p16 and p17 have a typo. it should not be fervos but foveros.
@user-oy4qs1xo5u
11 ай бұрын
OOPS, Mybad!
@user-oy4qs1xo5u
11 ай бұрын
I also hate those names (does not make any sense and therefore difficult to remember) Check out the story below how Intel name their products. It's not as simple as you think. computerinfobits.com/why-are-intel-processors-named-after-lakes/
@mizunommjp
11 ай бұрын
thank you for providing the video that is very informative. you presented two equations: y(A)= (1+A*0.223/2)^-2 y(A)= (1+A*1.15/2)^-2 what are the differences in those two equations?
@user-oy4qs1xo5u
11 ай бұрын
WOW, you caught me. One of them could be misleading. Please check my video about how I came out with the formula (p.14) kzitem.info/news/bejne/1XqdrWSiiGOXhmk
@mizunommjp
11 ай бұрын
@@user-oy4qs1xo5u Thank you for your response. I have watched the video and this one as well. kzitem.info/news/bejne/wp-Gn6aCbmmSqYY It looks like the following equation is for the 0.44X0.44cm die: y(A)= (1+A*1.15/2)^-2 and the following equation is for the 1X1cm die: y(A)= (1+A*0.223/2)^-2 What confuses me is that the x axis of the two graphs is the die size from 0 to 4 square cm. You came up with the two different equations because of different machines used at TSMC, correct? The 0.44X0.44cm die is made in machine A and the 10X10mm die is made in machine B so that you need to use two different yield equations, correct? The yield of the 0.44X0.44cm die at 3.5 square cm is 10%: y(A)= (1+A*1.15/2)^-2 The yield of the 1X1cm die at 3.5 square cm is 52%: y(A)= (1+A*0.223/2)^-2 What does these mean? The two graphs tell me that a larger die size has better yield.
@user-oy4qs1xo5u
11 ай бұрын
@@mizunommjp exactly, thanks for the reminding. The question is not that critical。 It's the trend that really matters.
@mizunommjp
11 ай бұрын
@@user-oy4qs1xo5u My understanding of the current semiconductor industry's trend is chiplet that avoids larger dies due to the die cost and yield loss. Your presentation has two equations that shows a larger die has better yield that seems against the indusctry's trend.
@user-oy4qs1xo5u
11 ай бұрын
@@mizunommjp The two equations should show trend with smaller yield for larger dies, as those in p.21.
Пікірлер: 18