Dave, because of you i did 32 vids out of 165 in 2 days. and i remember everything even tho some things were new to me. your way of explaining things is amazing.
@kripashankarshukla4073
7 жыл бұрын
I asked you many questions and you answered to all of these in 1 or 2 hours.You are a real genius. I am your very big fan!!!!!!!!
@elizaerfanelle
Жыл бұрын
Nothing ever feels better than getting the answers right at the end of the video
@jen-hf3wh
6 жыл бұрын
Thank you man, you helped so much for the exams
@abdullahalshamsi2971
4 жыл бұрын
I really appreciate you how teach us you are the best and I thank you
Thank you dude we always need people like you on the planet
@randomrom747
3 жыл бұрын
This was really simple, thank you
@jamacianv1ncecuh882
4 жыл бұрын
Thanks professor Dave
@martinsbenedict3388
2 жыл бұрын
Professor Dave ..I don't really understand how ur 4×^3 turned to 0×^4 can u explain pls
@daniloguilherme8148
5 ай бұрын
I've just found out it's simpler to distribute the negative sign over the second expression in a subtraction first. After that just sum them up.
@oliviahall6398
2 жыл бұрын
thanks professor dave! u always slayy
@dontstealmydiamondsv3156
3 жыл бұрын
Thanks again
@rosiecesareo8092
Жыл бұрын
How do you do it if you have a different number of terms on each side of the +/- sign? Like how would you stack them then?
@carultch
8 ай бұрын
If you have a different number of terms, that means that you have hidden terms with a de-facto coefficient of zero. Terms that do show up, without a written coefficient, have an implied coefficient of 1. As an example: (2*x^3 + 6*x - 1) + (x^2 - 5*x + 6) The first group of terms is a cubic, and "should" have four terms, but one of them is missing. The second group of terms has an implied coefficient of 1, on the x^2 term, and is missing its x^3 term. This means, if we rewrite it with all the implied coefficients, we get: (2*x^3 + 0*x^2 + 6*x - 1) + (0*x^3 + 1*x^2 - 5*x + 6) Now, simply add up the coefficients on corresponding terms: (2 + 0)*x^3 + (0 + 1)*x^2 + (6 - 5)*x + (6 - 1) After carrying out the addition, it becomes: 2*x^3 + x^2 + x + 5
@sadraqalandar
11 ай бұрын
You are the best Great job
@tGoldenPhoenix
3 жыл бұрын
Thank you
@tGoldenPhoenix
2 жыл бұрын
Done this lesson.
@MojisolaObayan
2 ай бұрын
Thanks brotha
@osac7587
3 жыл бұрын
This video helped me a lot but not I have equation with xy! EXAMPLE : (4x^2+ 3xy - y2) + (x^2 - 8xy - 2y^2)
professor dave one small doubt while we doing additions or subtractions we always take from the righthand side but why you have taken the lefthand side
@slickyy21
Жыл бұрын
Maybe bcoz that thing doesn't matter in polynomials-----you can do it from anywhere,but I'll recommend doing it from right hand side for avoiding errors👍
@yerramchettiparijatha3639
Жыл бұрын
@@slickyy21Thanks For the Information
@empyrean-jamelgreaves8034
Жыл бұрын
389 +983 Go from the right. Hundreds, tens, ones. 300+900 80+80 9+3 Same for subtraction. You know. In the direction we read and have done for thousands of years??? Give me any problem into trillions and using this method I’ll beat a phd mathematician using traditional method of carrying the 1s😂😂😂 100% of the time.
@Sussyslvt
Жыл бұрын
thanks!
@mayurwahane
Жыл бұрын
Best sessions
@coolgirlph1142
6 жыл бұрын
i need a word problem of adding and subtracting polynomials
@carultch
8 ай бұрын
A 1 meter cantilever beam, carries a uniform load of 1 kN/m, and a point load at the end of 1 kN. When only the point load is applied, the beam takes the shape of: y_pl(x) = 4*x^2 * (x - 3) When only the uniform load is applied, the beam takes the shape: y_ul (x) = -x^2*(x^2 - 4*x + 6) For each of the above, x is the position along the beam's length with units of meters, and each y-function has the units of millimeters. Find the equation of the deflected shape of the beam, when both loads are applied at the same time.
This was easier than I thought Damn I lost 4 marks in my exams cause of these
@brookszablan3318
3 жыл бұрын
Amen
@yukinocodm131
Ай бұрын
I was now addicted into math
@pigmaster911
2 жыл бұрын
Underrated tbh
@putraswarga608
Жыл бұрын
Finally, i can do it right
@lolabrowning3045
8 ай бұрын
the way this still makes absolutely no sense to me
@ksinger1617
Жыл бұрын
How is the last qstion x^3 - -5x^2 is x^3 Professor plz explain me
@harshita3243
Жыл бұрын
We have x³ ...and we don't have any variable in the other side with 3 as a power... So we... Leave it as if is (x³) Also we don't have ... 2 as a power in the l. H. S ...as in r. H. S. (5x² ) so we leave it as it is.. That's why the in the answer... It is X³ + 5x²
@ksinger1617
Жыл бұрын
@@harshita3243 Thank you very much 😊.I was stucked on that question...Thanks for helping me 😀.
@harshita3243
Жыл бұрын
@@ksinger1617 no worries! I thought I am too late for replying now... But I did anyways 😂
@chickenfry7025
2 жыл бұрын
I’m her for nti work g
@voxicwaste
2 жыл бұрын
Cramming for STAAR
@osac7587
3 жыл бұрын
Please explain I need help 😭😭😭
@mamadwali4278
2 ай бұрын
❤❤❤
@yassenahmed263
Жыл бұрын
how did u got 13
@putraswarga608
Жыл бұрын
Because positive minus negative is the same as positive plus positive
Пікірлер: 54