This question is from Series A Question paper of CSAT in UPSC Prelims 2019.
60. Number 136 is added to 5B7 and the sum obtained is 7A3, where A and B are integers.
It is given that 7A3 is exactly divisible by 3.
The only possible value of B is (a)2
(b)5
(c)7
(d)8
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