Clearly spoken and presented. Very informative, thank you for this.
@muhammadabdullahamer1540
4 жыл бұрын
Thanks sir. It was good, precise and had 0 useless jokes. It helped a great deal. Much appreciated.
@entropyz5242
5 жыл бұрын
Very well spoken and straight to the point. Excellent video
@jjl9422
5 жыл бұрын
Very clear demo, big thumbs up for that!
@lelesecchi6140
2 жыл бұрын
Very clear, well done. Thanks a lot I've encountered the hoop stress concept while reading about bicycle tires but didn't know what it is, now I clearly understood the concept!
@marwanadel__
5 жыл бұрын
i have a stress analysis exam tomorrow and this helped much thanks,mate.
@andriy9916
3 жыл бұрын
It makes basic knowledge more strong. Thank you very much sir..
@miakhalifa6171
3 жыл бұрын
I got an engineering job... I didnt even go to college thank you so much for allowing me to visually understand concepts... I may not be the best at the analytical math processes behind this but it helps still!
@mikoajmaecki7979
2 жыл бұрын
Great explanation - thanks m8!
@leeroymagora1206
3 жыл бұрын
splendid lecture
@LetsLearn-ge8ho
4 жыл бұрын
Great Job Sir
@vid_sh_itsme4340
5 жыл бұрын
Awesome...thanks
@rlikemoney
3 жыл бұрын
The fire fighters are not a pressure vessel lol. Thanks for the information. Great video!
@nazmulhasansuman9243
6 жыл бұрын
quite good :)
@t_c5266
4 жыл бұрын
If im to design a pressure vessel and am solving for the pressure given the yield strength in psi, diameter, and wall thickness. How would I go about that? Is it as simple as plugging it in to the formulas and solving for P? obviously taking the lower value of P from the hoop stress?
@rahmatnugroho2995
5 жыл бұрын
What if we want calculate the pressure with rectangular tank? what parameter that should change?
@mehrsachal
3 жыл бұрын
The fire fighters are not a pressure vessel. Hmmm
@mickeyhume7600
3 жыл бұрын
Hi :) Why is it we don't include the axial stress in the hemispherical ends of the pressure vessel? Aren't these like the spherical vessel and contain their own stresses? Thank you!
@zlatanibrahimovic3425
3 жыл бұрын
Very informative video. What kind of tool did you use to draw the pressure distribution diagram at 2:14 ? I would be grateful to know the tool. Thank you
@bigsalo8598
3 жыл бұрын
A fireman... Is not... a pressure vessel... LOL, jokes aside, great video
@CaliRepublic77
3 жыл бұрын
At 2:50, shouldn’t the pressure vectors from interior walls pressure p be painting normal to the cylindrical curved surface? You showed it perfectly horizontal. ? Are you trying to say that this vectors are already the x components?
@jaswanthkumar9527
4 жыл бұрын
Thanq sir
@shubhamagrawal5825
4 жыл бұрын
Great
@MrRodrixxxx
3 жыл бұрын
Hello, great video! But please help me with the following question, which would be the value of p, in calculating: sigma=(p*r)/t, if i have an internal pressure Pint, and an external pressure Pext. Would p be equal to Pint-Pext (in case Pext
@inspectioncorrosion
2 жыл бұрын
Well presented
@laughtherapey
3 жыл бұрын
if hoop stress is twice as much as longitduanal, shouldn't the vessel crack in hoopwise direction rather than longwise, since hoopwise pressure is stronger?
@judeugwu4987
2 жыл бұрын
No. I think it’s because the hoop stress is pulling the area element with greater force at opposite ends. So eventually, there will be a crack perpendicular to the direction, i.e in the axial direction. It’s like if you have a sheet of paper and pull hard enough, the paper will tear along the plane perpendicular to the direction you were pulling
@lelesecchi6140
2 жыл бұрын
@@judeugwu4987 Very nice example!!
@yashshekar7359
3 жыл бұрын
You saved my ass
@cyrilv1703
4 жыл бұрын
Beautifully explained as a concept. I just had one doubt, why, when the pressure is being transformed into a force, the area calculation for the same is shown as A = 2r * dx, instead of A = pi * r * dx; since it's a half circle and the area on which the pressure is acting has the length equivalent to the inner circumference of the half circle. Just a query and it would be really helpful if you could clarify that. Thank you.
@tauraichipurura8465
4 жыл бұрын
also have a query on thati think (pi) must be included because its a circle
@vishank7
4 жыл бұрын
I have the same doubt, and dont know much about it. For some reason, they take the projection of the semicircular strip here, which is a rectangle of area (2r)dx. (Shining a torch from the rhs on the semicircular strip at 2:55)
@vishank7
4 жыл бұрын
Also, shouldnt the pressure always be Normal to the surface(except the longitudinal one) as all other components would just cancel out?
@tuanphamrmit
4 жыл бұрын
The force acting on that half strip (half hoop) is calculated as the integral of the pressure NORMAL to the surface area of the half strip. The result is what shown in the video. It is not the same as taking the pressure times the surface area of the half strip because here we have a curved surface not a flat surface, in which case the force would be p*area. A quick way to calculate force on a curved surface is to take the pressure times the projected area of that curved surface on a plane. The pressure is p, the projected area of the half strip is 2r*dx, hence force dF is p*2r*dx
@ranadebray5440
Жыл бұрын
How to check the Pressure vessel integrity for the ‘full vacuum’ condition of 1 bar external pressure? May you please answer this question.
@justinmcredmond6104
2 жыл бұрын
If i have an air line with 100 psi going in to a vessel 1000 times the diameter of the air line, will I only have 100psi in the larger vessel.
@ZULFERISYAHPUTRA
3 жыл бұрын
Dear Sir..........Example Problem : I have single acting a cylinder with a bore of 18 mm and a rod of 10 mm and a stroke of 300 mm. I want to know what is the pressure if my cylinder presses 10 mm ........... Please advise and provide a solution with the formula
@sanat1102
6 жыл бұрын
I'm still unsure why the hoop stress arises. If the liquid flowing tries to expand the vessel, then it should do in all directions equally, as shown (at 3:52), hence it gets cancelled internally . So then why does hoop stress arise?
@introductoryengineeringmec9114
5 жыл бұрын
If you consider the fluid in the tank or pipe as discrete elements, each fluid element pushes equally against its neighboring elements. A fluid element in contact with the tank or pipe wall pushes against the tank wall and each of its neighboring fluid elements equally. The pressure from the fluid element pushing against the wall causes the hoop stress to arise.
@muhammadjunaidkhan4390
6 жыл бұрын
do u have a vedio on thick walled pressure vessels?
@fera5165
6 жыл бұрын
Please help me understand at ( 5:16 ), how the cross-section area of the vessel can be given as 2* π *r*t. As far as my understanding goes the area should be given as ( π R^2)-( π r^2). I have heard it in lectures, read it in books and it still does not make sense to me. If you try to to make 2* π *r*t = ( π R^2)-( π r^2) , you will not get the same answer, and it will be a difference of over 10%... Please clarify if you can..
@introductoryengineeringmec9114
6 жыл бұрын
You are correct that a more precise value for the radius is at the center of the vessel wall. However, for thin-walled pressure vessels (t/r
@fera5165
6 жыл бұрын
Thank you for the answer. That should be specified in the book.
@headlinmei979
3 жыл бұрын
Thank you for your sharing, it is worth learning and reference, I hope to have the opportunity to exchange and cooperation with you
@emmar1131
6 жыл бұрын
What is radial stress?
@introductoryengineeringmec9114
6 жыл бұрын
Radial stress is the normal stress (sigma) acting through the tank wall from inside to outside in the direction perpendicular to both the hoop and axial stresses. The radial stress near the inside of the wall thickness, adjacent to the pressurized fluid, is equal to the internal gauge pressure. The radial stress near the outside of the tank wall is equal to the pressure on the outside of the tank (zero gauge pressure).
@bensonkwok951
3 жыл бұрын
@@introductoryengineeringmec9114 Why can we ignore the radial stress for thin walled cylinders? (Sorry this may be a silly question)
@tajbhiullhaque6032
4 жыл бұрын
sir why the resistance force is only from the cut surface, not from the curved area?
@introductoryengineeringmec9114
4 жыл бұрын
The theoretical cut passes through the pressurized fluid inside the tank. The fluid pressure acts normal to the cut surface.
@tajbhiullhaque6032
4 жыл бұрын
@@introductoryengineeringmec9114 Sir, in between the cut surface, in the hoop stress, we calculate the pressure force in the curved area as PLD. why dont we calculate the resistance in the PLD surface? plz answer my question sir.
@introductoryengineeringmec9114
4 жыл бұрын
@@tajbhiullhaque6032, I apologize, I may not understand the question. Only the balancing forces that appear on the surface of the cut are included: the force from the pressurized fluid and the hoop forces in the tank wall.
@tajbhiullhaque6032
4 жыл бұрын
@@introductoryengineeringmec9114 Sir you got my question now. why the balancing force is only the from the cut surface? i think i have some less understanding in the statics.
@introductoryengineeringmec9114
4 жыл бұрын
@@tajbhiullhaque6032 In a static structure, all forces acting on the structure are balanced. The same is true for any cut section, all forces (internal and external) are balanced. In the cut section of the tank, the only forces on the section are the forces from the pressurized fluid and the hoop forces in the wall. Gravity effects are neglected here since they are typically insignificant.
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