If it wasn't for your videos, I would've never grasped the whole idea about projectile motion. You don't know how much help your videos have been to me! I am highly in debt and grateful! Thank You So much and Keep up the Enlightenment!
@FachrinabilPF
9 жыл бұрын
based on your all videos about projectile motion. I realised that you put either vertical/horizontal first on your working is because it depends on the time. If there is a time in the question, you would firstly use horizontal, vice versa.
@lindseyhughes
12 жыл бұрын
thank you so much for this! it's so confusing when my teacher does it but you explain it so well!
@michaelkraemerman2009
9 жыл бұрын
Your videos are incredible. You sir are a miracle worker. thank you very much
@leticiaaguirre8126
2 жыл бұрын
you're doing my professor's job for him. thank you
@derekowens
13 жыл бұрын
@DeanNickChase If you look closely you can see in the diagram that it is a stick horse, ridden by a stick figure. Stick horses (and stick figures) are two-dimensional, so they are very thin and extremely lightweight. This gives the horse a tremendous power-to-weight ratio, allowing him to make the jump that a big fat three-dimensional horse could not make.
@catherinsucalit975
9 жыл бұрын
Thanks a bunch its been long years since I was in physics
@KenKaneki-oy3kb
7 жыл бұрын
i love that drawing skills :D
@little0range
11 жыл бұрын
ur drawings make physics much more enjoyable :)
@mikemai8568
9 жыл бұрын
Great video, Derek. Thank you for breaking them down in steps.
@RobbyBoy167
7 жыл бұрын
100m??!!!! I need to get me that horsey!!!
@gr33nplastic
13 жыл бұрын
@derekowens as the previously mentioned teacher from TheJezza2, must say that I respect your work and clear explanations. I have commonly referenced your videos in my physics class for at home help. Keep doing the good "f x d x Cos(theta)"!
@babblingmonster1802
13 жыл бұрын
Its really saddening to see the view count of such a magnificent video...
@goshiluvarchie
11 жыл бұрын
Your videos are incredibly helpful! Thanks. :-)
@felixtira5245
10 жыл бұрын
Best video out there!
@mico9423
8 жыл бұрын
YOUR GREAT , IF U ARE MY PHYSICS TEACHER SWEAR TO GOD I PASSED WITH HONOR
@IrisVollmer
13 жыл бұрын
Ahhhh yeeeah! Bring it on exam 1. Thanks so much mista! :)
@kinstlerh97
11 жыл бұрын
wow, great job explaining! very helpful
@Yann1
8 жыл бұрын
your such a good teacher derek :D
@DaTurdburglar
13 жыл бұрын
Thanks for the vids! They really helped me alot. :D
@DannyDoomPink
12 жыл бұрын
Thanks for these amazing videos, now when i solve a problem i can actually say that i understand whats going on haha
@irwinisraeltomas7097
8 жыл бұрын
ok thanks derek for this video.
@koalakid3609
Жыл бұрын
This is intresting. VERY.
@kennysundiam
13 жыл бұрын
thank you very much sir!.keep it up :D you are a much better than my prof.haha
@tncreations1267
11 ай бұрын
thank you very much.
@lauratwilight1
13 жыл бұрын
This guy's drawing is awesome
@j.jcagney6522
9 жыл бұрын
Thank you so much.
@himorthem5406
Жыл бұрын
It works. Thank you
@EdwardCullensMayo
12 жыл бұрын
these videos are fucking awesome!! i'm gonna go ham on my test on monday!!
@emmanuelmaluba9653
3 жыл бұрын
This is awesome
@babakmahour
12 жыл бұрын
u got me!!!! good one thx
@derekowens
13 жыл бұрын
@H2daH acceleration is zero horizontally. This is always the case for projectiles because gravity always pulls down, and never exerts any force horizontally.
@albertcao96
11 жыл бұрын
Dude, you are the best
@malaklove464
10 жыл бұрын
thank you so much
@rubiksmaster301
5 жыл бұрын
The only reason I'm watching this is because it's a physics homework assignment.
@katehsu3642
3 жыл бұрын
Thank you 🙏
@user-wb1ko5uc4m
5 ай бұрын
Well done
@emmamercado9066
5 жыл бұрын
Thank you so much
@derekowens
13 жыл бұрын
@getrichquickideas Thinking from the start to the peak, which is only half of the flight, gives you a result of 2.5 seconds. This is half the total time, so the total time is five seconds.
@takumikanna5805
8 жыл бұрын
thank you!!!!!
@bloodisfuel9882
6 ай бұрын
hey there, I really appreciate your video. but at 3:25 I did not really understand much. Why would you make the time 2.5s? I know that at 2.5s that's when farmer bob and his horse reached maximum height, but why would you do that? Is there another way to get the initial vertical velocity here? thanks
@mercydelani7943
11 жыл бұрын
to find the initial velocity..can i use the parrelogram law/triangle law insead of pythogorus theorem
@webjeff2002
14 жыл бұрын
@emiri, thank you.
@derekowens
13 жыл бұрын
@jkoscak I prefer m/s, although m s^-1 is mathematically equivalent, and can fit neatly on one line when typing. I think the algebra is more clear, though, with it written as a fraction.
@jensons88
12 жыл бұрын
the lesson here is clear. on my channel is a projectile motion demo that you can watch. it's actually a program that you can download from softpedia
@TheJezza2
13 жыл бұрын
Whats up Mr.Butler's class!!!
@tahasilat7394
6 жыл бұрын
what software do you use?
@Gsmstfreshie
13 жыл бұрын
what if it asks for the landing velocity? would that just be the horizontal velocity, which is 20m/s? please answer my question, thank you!
@vj692
7 жыл бұрын
great
@funfofacts
9 ай бұрын
im here 14 years later
@derekowens
9 ай бұрын
And I'm still here, too!
@MisterBazarao
12 жыл бұрын
Isnt it easier to use U for initial velocity instead of V zero?
@getrichquickideas
13 жыл бұрын
Why is the time for horizontal (5sec) different from you time for the verticle (2.5 sec) ?
@remargonzaga3426
Жыл бұрын
i'm sorry. but, shouldn't be the initial velocity for x Vocos(theta)? thus, Vo=100m/(5s cos(theta))?
@miguellserrano3312
2 жыл бұрын
yo, i can see u r a good drawer haha
@xPinoyTribal
8 жыл бұрын
what is the reason we should assume that there is no horizontal acceleration? WHat if you jump from a stop? there would be both horizontal and veritcal acceleration
@derekowens
8 жыл бұрын
+xPinoyTribal Right, I see what you are saying. While you are jumping, pushing with your legs, there is definitely horizontal as well as vertical acceleration. Once you are airborne, however, coasting and out of contact with the ground, then at that point you are properly considered a projectile, and the only acceleration is the downward acceleration of gravity (assuming that we ignore air resistance).
@exogendesign4582
8 жыл бұрын
+xPinoyTribal pre hehe, kaya walang horinzontal ang acceleration, kasi unbalance ang force sa x-direction(horizontal) dahil narin sa air resistance, may ang acceleration sa Y vertical acceleration dahil constant at uniform ang force, at ang tawag don gravitational force 9.81m/s so dahil nag rereact lang ang gravity sa vertical , ang Y lang may acceleration kasi nag babago ang acceleration dpende sa time at distance, habang constant palagi ang horizontal, gets mo po ?> hehehe
@mickyadams8502
11 жыл бұрын
why dont you use 1/2 as often found in the formula 1/2at squared. When you calculate V zero
@monkieful
12 жыл бұрын
Bravo this video is very good keep up the good work.
@jkoscak
13 жыл бұрын
m/s or ms-1 ? what do you like better? :p
@heavenz94
11 жыл бұрын
thnks
@H2daH
13 жыл бұрын
why is (a)=0 ? in the first horizontal eqaution
@smileinc
12 жыл бұрын
Doesn't tan^-1(24.5/20)= 56.4 degrees?
@anajo240
8 жыл бұрын
Would you explain why in vertical initial velocity, v=0? Great video. Thanks
@Nuns341
5 жыл бұрын
this is probably too late but here lol when a object travels in a parabolic path, there comes a time ,right before when the object starts going down, the object only has horizontal force acting on it as the vertical force in that very instance is zero(the object goes up and when its done going up, in that very moment the final velocity is 0), and since its a parabola that means it took 2.5 seconds to go up and 2.5 to go down
@Rittiuu
10 күн бұрын
Because v zero is from theta angle so vx will v cos thata I think you made mistake
@boss2dawerld750
3 жыл бұрын
i didn’t consider the “start from peak” part for the vertical component solving, but i still got 24.5 seconds as the answer,,, is that alright?? THANK YOUU
@boss2dawerld750
3 жыл бұрын
oh wow didn’t notice this video was posted 11 years ago already oh wow
@derekowens
3 жыл бұрын
Yes, there are other ways to solve it. You can consider the motion from start to finish, and as long you use the correct initial and final velocity you should get the same answer for the time.
@derekowens
3 жыл бұрын
@@boss2dawerld750 11 years, and I'm still here! Lots to be thankful for.
@adnankamal3697
Жыл бұрын
@@derekowens since the flight time is 5 sec which means at t equal 5 they reached the ground doesn't that mean that at t equal 5 the vertical velocity equal 0?
@derekowens
Жыл бұрын
@@adnankamal3697 t=5s is the end of the flight, so the velocity at t=5s is the impact velocity. Think of the final velocity as being the speed with which it hits.
@irwinisraeltomas7097
8 жыл бұрын
is the peak half of the total time?
@derekowens
8 жыл бұрын
+irwin israel Tomas Yes, but only if it starts and ends at the same height.
@webjeff2002
14 жыл бұрын
How did you get the number 9.8 m/^2?
@bloodisfuel9882
6 ай бұрын
because of gravity
@MarMONEY-wz4zl
11 ай бұрын
Can you lmk where the 9.8m2 come from
@derekowens
11 ай бұрын
9.8 m/s^2 is the acceleration due to gravity. At least that's the value near earth's surface. And since a lot of physics problems take place near earth's surface, that value shows up fairly often, so it's a good number to know for basic physics work.
@abridgetool
3 жыл бұрын
The problem is quite old. So the video is.
@hardcore2103
8 жыл бұрын
where did 9.8 m/s come from??
@perrycheng4876
7 жыл бұрын
vertical acceleration from gravity
@tutstorial8474
4 жыл бұрын
well here's another approach: let T = total time (start to peak, peak to...) T = 5s. R = 100m. ¢ = angle since T = 2Voy/g T = 2Vosin(¢)/g Vo = gT/2sin(¢) --------- eq1. Vo = (9.81)(5)/2sin(¢) x = Voxt ---------------------- eq2 100 = Vocos(¢)(5) Vo = 100/5cos(¢) equate e1 & eq 2 9.81(5)/2sin(¢) = 100/(5cos(¢)) sin(¢)/cos(¢) = 5(5)(9.81)/2(100) tan(¢) = {(5)(5)(9.81)/2(100)} ¢ = 50.81° substituting ¢ to either eq1 or eq.2 Vo = 31.6 m/s
@Haza-rp1cb
3 жыл бұрын
U did all that for no reply
@tutstorial8474
3 жыл бұрын
well, u replied thank you
@bloodisfuel9882
6 ай бұрын
wow! I am very impressed by your work. well done
@uchwuzhere
10 жыл бұрын
Can someone explain to me why he used inverse tangent?
@zebunnisachughtai
10 жыл бұрын
Tangent theta is the ratio of opposite over adjacent but we don't want tan theta we want theta so when we take tan to the other side of the equation we get tan inverse theta (oppo/adj). I hope that was helpful :)
@catherinsucalit975
9 жыл бұрын
Use the inverse tangent to determine angle in degrees and seconds
@uchwuzhere
9 жыл бұрын
Oh, I took this class in the summer, but thanks anyways guys.
@NatashaKN
Жыл бұрын
I'm watching this video in 2023
@derekowens
Жыл бұрын
👍
@smileinc
12 жыл бұрын
@smileinc oh nevermind, my calculator needed reseting. :(
@sizwemaseko5223
6 жыл бұрын
When your doing the vertical motion, why is time 2.5 seconds? Please answer...
@DangerFishing
5 жыл бұрын
Thats half of the time so the velocity in the y direction is changing from up to down which makes the velocity in the y-direction 0, which enables you to plug the numbers in to solve for the inital velocity of y.
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