我觉得可以用波函数来看可能换种思路也可以得到75%: If we use wave functions for this problem: =C1|1>|0>|0>|0>+C2|0>|1>|0>|0>+C3|0>|0>|1>|0>+C4|0>|0>|0>|1> Where it is |At Bar 1>|At bar 2>...|At home> and |C1|^2=|C2|^2=|C3|^3=3/10 and |C4|^2=1/10 Then the police's check will collapse the wave function twice, by left multiplying the "measurement" basis to collapse it: |0>+C4|0>|0>|0>|1> At this moment, finding the drunk at bar 3 becomes |C3|^2/(|C3|^3+|C^4|^2)=3/4 Same....lol
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