01:25 - Intro and Review of Lecture 23 10:18 - Frequency Response of CB/CG Stages 27:10 - Example: Frequency Response of CG Stage with the P-MOS Current Source Load >> 35:33 - The Output Node - Taking Channel-Length Modulation into Account
@muratt6894
5 жыл бұрын
Thank You
@mnada72
3 жыл бұрын
Waiting eagerly for circuit theory I & II and the rest of the series.
@zinhaboussi
4 ай бұрын
01:29 Examples of High-Speed Circuits 04:08 Exploring high-speed circuits and their applications in real-life scenarios. 09:21 Challenges in transmitting high data rates 12:17 Understanding frequency response and resistor usage in common gate stage 18:29 Finding poles by inspection simplifies analysis of high-speed circuits 21:23 Understanding input and output poles in common base stage circuits. 27:46 Replacing resistor with current source for higher gain 31:09 Reduction of capacitances simplifies the circuit design 36:55 Understanding pole frequency in high-speed circuit analysis 39:38 Analysis of high-speed circuits with MOSFET source degeneration 45:37 Analysis of common-base/gate stages and finding pole frequencies. Crafted by Merlin AI.
@armature6675
Жыл бұрын
What about decomposing ro1 into input and output side according to Miller's Effect? Will the results for ω1, in and ω1, out be any different?
@inoth79
5 жыл бұрын
@41:50 i think it should be ro1 not ro2 at the mosfet M1 . Brilliant video !
@fettahyldz460
3 жыл бұрын
how do we find ro1?
@shivanshanand8818
3 жыл бұрын
@@fettahyldz460 1/(lambda*Id)
@himanshubharti3491
5 жыл бұрын
nice
@DemosthenesKar
6 ай бұрын
Can't we break ro2 using miller and then have a more accurate representation?
@AmrBinAas
4 ай бұрын
Miller itself is an approximation!
@PM-et6wz
5 жыл бұрын
Why didnt you add rpi in parallel with RE and 1/gm?
@tag1343
4 жыл бұрын
If you write the small signal model and calculate the input impedance(Vx/Ix) you will find out the it will be 1/gm. The reason is that Vx=-Vpi in the small signal model. So there is no rpi. It will be cancled out.
@avirathi9209
4 жыл бұрын
rpi is 1/gm
@konstantinoslagaros
2 жыл бұрын
@@avirathi9209 wtf bro? rpi is are no 1/gm
@adityatripathi02
Жыл бұрын
@@tag1343 You are right about Vx = -Vpi. However, Rpi does not get eliminated due to this reason. For simplicity if we ignore early effect in BJT(no Ro in the small signal model) and write a KCL at the emitter node for the common base topology. We would indeed find the impedance looking into the emitter to be Rpi||(1/gm). The reason it gets eliminated is because Rpi||(1/gm) = Rpi/(gmRpi + 1). gmRpi is the beta of the BJT which is assumed much greater than 1. The impedance would then just become Rpi/gmRpi which is just 1/gm cancelling Rpi.
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