodle is so good.i hope you solve my problem.
@sagarrajkumargupta5168
3 жыл бұрын
hi
@ramyagopalakrishnan8682
7 жыл бұрын
Thanks for your video.This problem is really solved and i easily understand .
@ankitsaurav5071
7 жыл бұрын
Thanks so much for your such fab explanation...... Hope it will help today in my exam👍👍👍👍
@heisenberglull1181
7 жыл бұрын
i love her speaking accent!
@nsa3679
6 жыл бұрын
She’s Russian.
@jamesretreat
5 жыл бұрын
shes greek
@Maen963
5 жыл бұрын
She is french
@perrytheplatypus8380
5 жыл бұрын
she is everything 🤣
@adekunleafolabi1040
4 жыл бұрын
Awesome explanation Marina. I find thevenin and norton's theorem particularly interesting it's why I tried as much as possible to solve a lot of questions on the topics on my channel.
@whomisac4616
9 жыл бұрын
Anybody confuses about what +Marina Belkina did. Here is the full list of the procedure: 1. Nodal Analysis on two node: V1 and V2, you could name them as VA or VB, does not matter. 2. As part of the nodal she did KCL (current In=Current Out) in each node. 3. Did simultaneous equation solving to figure out the voltage in V2. [Note: she made an ground node analysis in node 2 to get (-V2/4ohm) because Vground-V2=-V2 as Vground=0V] 4. She claimed no current will follow the end of 4 ohm resistor so V2 will be the same as the Voltage through Open circuit = VTH.
@whomisac4616
9 жыл бұрын
Hi I think what you did with current analysis to the node by KCL is quite wrong, because current don't just add up because they want to. From Voltage source of 12 V battery current flow clockwise but 2A currect souce(supplied) is going anticlockwise relative to the voltage source so should not there be a negative sign. I don't know how you worked but your Thevenin Voltage seems reasonable to me. Thanks.
@JustWatchingVideo56
5 жыл бұрын
Whom Isac Her KCL is correct if don’t want to mess up though just do V1 drops over every branch and you add them up to zero. Basically following the idea that at any given node all current is either going into the node or going out of it and it adds up to zero. That’s how I do it. So my equations for this would be: (V1-12)/6 - 2 + (V1-V2)/6 = 0 (V2-V1)/6 + V2/4 = 0 Personally I don't try to determine if the current is going in or out of a node based on intuition because it can be confusing. I just like to be consistent with this method and not have to worry about it. After all it's nodal analysis, you look at it from the node not the circles.
@paklunpoon218
3 жыл бұрын
Thanks for your video. Your example is similar to my homework question. Now, I can solve it with clear mind. Hope you can upload more video
@MA-qz1sd
5 жыл бұрын
at 3:17 shouldn't the 4 ohm resistor be in series with the rest of the resistors ? I could be wrong I just need clarification on why you think theyre in parallel thanks
@isaiahphillip4112
5 жыл бұрын
Don't forget that there's a node on either end or the 4 ohm resistor. Therefore it's not in series.
@michaelambrose3470
2 жыл бұрын
This is a very good example, Marina, and also well explained. The major problem, with your video, however, is that you have NOT shown how to solve the two equations formed, by Nodes 1 and 2, by the elimination, of V(1) which you really must show. V(1) = 2.5V(2) and working through, gives: (2/3)*V(2)=4, so V(2)=6V
@TheDeathstriker123
8 жыл бұрын
Why is Vth=V2 ? it should be V2 - V3 , where V3 is voltage at junction point just to the left of open terminal b
@jokerrecon8420
7 жыл бұрын
It is assumed that they're connected to the ground, hence V3 = 0. This is just to make the problem simpler.
@amritacharya5771
2 жыл бұрын
Agreed!
@ryanhegarty2936
9 жыл бұрын
Great job! This was a good review for me.
@u.rpaplu8424
6 жыл бұрын
tnxxx fr uploading this video...Infect your determination of V2 is superb... its a supernode bt u did it very easily which made this concept easy to me...
@sotiris6116
5 жыл бұрын
1:35 and i oop-
@sachinandanprasad7618
3 жыл бұрын
ooppp
@subhendudey6261
9 жыл бұрын
Really much more helpful .........Thank you
@mattkan3275
3 жыл бұрын
Perfect tutorial , thank you Marina !
@sarahee4178
4 жыл бұрын
why is this better than lectures in class?? :(
@ahmednobi5533
8 жыл бұрын
this video helped me alot to understand this thereom in my final exam today .. thanks alot 😊
@ivanhuynh3607
10 жыл бұрын
You can also use superposition theorem to solve for the voltage drop across 4 Ohm resistor. It takes a bit longer but it works if you haven't learned Nodal Analysis
@voyasart
5 жыл бұрын
superposition is embedded within the theorem.
@abhinavaray299
2 жыл бұрын
Yes . actually by doing that we are getting 3 volt for both cases(two sources alone) and they add up to 6 volt
@ojingbadu7221
7 жыл бұрын
Your voice is more anticipating I am in love😍😍😘
@ghkaispodos
8 жыл бұрын
thank you very much Marina, greetings from Greece!
@michaeldrolet7386
6 жыл бұрын
For this to work, she had to automatically assume that Vb is GND, correct?
@videoeffectstutor
5 жыл бұрын
Yeah I think so
@snehpoddar2674
6 жыл бұрын
you din't explain vth properly..!!!! EVEN THAT NODE EQUATIONS ARE NOT PROPERLY DESCRIBED
@ohmakademi
4 жыл бұрын
*Thank you very much. Very useful explanation*
@mqhelemugqakayisemguni709
4 жыл бұрын
l am sure you meant well but you could have given us a heads up that your method of solving this circuit had a nodal analysis prerequisite. Left us in the cold... well because the voice is nice went to study nodal and lemme see how it goes
@heisenburg6380
8 жыл бұрын
Thank you for your explanation Now I can a Do the 10 marks question in tomorrow exam
@shifty7
7 жыл бұрын
oh my English
@lorrainenyathi5106
4 жыл бұрын
Thank you...u helped me a lot now am ready for my finals
@feriacientifica6139
6 жыл бұрын
Súper! muchas gracias desde Freirina, Huasco, Chile
@angie96blizz
9 жыл бұрын
Why is the 6Ω and 4Ω resistors are in parallel? I thought they are in series. And why you used current division in solving for i? You used the Vth as the current source and used current division. I'm quite confused. Hoping for your reply. Thanks a lot..
@masenshiba2129
9 жыл бұрын
+Angelica dela Peña yeah i think the two 6 ohm and 4 ohm are all in series
@marinabelkina8397
9 жыл бұрын
+Angelica dela Peña These resistors are in parallel according to points a and b. And I didn't use current division, I used nodal analysis to find Vth. You can only use current division if you have one power source in the circuit.
@angie96blizz
9 жыл бұрын
Ahhh okay now I got it. Thanks a lot!
@Twist3dElements
8 жыл бұрын
Both terminals of the Req (equivalent R) of the series resistors share a common node with both terminals of the 4-ohm resistor. Therefore, by definition, they are in parallel.
@abdurrehmankidwai5389
8 жыл бұрын
angelica when current gets dvded then resistance become parallel so in thes q current flows from 6 to 4 there u see current s geting dvided
@nikhithajulakanti4839
7 жыл бұрын
Thanks for the video, it was very helpful. Please clarify my doubt: while calculating Rth, we removed both power sources... we considered voltage source as short circuited, but why did we take current source as open circuit? i mean, why didnt we consider a shorted connection between 2 6ohms resistors while calculating equivalent resistance?
@pranticksen4454
7 жыл бұрын
Thank you so much... :) You just made it so easy for me...
@MrYounis26
6 жыл бұрын
For Rth shouldn't you first calculate 6 and 4 in parallel and then add the other 6?
@Sjsime827
7 жыл бұрын
Love your videos and love your voice, haha!
@sagarrajkumargupta5168
3 жыл бұрын
itni achi bhi nahi hai
@almeida13peter
10 жыл бұрын
how did you calculate V2 as 6 volts?
@marinabelkina8397
10 жыл бұрын
2013Aleksey2013 Aleksey, Thank you)
@masroorahmed1638
8 жыл бұрын
+Marina Belkina how to calculate v2 as 6 volt.
@tevinmorgan191
7 жыл бұрын
peter almeida , simplify the two equations by removing the fractions then solve simultaneously
@king_kunta095
6 жыл бұрын
your high school algebra teacher must give you change
@IshtiaqueHossainAyon
6 жыл бұрын
Thanks a lot. Beautifully described!
@chaman1996
8 жыл бұрын
thanks a lot marina .....u did a great job
@nidalfikri3445
8 жыл бұрын
Marina :D thnx for this video :D u got a lovely voice here
@kirolos94
9 жыл бұрын
your explain is very good . please continue make videos and start in circuit with ac sources :'D
@githice
9 жыл бұрын
Clear, no ambiguities, perfect
@whomisac4616
9 жыл бұрын
+Aneya Florence Was not very clearly explained. Unless you are good in basic understanding. Because much more simplified explanation was needed. Because not everybody's brain is the same.
@githice
9 жыл бұрын
+Whom Isac I respect your opinion, maybe I hv an advantage
@shifty7
7 жыл бұрын
brilliant, no flaws, beautiful
@jaketracy1375
9 жыл бұрын
Much more helpful than my actual teacher. THANK YOU
@yorenton
8 жыл бұрын
How did you get 6v for v2?
@davidcham9954
8 жыл бұрын
+yorenton Set one of the equations for the nodes equal to V1 and plug it in to the other equation. This should change one of the formulas to be a function of V2 instead of a function of V1 and V2 and solve.
@anonakayamopaba9898
8 жыл бұрын
+David Cham yet the answer should be 4 and not 6
@thehindupenguin1684
8 жыл бұрын
I think you didn't calculate Vth properly. 6V is correct
@parikshitht1456
7 жыл бұрын
correct
@jonardmarcoromero3488
7 жыл бұрын
multiply the equations by the lcd of the denominator then simplify the equations then use systems of equations or you can use calculator mode:equations:simul polynomials represent V1 as x and V2 as Y :)) WC If you are still confused you might want to scan your notes from algebra 1,2. :)))
@nazzarnews
9 жыл бұрын
You are a great teacher
@budakkacamata10
8 жыл бұрын
because there is two sources, u use the nodal analysis method to find Vth, is this true????? is there another way to find Vth????? Please reply, its night and my finals is tomorrow morning.
@merensow200
5 жыл бұрын
May this video be blessed!
@bishalshrestha7522
9 жыл бұрын
Thanks a lot Madam !!!! you are teaching..........
@gieraz9291
8 жыл бұрын
Vth... 6ohms, what about the current source of 2A that create also a voltage over the (6 and 4ohms resistors. Maybe I wrong... I belief that you also need kvl to know the voc (over the 4 ohms resistor).
@jackerjacker51
Жыл бұрын
Thanks for the video but, there is something u need to correct, with the equation u have written V2 must be equal to 3.5 V
@MH-jf9mq
4 жыл бұрын
Amazing stepwise approach
@mostafaamingz
6 жыл бұрын
thanks for your effort but in the Node Voltage method we assume that every currents is coming out of the node
@josepheastman8509
5 жыл бұрын
Why wasn't v1 subtracted from v2?Instead of the other way around? I thought that all voltages are either were either supposed to be coming into or else leaving the node right?
@proshidhhajong9914
8 жыл бұрын
Really helpful. plzzzzz do upload for Norton also.
@CholoCJS
7 жыл бұрын
Proshidh Prosonno Hajong, for Norton is the same as thevenin, the only difference is that in the equivalent circuit you get a current source in parallel with an equivalent resistor (Which is called "Norton Resistance" this time).
@proshidhhajong9914
7 жыл бұрын
Thank you so much for the reply Luis. One basic question to ask. How do we know a given circuit is to be solved if it is not mentioned that the circuit is to be analyzed by Norton or Thevenins ? Will the final answer be same for current and voltage?
@ohmakademi
7 жыл бұрын
thanks so much.. this is very useful...
@dabulls1g
6 жыл бұрын
how on earth is a video that skips some of the most fundamental concepts behind thevenin's theorem useful to you AT ALL?
@danishzia6442
5 жыл бұрын
Thanku thanku thanku very much nice teaching very well, excellent
@lilyjames4170
8 жыл бұрын
u r a very gud teacher
@ricardodelabarra4948
8 жыл бұрын
A very useful video...thank you!
@leisalekalorib2494
10 жыл бұрын
How did you find vth? Confused
@leisalekalorib2494
10 жыл бұрын
Oh i understand. Thank you
@Ko_725
7 жыл бұрын
Leisale Kalorib nnm
@vasilisnikitakos9792
7 жыл бұрын
really helpful ! thanks a lot!
@202slh8
3 жыл бұрын
You made it so much easy🙏🙏
@MantisRay861
6 жыл бұрын
I thought you made currents negative when coming into a node, and positive leaving. Or is that only with KVL/KCL?
@luqmanedri948
7 жыл бұрын
for node 1 , the equation should be (v1 - 12)/6 right? Please explain to me...
@adityangurunarayanan5407
7 жыл бұрын
By convention, we assume that current flows from +ve terminal of voltmeter to the -ve terminal of the voltmeter. By that convention current would flow from + side of 12V voltmeter, goes thru the circuit, comes back to 12V voltmater at the -ve terminal.So 12V is higher than V1 and so + current = (12-v1)/6. Hope this helps :)
@julianarias3271
9 жыл бұрын
hi, for every exercise like this can I use nodal analysis to solve it and assume V2= Vth? hope for your replying. by the way thank you so much for the video. its hard to understand my Chinese teacher.
@1FRAG1B
9 жыл бұрын
+Julian Arias Only if there are no other resistors in between a, the 4 ohm resistor and b
@julianarias3271
9 жыл бұрын
+1FRAG1B Thank you!!
@rebornnum1fan
7 жыл бұрын
So let's just say I convert the current source into voltage source which would make 2Ax6ohm=12 V Total voltage is equivalent to 24. By using voltage divider law whereby: V2= 4/(12+4)*24 = 6volts. Is this valid?
@IlluvatarXi
5 жыл бұрын
fucking fantastic, easy and simple to understand. thank you
@badral-amri8622
7 жыл бұрын
Why did you consider the terminals from a to b open circuited in nodal analysis and didn't consider it open circuited in calculating Rth ?
@asis_sahoo
8 жыл бұрын
your explanation is very good...please add more videos regarding electronics...
@anishborkar6655
4 жыл бұрын
Thanks for such nice explanation
@Callisto314
8 жыл бұрын
i keep getting 4v & 10V, could you please tell me what im doing wrong?
@gateaspirant2387
7 жыл бұрын
no
@benjomabil6071
4 жыл бұрын
me too
@deepikaupadhyay3206
9 жыл бұрын
thank you , appreciate your work :)
@raymartdeguzman5905
5 жыл бұрын
6V is correct, the first equation will give v1 = 12 + 0.5v2, the second equation will give v1 = 2.5v2, equate both equations and you'll get v2 = 6V
@waleedmalik3420
5 жыл бұрын
VTH is essentially the point at which the voltage going to the resistor is consistent in terms of value. So in this case, VTH is the point where the resistance is 4 ohms. Ideally V2, should have been labelled VTH.
@Ashishkumar-vb7qh
4 жыл бұрын
Nice mam your voice very sweet.. 😍😍😍aap india se ho..??
@VitoxCzechia
3 жыл бұрын
Thanks for trying to help me and other 1 020 224 people! :)
@hadinsf
7 жыл бұрын
VERY SIMPLE AND GOOD WORK !!
@janphilipbalbin8886
4 жыл бұрын
in 6:12, in node 1, should it be -V1/2? help negative because of the current is to the node.
@rahulram7760
4 жыл бұрын
Just wanted to thank you! :)
@alphachannel3042
7 жыл бұрын
From which book this question is taken from?
@TothZ1000
8 жыл бұрын
Calculating Vth you could also use superposition and voltage/current division as well. The 12 V voltage generator create V'th=12*4/(6+6+4)=48/16=3V. The current generator's current should divide calculating the current on the 4Ω resistor i4=2*6/(6+(6+4))=12/16=0.75A. After this you could calculate the second part of Vth which is V"th=4*i4=3V. Finally the Thévenin voltage is Vth=V'th+V"th=6V.
@DrNoxer
7 жыл бұрын
Finally somebody who tinks like me...
@nathiyaa2095
7 жыл бұрын
What are the applications of Thevenin's theorem in electronics?
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