Man, you are seriously underrated. I am an A* scoring student but because I was unwell, I missed some crucial physics lessons. Your video truly enhanced my conceptual understanding.
@Cambridgein5minutes
3 жыл бұрын
Error correction: 24:50 The slide should say liquid -> gas instead
@nischalsurendara146
2 жыл бұрын
yeah i had doubt in it understood
@AliMurtaza-kc7kr
9 ай бұрын
Your make concepts very easy to understand unlike our teachers back in Asia.
@May-lq2ts
Жыл бұрын
Pliz do a video like this for space physics also .it’s very helpful
@tayybalatif6805
3 жыл бұрын
I have a test on thermal physics tomorrow and this helps allt. Keep it up
@tayybalatif6805
2 жыл бұрын
@@kareemwail4495oh ok.
@m_a_1062
2 жыл бұрын
@@kareemwail4495 where are you from???
@mhm8742
2 жыл бұрын
@@kareemwail4495 sameeeee
@nnfjd4926
Жыл бұрын
Same
@nnfjd4926
Жыл бұрын
@@kareemwail4495 same
@Woner181
4 ай бұрын
32.44 min of Cambridge
@Woner181
4 ай бұрын
😂😂😂😂😂❤❤relatable
@Woner181
4 ай бұрын
Nice boy
@britneyliyali2204
3 жыл бұрын
This really helps a lot when revising or studying It's explained in a way I can understand it better Thank you Happy to have found this channel 😊💕
@__erikaa
Жыл бұрын
best physics teacher right here
@tokyo7671
3 жыл бұрын
At 24:50, it should be liquid to gas
@currybon
3 жыл бұрын
THANK YOU FOR THIS
@premanandjain9442
2 жыл бұрын
can you publish a video for space physics unit for us.
@sunnypriyayadav2685
2 жыл бұрын
13:42 it should be 1jouls per gram
@feliperacing7146
3 жыл бұрын
At 7:30 is it freezing or melting point?
@sunnypriyayadav2685
2 жыл бұрын
it is both the freezing and the melting point . it will alway be the same through out the world not in the space !
@mesho3004
3 жыл бұрын
THANK YOU
@iIIvmi
3 жыл бұрын
at 21:50, how is the heat used only to break the bonds but the kinetic energy/heat doesn't increase? in order to break the bonds, the kinetic energy or temperature need to increase in order for collisions to occur and the particles to become spread out. I don't understand how the bonds would get broken if the kinetic energy isn't increasing. thank you for the great video btw!
@navysavy1684
3 жыл бұрын
i was honestly thinking the same thing, fellow learner (i dunno what i said it like that, ignore it) but ig the reason would be that, the temperature could be constant, but the substance is still gaining energy from it... like for example, you're heating... ehh something? and you put it on the stove on minimum (constant, it doesnt change through out the period), and you leave it for... like 4 hours! the thing you would be heating would be burning hot, or turned into liquid/gas! even doe the heat was constant. A constant heat is enough to break the attractive forces/bond of the substance! i have no idea if this is correct... lemme know if you know the correct answer. :,,,)
@akhilkommuru
3 жыл бұрын
As far as I recall, I think during the bond breaking phase, energy is only being used for that particular process. And once all the bonds are broken then the k.e. should start increasing. again not too sure (also a fellow learner), but if someone could confirm if this is the case - that’ll be appreciated
@Cambridgein5minutes
3 жыл бұрын
@@akhilkommuru that is correct :)
@nawhtetshwesinhlaing8653
2 жыл бұрын
this is so helpful. thank you.
@maryamfatima7569
3 жыл бұрын
THANKYOU SOOOOOOOOOOOOO F MUCHHHHHHHHHHHHHHHHHHH
@howto302
9 ай бұрын
Video not match name of channel
@tayybalatif6805
3 жыл бұрын
I did the formula at 19:06 and I get 42000j not 4200j so is it correct and if not so what have i done wrong
@sunnypriyayadav2685
2 жыл бұрын
see energy is 21000 and mass is 0.50 with the tempurature of 10* now the formula is E divided by tempurature multiplied by mass first you should do multiplication that is (0.50) (10) this gives you 5 now divide 21000 with 5 the answer is 4200 hope it help.
@courage6041
3 жыл бұрын
youre the best amigo
@seemariazkhan7353
2 жыл бұрын
Can u plz explain how a thermometer works
@sorbet237
2 жыл бұрын
The liquid in the bulb expands uniformly as temperature rises causing it to travel up the capillary tube.
@muoncollider
2 жыл бұрын
you are a god
@sigmagamingohio
5 ай бұрын
❤
@addonecomputer6863
2 жыл бұрын
Nice
@abdumannonmurodiy
3 жыл бұрын
Hey first of all thank you for video. Please how can we download these presentations from you?
@awegcwxgfd6953
2 жыл бұрын
I'm not sure if you need it now but he has a website with all of the notes
@addonecomputer6863
2 жыл бұрын
Hello 👋👋👋👋👋
@mariak1153
3 жыл бұрын
Where is ur first vid for thermal physics?
@anulinwume688
2 жыл бұрын
check his channel, the thumbnail is also thermal physics but look at the title carefully.
@Offical_Kelven
2 жыл бұрын
I found no confidence in your voice. This video was helpful but off. Well it's been up to 3yrs n I hope you've improved
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