POPULAR 👌 IIT Advanced 2009 Question | Trigonometric Functions Class 11 | JEE Advanced | #iit | #jee
About this Video -
In this video we have discussed a Very Popular Concept based Question of IIT JEE Advanced 2009 of Trigonometric Ratios and Identities Chapter. Asked in IIT JEE Advanced 2009, Paper-1 of Marks (+,4 -1). It is a very GOOD question based on fundamental concept. Here we will put our best to revise every aspect of the theory part related to the question. After seeing the video you will able to solve such problems very easily......
Question:
If sin^4x/2+(cos^4x )/3=1/5, then
(A) tan^2x=2/3 (B) sin^8x/8+(cos^8x )/27=1/125
(C) tan^2x=1/3 (D) sin^8x/8+(cos^8x )/27=2/125
Answer:
A, B [IIT Adv. 2009 Paper-1, Marks (+4, -1)]
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About this Channel -
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