Thanks a ton! I had only 2 days before my physics exam. I tried, but system of particles and rotational motion went above my head! Six hours I studied and tried to figure out what was written in book. In panic I decided to see online lectures and came across this. The whole night I watched your lectures. Next day I started solving problems. My concepts are so strong now!! I am expecting a 100% in my physics paper and thats just because of you!! Thank you so much! Now solving problems and deriving equations is a cake walk.
@ayushjakhmola7881
6 жыл бұрын
ek din ki practice se kux ni hoga
@sanandreas2765
12 жыл бұрын
sir you are fantastic.
@BangaloreTechie1511
10 жыл бұрын
sir, why did not you convert omega in radian/sec in 2nd numerical?
@apni123456
12 жыл бұрын
sir your ethical juncture of life is good but on the same thing I would rate you a dream teacher ever that a student can desire to have
@kunibaki
11 жыл бұрын
i do agree sir is definitly the dream teacher
@mehulkondapally5573
9 жыл бұрын
HELLO SIR this is tanay from my bother's account sir u r an awesome teacher ur lectures helped me a lot to understand many concepts. thank u
@VIKASHKUMAR-he3bs
4 жыл бұрын
Good morning sir 🙏🙏🙏
@ajaysaini-np6qi
9 жыл бұрын
sir , in starting lecture on moment of inertia ( 62), in the very first example of rolling two similar balls, u said that the one having higher moment of inertia will cover greater distance , and now in this video, while solving the last question by a different approach (1:06:00), you said that the one having highest moment of inertia will attain the lowest acceleration , i.e. it will stop first.
@uchidamadarasenju7175
9 жыл бұрын
sir wat about radius of gyration
@RohitSingh-pq8ss
7 жыл бұрын
sie 37.32 per jo numerical hai....usme omega=v/r lia hai vo v to periferal velo. hai.....and KE me jo v hai vo CM ki velo hai......vo barabar ho gaye ..kaise.....plz mera doubt clear kren
@sreetamkumar8044
8 жыл бұрын
Thanks a lot sir!! Online teaching has been efficient to me sir!! Simply awesome sir!!
@sohamlanke7571
6 жыл бұрын
Thank You Sir!!
@nityambagga160
11 жыл бұрын
sir in the second numerical i think u have made an error while calculating the angular velocity of the sphere. you forgot to convert it into radian/sec
@sherazkhalil5504
8 жыл бұрын
nice sir good job
@sunilkoparde8852
8 жыл бұрын
Thanks a Lot Sir......
@uchidamadarasenju7175
9 жыл бұрын
where is the radius of gyration
@SachinKumar-cp5xy
5 жыл бұрын
Yo yo kya hota hai
@doorofdreams5024
6 жыл бұрын
thanku so much sir ji....🤗🤗
@akashravindran2154
8 жыл бұрын
in the question at 35:45 how did you take the moment of inertia of sphere to be 2MR^2/3??? IT is 2MR^2/5 right???
@akashravindran2154
8 жыл бұрын
why did you take it as a hole sphere???
@akashravindran2154
8 жыл бұрын
+Akash Ravindran hollow*
@vedantparasrampuria4260
6 жыл бұрын
you are a legend
@SUDHARSANRathnakumar
11 жыл бұрын
Sir all throughout your video you have explained in the case of a pulley falling down or even the last numerical where you have taken the value of I on the account of perpendicular axis, shouldn't the axis be taken along the diameter when it rolls?
@sunnymishra3344
10 жыл бұрын
sir....how did u resolve the mg into its components......and where did u get the theta......will u plz explain that to me?????
@mansiaggarwal4839
10 жыл бұрын
sir...in acceleration in rolling under gravity , why did we take torque= friction * radius but not mgsin theta * radius...as it is also a force acting on the object. and similarly in rolling of pulley, why did we take torque= tension* radius and not {tension+ma} * radius...as thery both r together acting on pulley..plz do reply
@sanjupaul688
9 жыл бұрын
hello friend i dont know i m correct or not but i think that mg sin theta *r is not taken as the torque because mgsin theta is acting on its centre of mass but friction is acting on its surface. therefore this is the tangential force which will create a torque. and in case of rolling pulley, torque+ma is not taken as the tangential force as mg is only the force which is causing the tension. PLEASE LET ME KNOW IF I M WRONG
@shubhankumar6692
6 жыл бұрын
Sir can work =I×alpha × theta is possible according to work =mas
@poornimasharma2424
7 жыл бұрын
best
@vidyarthiclasses4721
5 жыл бұрын
Sir lekin circular object me to friction saamne hoga n....to equation to ye hona chaiye n...mgsintheta + friction...(kyu ki aqpne hi kaha tha...friction opposes intention of motion)
@vivekmathur6782
11 жыл бұрын
sir in 2nd numerical of rolling motion you take W without calculate its actual value
@uchidamadarasenju7175
9 жыл бұрын
sir Plz also make up the video for slipping without rolling or sliding related concepts... Cz it is asked in many quiz of this chapter
@pallavichoudhary3165
6 жыл бұрын
sir plzzz answer that question its urgent .......
@amanupgraded7000
11 жыл бұрын
sir in the numerical of radius 5cm and mass 5 kg u have write down the value of I=1/2mr^2 but i think I=should be equal to mr^2??
@kanishkjain7137
10 жыл бұрын
Sir in acceleration due to rolling body under gravity.......the frictional force shud be in the direction of mgsin(theta)......bcauz u had told in friction chapter... that for rolling body friction is in the direction of motion....??
@sanjupaul688
9 жыл бұрын
at time 29.00, in the example we had the relation for KE of rolling disc as K.E=1/2 mv^2 + 1/2 Iw^2. after this u converted the term Iw^2 by writing mr^2 for I, and v^2/r^2 for w. i dont understand why u took the rotational velocity same as its linear velocity??? i think v is the velocity by which the CM of the disc is doing linear motion. and the velocity which will come in place of w will be different. this will be the velocity by which a point in the circumfrence of the disc will rotate.
@sanjupaul688
9 жыл бұрын
***** but while calculating 'w' we do not take the av linear velocity of the particle at circumfrence. we take its instantaneous velocity???
@shubhamgupta6304
11 жыл бұрын
sir in video while calculating the power of the bike you converted 12000rpm into 'w' by dividing by 60 and multiplying by 2pi but in case of calculating the K.E. of a hollow sphere you have taken 'w' as 50rpm without dividing by 60 and multiplying by 2pi why so diffrence is there??
@ayushjakhmola7881
6 жыл бұрын
as Omega is rpm ×2πr/60
@sidharthkhurana3249
10 жыл бұрын
sir, in this vedio why we have'nt convert rpm as we have done in calculating the power of bikes
@ashish19ak8
7 жыл бұрын
Sir please add a video for the explanation of topic 'center of gravity'
@pallavichoudhary3165
6 жыл бұрын
rpm is the unit of frequency and as we know that omega=2π(nu), than why you dont convert nu into omega???????
@suhailsaifi562
6 жыл бұрын
pallavi choudhary its a mistake by sir
@rd0769
6 жыл бұрын
sir last numerical ka comparison galat ho gya .. 1/2 , 2/3 , 3/5 ( order of biggest to lower is = 2/3 , 3/5 , 1/2) and quick way can be this one.... just cross multiple terms ( 1/2 and 2/3 ) = 3 and 4 , so second is bigger than first fraction, similarly we can compare others.
@kashifkhan-cv2oz
7 жыл бұрын
sir, inclined par rolling hone par (torque=friction*radius) kiya tha aapne.sir,mere hisab se torque ka value net external force multiply radius hoga na, us hisab se( torque=mg sin theata *radius) hona chahiye. Sir, I am confusing
@RohitSingh-pq8ss
7 жыл бұрын
Md Kashif bhai....mgsinθ to CM per lag rha hai....to uska torque zero hogaya......tabi sir ne ni lia...only friction provides torque
@ShanuKumar-bp6ub
5 жыл бұрын
Sir aapne 2 numerical m glti krdi h. U should multiply 50 by 2pi/60
@SUDHARSANRathnakumar
11 жыл бұрын
Sir but in nert reader it is written mr square/4
@manukr8689
6 жыл бұрын
Si r aap iit jee ke sallabus se padhiye na. Please
@prakashvasan2334
11 жыл бұрын
sir u forgot to convert into rpm to rps in second sum
@amatya11
7 жыл бұрын
Sir are these videos will be helpful fir KVPY exam also ??
@ayushjakhmola7881
6 жыл бұрын
sir at 35.32 ,,,, how we will find omega
@satvendersingh9996
10 жыл бұрын
Sir in "ma+Ia/mr(square) = mgsin(theta)" How can you cancell m of LHS to RHS m ? there is "plus" sign in b/w them !!
@satvendersingh9996
10 жыл бұрын
Sir at 59:08
@satvendersingh9996
10 жыл бұрын
thanks . .i 'll see it again
@sherazkhalil5504
8 жыл бұрын
sir work is a cross product or dot product
@RohitSingh-pq8ss
7 жыл бұрын
Sheraz Khalil work is scalar....and remember always a dot product gives a scalar quantity......लोल
@shashanksah3915
10 жыл бұрын
sir,what is the reason for rotation of the wheel in this video..MIT Physics Demo -- Bicycle Wheel Gyroscope
@kaushikghatak4918
6 жыл бұрын
conservation of angular momentum
@devyanshusuryavanshi9508
6 жыл бұрын
Sir where is equations of rotational motion Plz help fast....
@saithanos9210
6 жыл бұрын
Sir motion in St lines
@warshahid8134
5 жыл бұрын
Students are making noise there.we are not understanding properly
@saithanos9210
6 жыл бұрын
Sir can you explain what is translatory motion
@zainabfirdous7898
5 жыл бұрын
It is simply linear motion.
@talhajaved3090
10 жыл бұрын
Sir How can u Understand all the concept of physics?? Tell me that trick :) Brilliant m a bit a fan of you ! Allah bless You
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