FINALLY a simple explanation without excess verbiage. Thank you so much.... keep making videos!
@ryanburchett8455
2 жыл бұрын
My thoughts exactly. I just found this, though.
@cdnjmusic
10 ай бұрын
Finally a real genius who explained this to me like a nursery rhyme, yet the knowledge I gained is invaluable 😢❤
@Avgenius
3 ай бұрын
AWESOME! Thank you!
@DannyWJaco
11 ай бұрын
My first introduction to Q. Now I can "perform surgery" on some of my old Marantz 4-track mixes from the 1990's! Thanks!
@Avgenius
3 ай бұрын
Nice!!
@Dr.Fingertips
6 жыл бұрын
Thanks man, I really appreciate you explaining this so simply and clearly.
@ismaelestabile1553
6 жыл бұрын
Finally a short and good explaining of the Q factor, i was getting confused on some sites
@cyrusnanavati
2 жыл бұрын
Excellent simple explanation - thanks Greg - well done!
@someguy9173
9 жыл бұрын
Hope to see you back again sir! We need some more of your awesome knowledge, thanks so much!
@Metalhead-4life
6 жыл бұрын
I always wondered about this setting on my yamaha reciever, thanks this is a good place to start for info
@CopenYotas
Жыл бұрын
Awesome video
@kredenzp.5468
10 жыл бұрын
Hey you're back -- it's been a while! And you uploaded a video in HD. Awesome!
@UltraNuggz
3 жыл бұрын
Oh wow perfect thank you! Working with the Dayton Audio DSP, the defaults were 2.15, will set all down to 1.5 and run the sweep again. Subscribing now.
@mystcat3
4 жыл бұрын
I'm learning to use the Web Audio API Biquad filter effects and this video was very helpful!
@anibalpinero3728
2 жыл бұрын
Thank you so much!
@mercyaudios
3 жыл бұрын
Very nice explanation, thank you.
@jaderington
3 жыл бұрын
Joseph Fourier I am not. So thanks for keeping it real simple, great !
@owen0314
5 жыл бұрын
thank you so much for your intuitive explanation !
@RanGer-498
Жыл бұрын
Thanks
@gtslikemike4649
2 жыл бұрын
Super helpful, thanks man!
@ChrisDarkMentaL
4 жыл бұрын
Note that plugins might have different values for quality factor. Pro-Q for example has every q value multiplied by the square root of 2 or Oxford multiplied by 2. So for Pro-Q one octave is 2 and for Oxford one octave is 2.83.
@brucedickinson8993
6 ай бұрын
Studying to cut out 1.2khz and play metallica and pantera!
@duranarts
3 жыл бұрын
Brilliant
@kingblack6965
3 жыл бұрын
thank you
@scurrellous
5 ай бұрын
Fantastic explanation. Thank Q...see what I did there.
@Avgenius
3 ай бұрын
Glad it helped!
@xorsama
4 жыл бұрын
big thank
@geestoddard7765
6 жыл бұрын
Please do not more videos. You are explain it clearly.
@tylerbelk5371
5 жыл бұрын
So that's what that does😂😂 thanks man!
@vladfarcam4817
5 жыл бұрын
From your formula in fou change 500 to 600 or any other freq the Q also changes. That is wrong, Q should not depend on the freq. Am I getting something wrong?
@Avgenius
5 жыл бұрын
Yes. The Q IS dependent on the frequency. It is calculated by dividing the center frequency of the filter by the range (bandwidth) of frequencies that are affected by the filter. So yes, a Q of 1.5 at 500 Hz covers a bandwidth of 333 Hz and a Q of 1.5 at 600 Hz covers a bandwidth of 400 Hz. But don't fret - We hear octaves, not numbers - the Q of 1.5 affects the same OCTAVE range at every frequency, even though it is not the same NUMBER of frequencies...
@skyhr
3 жыл бұрын
What is the equation translating Q to oct? Reaper EQ uses oct instead of q...
@Avgenius
3 жыл бұрын
First off, it’s nice to just use the octave number. For general tone changes, 1 octave is pretty good at lower frequencies, 0.5 octave is pretty good at higher frequencies. For surgery, use something like 0.33 (one third) octave or so. To answer your question though, the EQ center frequency divided by bandwidth in Hertz, gives you a Q. So if you know the bandwidth in “octaves” you need to convert it to Hertz. Multiply the EQ corner frequency by the octave number and blammo, you have the bandwidth in Hertz. Let’s say you set the EQ in Reaper to 0.5 octave at 500 Hertz, you would take 500 Hertz divided by (500 Hz * 0.5 octaves = 250) which equals a Q of 2.0. Savvy?
@skyhr
3 жыл бұрын
@@Avgenius Thanks for the reply! How do I do it in reverse? I know the center frequency and Q values in TDR Nova, and I want to convert them into oct in order to input them into Reaper EQ, which has considerably low CPU usage in live streaming. Say, the center frequency is 500hz and the Q is 1.5. What would the oct be? Does this apply for high shelves too?
@skyhr
3 жыл бұрын
I see. I think the answer is that Q is the reciprocal of octave. I'm going to try this and see how it works.
@Shoto519
8 жыл бұрын
soo if i want to cut 50 hz at 200 hz my q should be 4?
@Avgenius
8 жыл бұрын
Yes! A Q of 4.0 at 200 Hz, would be a bandwidth of 50 Hz - so it would affect roughly 175 to 225 Hz, with the peak at 200.
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