Math video of the year. Finally someone who explains the big deal!
@francoislechampi2002
5 күн бұрын
Hi Hexagon, I have to go after watching untill 16:54 but I will come back to watch the rest. I want to congratulate you on this beautiful work. I already watched several videos on the Riemann Zeta function but you managed to push it a little further so we lay people can understand it more deeply. Thank You so much and here is my thumb up before I see the remaining part.
@nathanevans6277
12 күн бұрын
Best Zeta explainer yet. 👍
@dcterr1
19 күн бұрын
Wow, this is a truly amazing proof! It reminds me of a very complicated outline of a proof I once saw for the existence of a Turing machine in Conway's Game of Life.
@SenChandan
20 күн бұрын
In ancient times, Eratosthenes' sieve did shine, A mathematical marvel, a treasure divine. With keen insight, he sieved primes apart, Unveiling patterns with his intellectual art. Through the ages, his legacy held tight, Guiding minds to realms of mathematical light. In numbers vast, his sieve did gleam, Revealing primes like a radiant dream. And in the depths of Riemann's mind did stir, A converter of primes, a theorem so pure. With zeta's function, he charted the way, To understand primes in a mystical array. Through complex contours and analytic finesse, He probed the depths of the number's caress. In Riemann's realm, the primes did unfold, In a dance of zeros, a story untold. So let us honor these mathematical sages, Whose brilliance echoes through the ages. In Eratosthenes' sieve and Riemann's converter, Lies the beauty of numbers, forever and ever.
@SenChandan
20 күн бұрын
In mathematics' realm, where numbers align, Euler's number and primes intertwine, A dance of elegance, in cosmic design, A link profound, in numbers' shrine. Euler's number, e, a transcendental star, Constant and infinite, stretching far, In exponential growth, it sets the bar, A mathematical gem, seen from afar. Prime numbers, guardians of the math domain, Indivisible, their unique refrain, Unraveling patterns, with every gain, Infinite in number, yet their essence plain. But what's the link, in this cosmic dance? Euler's number and primes, in a trance, A connection subtle, yet in clear expanse, In number theory's realm, they enhance. Euler's identity, a key to behold, E^iπ + 1 = 0, in numbers bold, A formula profound, in mysteries untold, Where e, i, π, primes' secrets unfold. Complex numbers and their roots abide, In Euler's realm, where mysteries reside, Primes emerge, in patterns implied, Euler's number, their essence allied. In the dance of primes, Euler's number gleams, A link unseen, in mathematical dreams, In the tapestry of numbers, where beauty teems, Euler's number and primes, forever beams.
@kristofferrobinhaug8029
20 күн бұрын
That's numberwang!
@EatScrabbleGoo
22 күн бұрын
what paper did you get the riemann converter from?
@Geek37664
27 күн бұрын
You are the Arnold Schwarzenegger of math…wonderful presentation.
@mistafizz5195
27 күн бұрын
Great channel
@beaumatthews6411
27 күн бұрын
I LOVE YOUR LOGO, I LITERALLY DREW THIS WHILE I was working at Mathnasium! 1/6 + 1/3 + 1/2 = 1!!!
@zachdetert1121
28 күн бұрын
This is amazing! Hands down best video on the topic I've seen (and that means better than 3b1b which is saying something!)
@user-eh9ty1yb1h
29 күн бұрын
"you certainly have the right to be mad at me for just claiming I exist without any explanation" 🤣
@enlongchiou
Ай бұрын
1,(2),3,(2*2) have p(4)=4-(4-0)*(1/2)=4*(1/2) + mod(4,2)/2 + 1 -1=2 from traditional sieve of prime, + 1 for 2 when sieve of 2 we take it out so plus 1 put it back -1 for 1 is not a prime number, mod(4,2)/2=0 for sieve of 2 do not have remainder at 4, between 2^2 =4 to 3^2-1=8 use sieve of 2 only, add sieve of 3 start at 3^2, because sieve of 6=2*3 been use by sieve of 2,3 twice must add one of sieve of 6 back p(3^2)=9*(2-1)*(3-1)/(2*3) + (1/2-3/6+0/3) + 2-1=4=9- (9-1)/2 - (9-0)/3 +(9-3)/6+1=9-4-3+1+1=4.
@mrmrigank7154
Ай бұрын
watched couple of minutes and I am already loving it.
@markwrede8878
Ай бұрын
The Riemann Zeta Function gives the sine value for all X to the limit of the last prime to give a novel sequential difference to its predecessor. The sequential differences available among integers is finite, and so the completed finite function will solve for all factors of X without limit, excepting only 2.
@wesso27
Ай бұрын
Amazing video! Always amazed by the beauties of mathematics
@ArthurvanH0udt
Ай бұрын
FF-ing volume is WAY too low!!!!!
@NowNormal
Ай бұрын
Reverse prime factory function function?
@NowNormal
Ай бұрын
Wait no
@NowNormal
Ай бұрын
Wait that's actually true I thought it was false
@trapkat8213
Ай бұрын
Excellent presentation.
@user-hd3pz2ow1b
2 ай бұрын
cool
@garythomson3580
2 ай бұрын
Thanks for this video. It really helped me understand more about this problem - although still a lot I don't yet fully get!
@TimJSwan
2 ай бұрын
Reminiscent of collatz conjecture.
@weixinguo6094
2 ай бұрын
You teach complex number in a video for Riemann hypothesis?
@NabiruBogdan
2 ай бұрын
Thanks
@NabiruBogdan
2 ай бұрын
Thanks
@v8torque932
2 ай бұрын
it’s easy set it equal to 0 and solve
@rwd420
2 ай бұрын
What a great video!👍
@kub8675
2 ай бұрын
What is the actual name of the function at 11:08. I’ve googled it but I can’t find anything
@andrewporter1868
2 ай бұрын
I say: find a way to get a closed form inverse of the Gamma function and you'll have your pi(n) in no time since we already can compute is_prime(n) in closed form with it by computing a residue, and is_prime(n) = pi(n) - pi(n - 1), but is_prime(n)x is a sort of inverse of prime(n), and prime(n) is the right-inverse of pi(n). Then you can compute the inverse of that to get prime(n) too. Would potentially be handy for speeding up a handful of algorithms I can think of, probably more...
@cameronspalding9792
2 ай бұрын
Anybody who solves one of the Millennium problems will win $1 million. What’s less well known is that if that person can write a rap explaining the proof and then perform it in front of people: they will win $2 million instead!
@cameronspalding9792
2 ай бұрын
@ 27:54 isn’t the integral expression for zeta only valid for re(s)>1?
@jorgesoberon6866
2 ай бұрын
Wow!!! Sheer magic!!!!
@Hanible
3 ай бұрын
parity is so ubiquitous in many proofs that I never noticed how powerful it is!
@dieterbaecher2975
3 ай бұрын
I missed the link to prime numbers. Maybe because its hidden?
@JohnSmith-gu6hf
3 ай бұрын
I would solve this but a million dollars isn't worth as much as it use to be. Can't even buy me a house anymore.
@westudy-byallinone6052
3 ай бұрын
docs.google.com/document/d/1w87YRAlqHLRGP8L_pe-LmeaZhSo35eWI/edit?usp=drivesdk&ouid=117117634412059020038&rtpof=true&sd=true I request to check if I got any mistakes in solving.
@user-ol1ll7lf5p
4 ай бұрын
After watching at least 5 videos, I finally have a better understanding of the connection of the zeta func. to the prime numbers, thank you!
@sidneysilva7364
4 ай бұрын
Eureka!!!!!!!!!I have uncovered the great secret and enigma of times past, how to solve a problem from the 2000th millennium, I am reporting "Rielmann's hypothesis" and I affirm with total truthfulness that the numbers 2, 19. 41 and many others... they are not primes, and twin primes do not exist, I managed to factor a giant number into prime numbers by factoring 04 prime numbers (2,279,269)(Two Million Two Hundred and Seventy-Nine Thousand and Two Hundred and sixty-nine) I found three prime numbers(3,532,343)(Three Million Five Hundred and Thirty-Two Thousand and Three Hundred and Forty-Three) I found three prime numbers, I say Factored into prime numbers)(4,709,233)(Four Million Seven Hundred and Nine One thousand two hundred and thirty-three) I found three prime numbers(7,262,011)(Seven Million Two Hundred and Sixty-Two Thousand and Eleven)I found three prime numbers(2,700,984,697)(Two Billion Seven Hundred Million Nine Hundred and Eighty-four Thousand and Six hundred and ninety-seven) I found 04 prime numbers (all factored only with prime numbers (5,310,765,049) (Five Billion Three Hundred and Ten Million Seven Hundred and Sixty-Five Thousand and Forty-Nine) I found 04 prime numbers (all factored only with numbers cousins from smallest to largest and from largest to smallest...so "The Rielmann Hypothesis has completely lost its force in the current era....... Mr Sidney Silva.
@sathishr7774
4 ай бұрын
The answer is Optimus prime
@lewisking291
4 ай бұрын
But how do you know that the missing numbers can always be inserted? Like when 1 to 12 was missing from the new sequence, you just slotted them in. How do you know that always works?
@krakraichbinda
4 ай бұрын
A great explanation of the problem!
@BriggsProgrammingDevelopment
4 ай бұрын
image if someone proved that if the collatz conjecture is true the Riemann Hypothesis must be false, and if the collatz conjecture is false the Riemann Hypothesis is true. That’s not going to happen, but if it did it would cause a lot of chaos in mathematics.
@adrianmisak07
4 ай бұрын
vert impressive video
@BillyBob-wh4sq
4 ай бұрын
This is a cool topic and your explanation was really helpful in understanding it. Thank you for making such a great video!
@norude
4 ай бұрын
Why, again the furthest point from the sun is almost, but not quite equal to the point, where the Earth's axis aligns with the sun? Indifferent universe, are these two things secretly related?
@joeeeee8738
4 ай бұрын
Amazing explanation!!
@johndoyle2347
4 ай бұрын
Proving the Riemann hypothesis: Moments after a Big Bang, dual numbers are at the origin, repulsive and gravitational forces are balanced, but dark matter is breaking up. Delanges sectrices for the unflaking, Archimedean spiral for spinning up dark matter, Ceva sectrices for that dark matter breaking into smaller, primordial dark matter and black holes, Dinostratus quadratrix for impacting surrounding black holes, and Maclaurin sectrices for dark matter being slowed down over time. Split-complex at one, noting the more gravitational nature of diagonal ring/cylinder singularities of baryonic matter from broken dark matter. Using repetitious bisection, one gets added (SSA) for when dark matter dominates a universe and one gets added for when black holes and rarified singularities make things more gravitational, leading to a Big Crunch. At 2 = a Big Crunch, the solution to the Basel problem, and the "bellows method" drives things. A Big Crunch event needs the net gravity from the localized area AND gravitational effects from surrounding universes. The 2 represents how locked up black holes are making a stacking, planar contact. Everything else are harmonics - effects on surrounding universes. Ramanujan's Infinite Sum of negative one-twelfth: each positional jostling, mass, and gravitational/attractive exchange between universes (defined by Big Bounce events, considering Ramanujan during both Big Crunch and Big Bang sides) ADDS up to evenness (or a partner in marriage - like half of the whole, I guess). Net gravity increases over time from the breaking up of dark matter, much like a vertical asymptote. It continues to increase, but hits a critical point, much like a vertical tangent, when enough dark matter has weakened and been broken up into the more gravitational baryonic matter (split-complex numbers). Then, the effects of gravity reach their upper limit - much like a vertical line - at e to the negative e. Over a decade ago, I said that the potential energy of a Big Bang was 1/6 times (the speed of light, cubed). If I had said Big Bounce instead, I would have been correct.
@MrMatttL
4 ай бұрын
Best video I've seen explaining this. So glad I finally understand! Just need to remember it for next year now 😂
Пікірлер