Please make another video on how to find power of powered roller conveyor . In which every roller is powered by chain drive.
@AnilKumar-iz7ic
4 жыл бұрын
Try to do it in metric unit .
@AnilKumar-iz7ic
4 жыл бұрын
This was really best and easy calculation to understand power
@onearyf1641
Жыл бұрын
How do we calculate the friction coefficient, do we refer to any table?
@tzb05
8 ай бұрын
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km length = 5 Km , Flow = 2500 to 3000 Mt/Hr , Route inclination= zero inclination, Width = 1200 mm , trough angle=30 how much electricity will be consumed in electrical motor
@rulmecacorporation4596
8 ай бұрын
Your question cannot be answered until you specify a belt speed at which the material will be carried. 1 watt = 1 newton-meter per second. Once you calculate the required tension (newtons) to pull the belt you must multiply that force by the desired belt speed (m/s). For example, a 5 km long horizontal conveyor carrying 3000mt/hr might have a belt speed of 5 m/s. If belt pull = 222 kilo newtons, then required electric power will be approximately 222 kN x 5 m/s = 1,110 kW.
@tzb05
8 ай бұрын
belt speed = 2.5m/s and material is dsand with density 1.55 Mt/M3 @@rulmecacorporation4596
@tzb05
8 ай бұрын
@@rulmecacorporation4596 here we are with full data I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)
@jaisinghmaurya
2 жыл бұрын
superb sir its great video
@rajeshkumar-wz4pv
3 жыл бұрын
Thanks a lot sir..
@rulmecacorporation4596
3 жыл бұрын
Most welcome
@ravindraathare3977
3 жыл бұрын
Please tell me bellow power and torque relation with all units, power = force x linear distance / time, and power = torque x angular velocity all units and its final value.
@rulmecacorporation4596
3 жыл бұрын
No problem. Here is a video which presents what you requested kzitem.info/news/bejne/0musmYFsk6WjpY4
@ganeshmr7625
3 жыл бұрын
thanks sir
@rulmecacorporation4596
3 жыл бұрын
It is my pleasure.
@wadib3eed7
2 жыл бұрын
You calculated the mechanical power is required, but does that mechanical power equal to the electrical power of the motor which will drive the belt ? in the case of calculation P=0.15KW , so in this case i will use an AC motor with a power at least of 0.15 KW to move all those weights ?
@rulmecacorporation4596
2 жыл бұрын
We have some videos explaining the relationship between calculated required mechanical power and suggested electrical power. Did you watch them yet?
@wadib3eed7
2 жыл бұрын
@@rulmecacorporation4596 No, i did not , i will search it .
@rulmecacorporation4596
2 жыл бұрын
@@wadib3eed7 watch this webinar please m.kzitem.info/news/bejne/0musmYFsk6WjpY4
@wadib3eed7
2 жыл бұрын
@@rulmecacorporation4596 Thank you so much for helping me.
@jacobthomas785
2 жыл бұрын
Hi, Belt pull required to accelerate = mg x coeff.of friction+ma.But you have not considered ma?Is it wrong?
@mikegawinski3450
2 жыл бұрын
Please define your terms. Thanks
@jacobthomas785
2 жыл бұрын
m=mass of the load(kg/m) +belt weight g=9.8 m/s2 a=acceleration
@mikegawinski3450
2 жыл бұрын
ma will always be negligible on short package conveyors which travel at 50 fpm +/-. However, if you need to accelerate very quickly to a high speed with a large load mass, then you should check it.
@Mrdovdberg
3 жыл бұрын
Thx! Why is the inertia not included?
@rulmecacorporation4596
3 жыл бұрын
To what inertia are you referring? If you are referring to start-up inertia of a fully-loaded belt, many designers of small conveyors assume that will be covered by the "start-up torque" of the drive motors. Design C motors, such as we supply, have a start-up torque of 200% of running torque. That is usually adequate to do the job for the few seconds it takes to start a fully loaded belt.
@travellervkvlog552
2 жыл бұрын
I think belt weight should be equal 2 times
@intanpratiwi4499
Жыл бұрын
3 lbs/feet. what parameters is that?
@mikegawinski3450
Жыл бұрын
3 lbs/ft = the weight per foot of the belt.
@intanpratiwi4499
Жыл бұрын
@@mikegawinski3450 how to calculate belt weight per foot ?
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