由視頻教學學到如下: 預賽:M X M 數量的車,每一場M數量的車進行比賽,所以預賽共比M個場次。 決賽:預賽有M個場次,就會有M個預賽第一名,正好一起比決賽一場 ,取得冠軍。 加賽:預賽時「冠軍車」那一場的第二名和決賽時的第二名,都有機會亞軍,所以加賽取勝者為亞軍。因此共需要比 M+2場。 回到原題。若M=3,共有3X3輛車,每次比賽用3個跑道,共需要3+2場,才能賽出冠軍和亞軍。
Step one: 9 cars do 3 game Result : G1:A,b,c G2:D,e,f G3:G,h,i step choose every team first two cars: A,b, d,e, g,h make two time games again G4: A,b,d G5: G,h,e If d or e is most fast, thats will in the no.1 result So. The most faster two car is G4 no.1, and G5 no.1
@ranger5322
2 жыл бұрын
What if d or e are not the fastest... The best solution is as taught by Dr.Lee: G4: A,D,G result no.1 and no.2 G5: no.2 of G4, and the no.2’ in the first match with no.1, e.g. no.1 of G4 is A, no.2 is D, then the contestants of G5 are D and b.. Wish my poor English makes it clear to you, jajaja Have a nice day~
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