dude thank you so much I was having a mental breakdown because of physics but you made it so much more simple
@maribelescaros5803
3 жыл бұрын
A reminder that 4 years ago you had a mental breakdown over physics. how does it feel now that it is over.
@dahstroyer
2 жыл бұрын
I'm currently going thorough the mental breakdown
@justinc.4558
2 жыл бұрын
@@dahstroyer mental breakdown club
@keronrampersad1021
Жыл бұрын
Now I’m having my mental breakdown currently
@zone-00
Жыл бұрын
@@keronrampersad1021 bro same, we have a test tmr. im sobbing i still dont know how to solve it
@cinechromefilms4045
9 ай бұрын
13 years later, this is still helpful. Thank you sir
@MovieTrim
9 жыл бұрын
Wow the quality and organization of his calculations as well as pace and verbal description of the problem beats even KHANA. Great quality content I'm subbed
@michaelkhalil7368
Жыл бұрын
I never write comments so when I do you know I mean this so sincerely. Physics has never ever made sense to me since middle and high school. Now in college I gotta get it so I don't fail these classes. This is the first time I've felt confident and actually understood even slightly what I was doing. So thank you Derek!!
@felixtira5245
10 жыл бұрын
Thank you Mr. Owen! I've been frustrated for hours LITERALLY. This is the best video out there! 10/10!
@superbaby0907
13 жыл бұрын
love the fact that its colourful! helps to clearify things a lot!
@abhisheksaini-lw8li
11 жыл бұрын
seriously, i think people like u deserve a great prize... ive physics exam tommorow and i didnt know anything... thanks very much
@itsjasminagain
10 жыл бұрын
Thank you! I've been having so much problems understanding this and I have my first exam tomorrow.. This helped so much!
@princesspat5239
3 жыл бұрын
Thank you so much Im doing my first year of biomed but i didnt learn much about physics in high school. I know theres projectile formulas but I've been trying to find videos where they use the kinematics one since that increases your understanding. Thank you so much for making these, it was very clear!
@derekowens
10 жыл бұрын
Yes, that's correct. That's because for a projectile, there is no acceleration horizontally, so the velocity is the same the entire time, and you can find it with the equation x/t.
@Vlb361
11 жыл бұрын
Thank you so much for making these videos! They made studying for my exam so much easier. :)
@aaravmaheshwari3733
2 жыл бұрын
This literally just saved my whole grade, thank you
@SBchampsXLII
11 жыл бұрын
Thank you so much for uploading these videos. You explain things so well, and your visuals are amazing.
@derekowens
12 жыл бұрын
@omar3211 Acceleration near the earth's surface, due to gravity, is 9.8 m/s^2 (or very close to that). That's basically a constant (if you're on earth).
@derekowens
12 жыл бұрын
@Ell4Sh Yes, that approach would also work. There are typically multiple ways to set up a problem, all of which should give the same final answer. I set it up with 0 a the top because all of the motion and the acceleration are downward, in this problem, and setting it up this way makes all the displacement, velocity, and acceleration numbers positive. The other approach is fine, though.
@Denseworldproduction
13 жыл бұрын
thanks WOW! your 8 min tutorial rlly helped me do a problem that wasnt even the same as this, so basically you improved my understanding :)
@derekowens
14 жыл бұрын
I typically use v_0 for the initial velocity. That's v with a zero in the subscript position. It basically means "velocity at time zero" or "velocity when t=0". Then I use v by itself for velocity at some later time. Using u works also, though. Good notation definitely helps, but it's not as important as the concept.
@derekowens
12 жыл бұрын
@SohrabR93 It depends on how the problem is set up. Typically a problem can be set up with up being the positive direction (in which case gravity is -9.8), or with down being positive (in which case gravity is +9.8). It can be done either way, as long as you pick one way and stick with it consistently through the whole problem.
@lizrey63
11 жыл бұрын
omg you are soooooo helpful!!!!!!! im so glad i found your videos! thanks for taking the time to make these. you dont understand how helpful these are. thank you!
@TheCarlosfgm91
14 жыл бұрын
Awesome! thanks for the help! please keep on making physics videos, they're a ton of help! 5stars!
@derekowens
13 жыл бұрын
@alkhor999 I typically use x to indicate the horizontal position and y to indicate the vertical position.
@SuperMmmm33
12 жыл бұрын
you are amazing!, ths tutorial helped me with a problem that i've been struggling with for days! :)
@derekowens
12 жыл бұрын
@HairtUB It depends on how the problem is set up. If it is set up consistently, then y and a will both have the same sign in that equation, and there would be no negative square root.
@mattmeyer8141
4 жыл бұрын
Derek, Nice job explaining this problem!!!! What software/hardware do you use for your chaulboard?
@micheleloga2099
10 жыл бұрын
Absolutely AMAZING! I can't get my Physics teacher to explain any of this to me and my book is too confusing to help me with these kind of problems. Thank you so much for doing this video! I understand it so much more now.
@gggg-gu2hl
Жыл бұрын
Been 9 years.. how did you do?
@isome9123
8 жыл бұрын
Great vid as always! I have a question however (hope it's not too foolish): Why do we use the same t in the horizontal equation as the one we used in the vertical one? Maybe I interpret it wrong but doing so wouldn't it mean that it takes the same amount of time to move in a horizontal and vertical way independently? And if so, how do we know it does this? Hopefully I managed to explain my misunderstading well.
@derekowens
12 жыл бұрын
@MsBiebaholic Yes, that is correct. The two equations you mention are actually the same, since horizontally there is no acceleration so the 1/2 a t^2 term reduces to zero. The larger equation simply reduces to the smaller in this case. I don't know an any easy way to memorize the equations of motion, but even if it's just by brute force or practicing, memorizing them is certainly a good idea.
@ItsChenice
8 жыл бұрын
You sir, are a life saver!
@derekowens
12 жыл бұрын
@804YankeeFan Yes, that's basically correct. When I throw a ball into the air, the rotation of the earth does not cause the ball to be "left behind".
@derekowens
12 жыл бұрын
@lidyaFACE There are usually two (or more) ways to set up a problem. The acc. can be either positive or negative, depending on how it is set up. For a projectile, though, the horizontal and vertical motions are always independent, and the acceleration of gravity only applies to the vertical motion. For a projectile, the horizontal acceleration will be zero.
@scraggsds
9 жыл бұрын
Thanks for posting this. Helped me understand it easier and made my life a lot easier.
@derekowens
11 жыл бұрын
The key here is to distinguish between the vertical and the horizontal. Once the bomb is released, it is a projectile, and there is no horizontal acceleration. There is vertical acceleration, though: gravity is pulling it down. It also gets more complicated when you include air resistance. Air resistance introduces some horizontal and vertical forces, which depend on the speed.
@804YankeeFan
12 жыл бұрын
@derekowens So, I have a last question I was wandering about. So are satellites orbiting the sun with the Earth while they are orbiting the Earth? Does this cause the Earth to be an inertial reference frame when calculating its orbit?
@mdewolfe33
7 жыл бұрын
Got it perfectly right! Thank you
@FachrinabilPF
9 жыл бұрын
how could you determine the way of which should you firstly use horizontal or vertical ?
@804YankeeFan
12 жыл бұрын
@derekowens I was wandering If I drop a ball in the air, the air's bouyancy force is acting on me and accelerating me with the weight. Am I right? So why dont people consider the extra bouyancy force?
@FHO72
11 жыл бұрын
holy shit, i finally UNDERSTAND. Jesus christ. I am jumping with joy right now. Thank you for making sense. Thank you. Seriously.
@claymountain1300
10 жыл бұрын
this video saved my life!! got a test tomorrow morning, but I finally understand now!
@gggg-gu2hl
Жыл бұрын
Been 9 years how was the test? Did you graduate yet?
@wasb911
9 жыл бұрын
is it possible to find the speed if the vertical velocity wasn't 0 given the x and y distances only ?
@joshuabrucetaylor9897
11 жыл бұрын
I'm brushing up on my physics for the MCAT and these videos have been great. Thanks for uploading Derek, I really appreciate it :)
@RamanShrikant
2 жыл бұрын
how was mcat!
@gggg-gu2hl
Жыл бұрын
Been 9 years what did you do? How’s everything?
@derekowens
12 жыл бұрын
One of the key points of projectile motion is that the horizontal motion is independent from the vertical motion. There is no acceleration horizontally, but there is acceleration (downward) vertically. A bullet fired is accelerated horizontally by the gunpowder exploding behind it, but once it leaves the barrel then it is just coasting, under the influence of gravity alone (which is downward). While it is coasting, it is considered to be a projectile.
@user-dp6th8mu6v
9 жыл бұрын
What is the software and device do you use to draw this pictures?
@HienNguyen-jv1px
9 ай бұрын
thank you so much ! this was so easy to understand and it also makes sense!!!
@utuntupamed6224
3 жыл бұрын
Thanks man have finally made it in physics
@Star123Euro
12 жыл бұрын
@derekowens why when we take the horizontal the acceleration is zero? please tell me
@derekowens
12 жыл бұрын
@Star123Euro In this problem, the object is a projectile, which means its motion influenced by gravity only. And gravity pulls straight down. The force of gravity does not have any horizontal component, so the horizontal acceleration is zero as long as it is in free flight.
@currentlyindisguise8322
8 жыл бұрын
I m indian and from half an hour I was dealing with the concept that u made me understand in few mins thanks a lot
@PhilberthBundo
3 ай бұрын
It's very helpful, thankyou for the video
@supajustin4285
7 жыл бұрын
This is very helpful for my AP class. Thanks so much
@redcamel7965
8 жыл бұрын
thank you very much for this great video, it really helped me all .
@colorgreens
14 жыл бұрын
your hand writing is beautiful! :)
@RandomBoggoDude
9 жыл бұрын
Nice vid, somewhere there is either a mistake in my books or with my interpretation of the formula. If I use the formula "delta x =[(Vf+Vo)/2*delta t]" i get exactly double your answer. That is if I use Vf as 0. Is using Vf as 0 wrong while working with projectiles or is the derivative formula I'm using wrong?
@duanoor3061
8 жыл бұрын
thank you very much for this great video, it really helped me allot
@derekowens
11 жыл бұрын
At the start of a problem, you need to choose which direction you will call positive. You can call up positive and down negative, or you can call down positive and up negative. Pick one, and just stick with it through the whole problem. If up is positive, then the acceleration due to gravity is negative. If down is the positive direction, then the acceleration due to gravity is positive.
@804YankeeFan
12 жыл бұрын
Does the projectile objects have the inertia of the rotation speed of the earth?
@kareemkourouma3976
11 жыл бұрын
why is the intial velocity horizontally 0? wouldnt it need some velocity once it reached the edge of the cliff to keep moving horizontally.
@user-mm6vm2kc6p
Жыл бұрын
Why the the acceleration is not negative if it's going horizontally?
@samjib8284
10 жыл бұрын
Mr Owen, how do I contact you. My daughter wants to take some classes with you. Please let me know. Thanks.
@rdbanks2823
7 жыл бұрын
Derek Owens - Thank you so much! Resolving in the Y direction makes so much sense - then you can find the time it would take to drop. This idea links nicely to your last video!!
@Applecheria
14 жыл бұрын
I am at the verge of failing Physics class. Chemistry was a mess and I do not want to Jeopardize my GPA! Thank you so much for your help!
@Purpleye815
11 жыл бұрын
Thank you for posting this is helping me study for exams
@shadowfox6431
11 жыл бұрын
Hello, I would like to ask something, say that the projectile is a bomb released from a fighter plane going at a certain speed, is the acceleration of the object still zero, or is it the acceleration?
@craziecat100
10 жыл бұрын
do you use the equation d=vit+1/2at^2
@jojosh234
13 жыл бұрын
@jojosh234 the vertical distance should be at negative because it's going down to Y axis,
@Jayankesha
10 жыл бұрын
for the horizontal can u do velocity=distance/time does it still work?
@derekowens
11 жыл бұрын
I understand your reasoning. The problem is how theta is defined. In this context, theta is the angle measured relative to horizontal. The equations Vx = V cos Θ Vy = V sin Θ assume that theta is the angle measured relative to the horizontal. If you called theta the angle relative to vertical, you could still solve the problem, but the sine and cosine would get switched. Hope that helps! Derek Owens
@derekowens
12 жыл бұрын
@804YankeeFan The buoyant force is very tiny, and is generally considered small enough to ignore. One could, though, include both the buoyant force and the air resistance in the calculations. The calculations get beyond the scope of this course, though.
@stevetari3990
10 жыл бұрын
perfect explanation, i am sure i've gained something from it....
@derekowens
13 жыл бұрын
@anoorcc Not in this case. If it were a symmetrical parabola, going up and then back down, then we could double the t to find the whole time. In this case, though, we only have half of such a parabola.
@riceisnice8643
Жыл бұрын
thanks for helping me I was on the verge of crying
@EmmanuelGINI-vj8qf
10 ай бұрын
Bro your teachings are very smart and easy Thank you very much
@ArrowedDragon
10 жыл бұрын
THANK YOU! THE OTHER VIDEOS I'VE SEEN SUCK!
@Palmar3s
13 жыл бұрын
@juschecknin because gravity doesn't affect it because it's going horizontal, that is why there is no horizontal acceleration, but if it's vertical then yes, because gravity pulls down, gravity doesn't work from side to side (horizontal) therefore there is no acceleration. As far I have seen, every time acceleration is mentioned I think of gravity working on the vertical axis, pulling down, never it acts sideways, unless there is another force of acceleration. I think it goes like that :/
@slamreaper2269
4 жыл бұрын
if the origin is 0 then why horizontal displacement isn't -100m?
@happyports2621
8 жыл бұрын
THanks man!!!! It helps a lot dude
@thepunisher1951
8 жыл бұрын
Thank you very much. It helps me a lot.
@lylass1232
10 жыл бұрын
Good video. It help me to understand better in this chapter. Good job!
@anuurcc35
13 жыл бұрын
@ derekowens; When finding the initial horizontal velocity, should time be doubled @ 7:21 so that it account for the whole horizontal time. So instead of 4.52 should it be 9.04. Can anybody else see what I'm talking about as well?
@thepunisher1951
8 жыл бұрын
Thank you very much. It helps me a lot
@omsnet63
9 жыл бұрын
My only doubt is that if acceleration horizontally is zero the projectile should keep moving in the same direction (if its velocity is constant ) then why does it stop? ( i m sorry if its 2 obvious)
@Ell4Sh
12 жыл бұрын
im really bad at physics im watching this to get a better understanding obviously. i would make the top of the cliff 100m and the bottom 0m.. id also make my a -9.8 m/s.. i guess what im asking is how do you lay it out that way?
@JaredReabow
11 жыл бұрын
Why did you not just use v^2-2aS=u^2 ? to find the horizontal
@rangiroa100
Жыл бұрын
Hi Derek. I got a question. An object fall to the earth at 9.8 meter per second. If the vertical distance is 100 meters, then 100 / 9.8 = 10.20 seconds. It would take 10.20 seconds for an object to fall 100 meters. Your calculation showed 4.52 seconds. Can you explain the discrepancy ?
@OmarSN93
11 жыл бұрын
thank you so much :) i solved it before you started solving it and my answer was the same as yours :D
@RonaldTani
Ай бұрын
Thank you job well done ✅
@masoncore3470
10 жыл бұрын
what s the software you use to draw...?
@lambosteve1000
10 жыл бұрын
idk if this is a dumb question but can someone anwser??. How do you know when to rearrange the equation???
@merlin88888
3 жыл бұрын
im just gonna leave this here... cuz im not too sure if everything required here is in the vid. 1. A ball rolls off a table that is 1.5 m high and lands on the floor, 4.0 m away from the table. a. How long is the ball in the air? b. With what horizontal velocity did the ball roll off the table? c. What is the vertical velocity of the ball just before it hits the floor? d. What is the horizontal velocity of the ball just before it hits the floor?
@thejavellanas
10 жыл бұрын
you explained very well. :)
@ChaosGamerNick
9 жыл бұрын
this video helped me so much thank you
@Cleopatra0629
2 жыл бұрын
I have the first problem as my assignment and im confused because the process and the labels used are different TT
@sawaimal612
8 жыл бұрын
why we use -g in projectile motion?
@earlcamblelover
13 жыл бұрын
What about when horizontal distance is not given ??
@lonogugeadult
13 жыл бұрын
@emmalainesmiles you'd use the equation y = yo + vo(t) + 1/2a(t^2) and plug in what you know for the vertical component to solve for t
@dixibeazz6390
Жыл бұрын
amazing
@gambitx24
13 жыл бұрын
you are very good.
@Sana-qo3tc
2 жыл бұрын
My goodness.....thank you very much
@Soccerstar7867
11 жыл бұрын
thanks man helps alot. How smart can you get? and are you like a physics teacher, or like a prof? thanks again helps a lot.
@LeonardATF
10 жыл бұрын
Thank you I couldn't understand until I watch this
@gggg-gu2hl
Жыл бұрын
Did you pass? It been 9 years
@avgrech
13 жыл бұрын
10x a million ma 2 morro i got a test aout thease and i was sick all week no idea what to do but now i got a clue 10x m* ur da best vry good explenation btw
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