In this video we calculate precisely how many possibilities there are for each type of poker hand with a little help from the binomial coefficient n choose k.
Great video, well explained, a shame I had to spend so much time finding it.
@mathaha2922
5 ай бұрын
Thanks! And sorry it took so long to find!
@coderassistant
10 ай бұрын
Good explained, thank you. I love mathematic too
@mathaha2922
10 ай бұрын
Glad to hear it!
@DonMattoncino
2 жыл бұрын
Wow! Interesting insight to the game of poker. I never looked at it like this. What’s the probability of the royal flush?
@mathaha2922
2 жыл бұрын
Good question! There are exactly four royal straight flushes (one for each of the four suits), so the probability would be exactly 4/2,598,960. In other words, you have a 0.000153908% chance of being dealt such a five-card hand.
@johnwaugh8035
8 ай бұрын
This is a pretty interesting video and I like the way the maths behind the chosen combinations is explained intuitively. But the sound is terrible. You have evidently invested in a big microphone so please turn it up - exponentially. (m, v)! ^ (m, v)! = Microphone Volume! x Microphone Volume!.
@mathaha2922
8 ай бұрын
Thanks for the tip!
@jungwisely8725
Жыл бұрын
Nice Video
@mathaha2922
Жыл бұрын
Thanks!
@nynthes
11 ай бұрын
hii, could you do a video on 7 card poker (texas holdem)? im struggling to figure out how to calculate the probabilities
@mathaha2922
11 ай бұрын
Thanks for your comment and the suggestion. Do remember that even in Texas Hold 'em there are exactly 5 cards that make up your final hand.
@tonychopper3751
Жыл бұрын
I think I am misunderstanding. I am confused on the straight flush 10 choose 1. You explained that you cannot start a straight above a 10 with jack and queen because it does not go that far, but you can still have a Q, J, T, 9, 8 straight flush. Should it not just be 13 choose 1, 4 choose 1, and then subtract 4 to account for the royal flush possibilities? So 48 Possibilities of a Straight flush?
@mathaha2922
Жыл бұрын
Good question! The answer is that we don't want to double count. 8,9,10,J,Q is the same hand as Q,J,10,9,8. So it's enough to just consider what the lowest card is. If we wanted, we could also just consider the highest card. Or just the middle card, etc. Hope that helps!
@tonychopper3751
Жыл бұрын
@@mathaha2922 Ohh I see, thank you so much for the response. Very helpful.
@jeremyhannah283
Жыл бұрын
Good video, but shouldn't the number of conbinations for a straight be 9 choose 1? 10 choose 1 works for a 4 hand deck, but I think 9 is more appropriate with 5 cards. Unless you are treating ace as high and low?
@mathaha2922
Жыл бұрын
Thanks for the question. I would say 10 choose 1 because there are 10 cards that can function as the bottom (or top, or middle, etc.) of a straight and we must choose one of them. (And yes, the Ace can be high or low.)
@sven9487
Жыл бұрын
How do i convert these probabilities to 8 hand poker?
@mathaha2922
Жыл бұрын
Good question. I don't know the rules to that game. But the principles remain the same for computing the probabilities.
@patricksutton4662
Жыл бұрын
For straight flush, wouldn't it be 9 choose 1 because royal flush is its own hand?
@mathaha2922
Жыл бұрын
A royal [straight] flash -- as I treat it here -- is simply the highest form of a straight flush.
@patricksutton4662
Жыл бұрын
@@mathaha2922 Oh, okay. I see what you did.
@Y7Y01
4 ай бұрын
Hey! I wonder if you can clarify why you chose (10 1) while we need 5 cards. it was in minute 4:52 Thanks
@mathaha2922
4 ай бұрын
Because if you don't consider the suit, there are exactly 10 different straights: A2345, 23456, 34567, 45678, 56789, etc. It is true that we need 5 cards, but once we have chosen, for example, the lowest one, the others are already clear. Hope that helps.
@SweetPlain
4 ай бұрын
@mathaha2922 shouldn't it be 9C1? A2345, 23456, 34567, 45678, 56789, 678910, 78910JQ, 8910JQ, 910JQK
@prob_io7299
10 ай бұрын
You speak too silently, increase the volume of your videos after you make them please
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