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I love it when he says - "that looks important, lets put a box around it" :)))
@samloos3531
Ай бұрын
YES! This is the first one I solved on my own!
@That1BeegWhale
18 күн бұрын
Same here actually, good job bro
@dmuth
Ай бұрын
This channel continues to be a pleasure and a delight. I'm so glad I subscribed!
@user-ox4ii2bw6x
Ай бұрын
Simple and easy, very nice and very exciting!
@jamesrocket5616
Ай бұрын
People like you make Math look like a fun hobby, how exciting
@thomazsoares1316
Ай бұрын
When the life gives you a square and a circle, apply the pitagoryan theorem. That's RULE ON THIS CHANNEL How exciting!
@thomascarter8833
Ай бұрын
I have been watching your videos for a while and this is the first one I have solved on the first try!
@greendruid33
Ай бұрын
That was a tough one. Nicely done.
@henricovsky9363
Ай бұрын
I love the vids! These help me a lot
@henrygoogle4949
Ай бұрын
This’es is brilliant work.
@karagumruk2104
Ай бұрын
How Exciting…
@matthewkendrick8280
Ай бұрын
I love liTTle r
@notonlyhuman6073
Ай бұрын
I was looking for someone to mention it! 🤣
@Kuwustilam
Ай бұрын
Incredibly exciting
@earthdragonw
Ай бұрын
yay! I worked this out on my own. Love your math problems
@meow65
Ай бұрын
how exciting!!!!!!!
@mhkkarami2435
Ай бұрын
Excellent
@cmilkau
Ай бұрын
Not very elegant but it works. Once you have established R² = 5r² by Pythagoras, you know that πR² = 5πr², i.e. the blue full circle has 5x the area of the orange full circle. Now it's just a bit of fraction logic: so a blue half circle would be 5x the orange half circle (50). A *quarter* blue circle is then half of that (25), and the shaded area is minus the orange area (25 - 10 = 15).
@Jack_Attack1234
Ай бұрын
How Exciting?
@nikhilhalbe
Ай бұрын
How exciting
@tanko.reactions176
Ай бұрын
s := square sidelength rrpi/2 = 10 rr = 20/pi r = (20/pi)^.5 s = 2r R := radius of blue circle R = (ss + ss/4)^.5 A := quarter area of blue circle A = RRpi/4 ---- substitute R: (ss + ss/4)pi/4 substitute s, simplify: (4rr + rr) pi/4 = 5rrpi/4 = substitute r, solve: 5(20/pi)pi/4 = 5*20/4 = 5*5 = 25 blue area without the orange circle = 15
@picknikbasket
Ай бұрын
How eloquent!
@DriftinVr
Ай бұрын
I got about 40/pi which is close but didn't get it right fully, Great explaination on and figured put what I did wrong!
@rabidbuddha4328
Ай бұрын
New background! As a programmer I’m not sure how much I want to recommend thinking like a programmer.
@gitchfitness6591
Ай бұрын
Nice
@subzero.cuber47
Ай бұрын
If a = area of blue circle, x = radius of half circle, and y = radius of quarter circle, then 10 = πx²/2 20 = πx² 20/π = x² If 2x = a side of the square, we can use the pythagorean theorem (2x)² + x² = y² 4x² + x² = y² 5x² = y² x√5 = y now use q.c formula π(x√5)²/4 5πx²/4 Now substitute πx² for 20 using the equation somewhere above 5(20)/4 100/4 25 Now subtract the 10 = 15u²
@jjwxnett
Ай бұрын
Interesting
@anseiler
Ай бұрын
When I had a look at the thumbnail, I solved it like this: Because of the pythagoran theorem, R:r is equal to the square root of 5. Have a look at the yellow triangle if you don't see it at once. This means, the area of a full blue circle equals 5 times the area of a full orange circle. Relations in area are always the square of the relation in length. Beacause it is a quarter blue circle and half of an orange circle, the relation is 2.5:1. For the blue area, this is 25 - 10 = 15.
@PreschoolFightClub
Ай бұрын
Wait. If it was asking for the blue area, wouldn't the correct answer have been the quarter circle's total area minus the orange semicircle's area?
@PreschoolFightClub
Ай бұрын
@user-kv9pg7hu7mYes. Yes he did. I have no clue how I missed that part.
@Solarbeam42
Ай бұрын
I've replaced my lessons with your videos
@BlackFriday-lp2gc
Ай бұрын
Is not 40u ?
@klatis84
Ай бұрын
h-oww exiting?...
@MattLuceen
Ай бұрын
1:48 4 20 😮😂
@williamdragon1023
Ай бұрын
I know it’s not to scale, but that don’t quite look right
@raqqafeller152
Ай бұрын
i found “25” cause i didn’t read the question properly and assumed that it asked for the area of the 1/4 circle. RIP
@hassanawdi3793
Ай бұрын
You didnt to calculate r butt leave it r^2
@pokeflora
Ай бұрын
littol arr...
@revantdadoo512
Ай бұрын
W
@armantavakoli5314
Ай бұрын
l i t t l e R
@angelaogara1219
Ай бұрын
5th
@mr.turtle375
Ай бұрын
liTTTTTTle r,beautiful
@myfishcalledbobble6923
Ай бұрын
4th
@AlmightyFSM
Ай бұрын
Um.. ok but.. I don't think you can guarantee that the black square intersects the blue quarter circle at exactly "little r" height from the x axis can you? A very slightly wider radius on the blue circle would mean it's *not* the same distance (from x-axis to intersection), and there's nothing in the image to say that this is the case. What am I missing?
@ShaneBaumanUWaterloo
Ай бұрын
the hash marks on the sides say that the blue circle intersects the square at the midpoint of the sides. The side length of the square is equal to 2r. So half of the side of the square is r.
@AlmightyFSM
Ай бұрын
@@ShaneBaumanUWaterloo ok good point... Although I wasn't aware of the "international line hash" standard implying precise midpoints ;)
@Grizzly01-vr4pn
Ай бұрын
@@AlmightyFSM The line hash means that all line segments in the diagram with that hash have equal length. So if a longer line segment is split into two smaller segments, and each of those smaller segments have the hash mark, they are the same length, and thus the split point must be the midpoint of the original long line segment.
@michaellacaria910
Ай бұрын
@@ShaneBaumanUWaterloo That was my big question mark too but you answered it nicely, thanks.
@michaellacaria910
Ай бұрын
How exciting… and Brilliant!
@KristianYeager
Ай бұрын
No no nooooo! Keep the pi terms as they are so you have 5(20/pi) = R^2 and just substitute that into the formula for the blue area!!! The pis cancel, you’re left with 100/4 - 10 = 15
@godlyBlade
Ай бұрын
Yes, I too watched the video.
@Grizzly01-vr4pn
Ай бұрын
That is what happened.
@ccmplayer87
Ай бұрын
2:00 - 2:05 is a brilliant idea
@obsoleteprofessor2034
Ай бұрын
Answer: The blue area is California. And as in all blue areas, the total (votes) is always more than what is really there.
@Stooge2
Ай бұрын
Looool
@frankstrawnation
Ай бұрын
Good joke, but try to avoid poisoning the comment section with politics.
@comp1080p
Ай бұрын
booooooo
@4.0.4
Ай бұрын
I 120% agree. (20% is from mail-in agreement)
@obsoleteprofessor2034
Ай бұрын
@@frankstrawnation Sorry... couldn't help myself. It was just standing there like a big question mark asking "WHAT?"
@NimbusDaDumbass
Ай бұрын
This channel is the only reason I can still do mathematics 😂
@kkkggg19
Ай бұрын
I found a really good question. How can I submit it?
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