Almost 10 years later, and this video is still pretty awesome. Thanks for so many good resources that my students have used through the years! I wish my videos aged this well 😏
@FlippingPhysics
2 жыл бұрын
Thank you so much!
@astro_penguin_
Жыл бұрын
Thanks to you I feel much more confident on my AP Physics 1 exam!! You're the best!
@FlippingPhysics
Жыл бұрын
Wonderful. Best of luck tomorrow!
@someonestolemypc8435
2 жыл бұрын
Thanks for these videos
@chemical_x5350
4 жыл бұрын
You're videos are a gem💎💎✨
@FlippingPhysics
4 жыл бұрын
Thank you!
@BenXu-sw3os
3 ай бұрын
whos watching this video 10 years later and still admiring the editing
@nikhilsingh5863
9 жыл бұрын
Since the acceleration is constant when the ball is going up and coming down (-9.81 m/s^2), then using our uam equations and the data: vf=0, change in x=0, and a=-9.81m/s^2, we get initial velocity and change in time as 0, which is impossible. How come the UAM equations do not work?
@FlippingPhysics
9 жыл бұрын
***** My assumption is you mean the change in y = 0 (not change in x) and when you refer to the velocity final = 0, you are referring to after the ball strikes the ground. As soon as the ball touches the ground, the ball is no longer in free fall and the acceleration of the ball is no longer -9.81 m/s^2. The UAM equations work and the final velocity of the ball right before it strikes the ground ≠ 0.
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