One can use (-b/2a, f(-b/2a)), completing the square, graphing, derivative, and other methods for finding the vertex of a parabola. Here's one of many methods.
@Rayleigh593
Жыл бұрын
Bro i was about to say that 😢 but anyways
@RishavPlayz2007
Жыл бұрын
(-b/2a, -D/4a) where D is discriminant D=b²-4ac
@ryanmahadeo3132
Жыл бұрын
I remember studying parabola vertex
@jatingomber9141
Жыл бұрын
@@RishavPlayz2007 -D/4a
@matheusjahnke8643
Жыл бұрын
rewrite: ax²+bx+c as a(x+b/(2a))²+c-b²/(4a) The minimum(when a > 0... if a < 0 it is the maximum... and if a=0 things break since it is not a parabola) value is when x+b/(2a)=0
@HamhockandHemorrhoids
Жыл бұрын
This is my favorite math short channel of them all... this guy must be a great tutor. Keep teaching the world good sir
@mrhtutoring
Жыл бұрын
Will do! Thank you.
@umarfaruq3378
Жыл бұрын
@@mrhtutoring I don't speak English well but your shorts are very simple! As-Salyam from Caucasus Good luck!
@MotorCityGas
2 ай бұрын
On some real shit, I wholeheartedly love this fucking guy, he’s helped me out a lot during this Engineering process
@TheFeraligamr
Жыл бұрын
I like to set the derivative equal to zero to find x and then plug x back into the original to find the y coordinate
@_mark_3814
Жыл бұрын
@@Jack-hd3ov how would there be a pain to differentiate any quadratic? By definition quadratics are in the form ax^2 + bx + c and the derivative is simply 2ax + b? Much easier than finding roots in general
@3lackman761
Жыл бұрын
Same dy/dx = 2x-6 2x-6=0 X = 3
@matheusjahnke8643
Жыл бұрын
I mean, this is easier. But then you would have to know calculus. Not that it is some arcane knowledge. But, depending on what stage you are, you weren't taught calculus yet(... or ever). In Brazil, they teach you calculus at university. But this problem(finding the vertex of parabola) is given to people at high-school.
@MithilaMaati
11 ай бұрын
@@matheusjahnke8643 find the vertex is taught at the age of 15, or in 10th class in india
@matheusjahnke8643
11 ай бұрын
@@MithilaMaati that might be in the high school here... or the last year before high school. I also might have overestimated: finding a vertex of a parabola is slightly earlier.
@shiki7160
Жыл бұрын
If this good sir was my maths teacher I would've became Einstein by now
@dilipprajapati1402
Жыл бұрын
😅😅😅😅😊😊😂
@wileynicholson1682
Жыл бұрын
I told my grandson too study the rules and he will understand. He does great now.
@yurisich
Жыл бұрын
You know you're dealing with a teaching pro when comic sans gets used in the title of each problem.
@luisclementeortegasegovia8603
Жыл бұрын
Nice and clean! Thank you
@crustydustydinosaur4682
Жыл бұрын
OH MY GOD THIS HELPED SO MUCH THANK YOU!!!
@nicolagonzalez282
Жыл бұрын
I can't stop watching this guy.
@aneek1201
Жыл бұрын
Just put (-b/2a) for the x coordinate and {(4ac-b²)/4a} for the y coordinate when finding the vertex of a parabola.
@RBKJesusEC
Жыл бұрын
You can also just use (-b/2a) to find x coordinate and plug it into the function to find y
@tazguy371
Жыл бұрын
Exactly what I thought when I heard this - just find the axis of symmetry. Simple.
@danielsolomon6227
Жыл бұрын
I love this. One thing I would add to the graph is the y intercept.
@MJ-fk2tb
Жыл бұрын
Your videos are great! 👍 i would watch your maths lessons!
@andrasfarkas2198
Жыл бұрын
You could also complete the square, so x²-6x+5=x²-6x+9-4=(x-3)²-4 and its obvius from here on
@sIeepstudy
Жыл бұрын
i was thinking the same!
@stevendavis2122
Жыл бұрын
Obvious.
@blushadowcat
Ай бұрын
Thank you Sir 🙏 I’ve had to teach myself math this entire college semester. My professor spend 2hrs out of a 3hr45min lecture period teaching us this concept. Was certain I wouldn’t understand it for the final, then watched your video and it clicked instantly with everything I already knew. Much appreciated.
@somebody401
11 ай бұрын
Fantastic! So clear and straight to the point.
@deflmaokioo9941
Жыл бұрын
This makes perfect sense since you’re trying to find the mid point of the two points. I’ve always used the partial QF of -(b)/2(a) to solve this, but now I know another way.
@juanjosebelmontesanchez6258
Жыл бұрын
Now you can mess with your students by asking them the vertex of a parabola that doesn't cut the X axis in the test 😂. That would be definitely funny.
@gustavofurlani3055
Жыл бұрын
When you learn calculus, this becomes much easier, but knowing the basics is essential for learning quadratic equations. Nice video, im a brazilian guy.
@ApteacherNetTelanganaTeachers
Жыл бұрын
super
@limin2557
8 ай бұрын
Excellent inspirational teaching that broadens a learner's mind through human intuition. Easily Unlock a learner's dormant potential. Thanks
@francepri2415
Жыл бұрын
Surgically perfect👏👏👏
@CertainlyStoopid
Жыл бұрын
Just find the axis of symmetry using -b/2a, and plug it in for x
@cbseE9212
Жыл бұрын
Now that's how you make maths so easy. Thanks mister H for your service. Can we expect a video on differentiation, it would be very helpful. Thanks again. :)
@gwensimmons_gigi1629
Жыл бұрын
You do know it’s easier to find the y- value by substituting the x- value into the Intercept or factored form, right?!? (3-5)(3-1)= -2(2)=-4. So much easier to do mentally! 🎉❤
@annkumiko1736
6 ай бұрын
We haven't learned this yet in school, do u mind explaining why and how he transformed the equation to 0=(x-5)(x-1) ?
@timeonly1401
Жыл бұрын
Since you already have f(x) in factored form (x-5)(x-1), the easier way to get f(3) is to plug 3 into the factored form (3-5)(3-1) = (-2)(2) = -4. Why easier? The numbers are smaller, and you only have to keep track of two things at a time. 😊
@abdelhamidznifiri
Жыл бұрын
Thank you
@bornagainsaint1
Жыл бұрын
This guy is a genius !!! Math comes so easy for him !!! It takes someone who is really smart to solve these math problems !!!
@dbisht
Жыл бұрын
Thank you so much
@cyrusmorrow5629
Жыл бұрын
I like to put it into standard form but I’ve never thought to do it like this, nice
@rxb364
11 ай бұрын
Im 65 and enjoyed doing that un school. Now kids cant even do basic math forget algebra, calculus, trigonometry!!!
@maxhagenauer24
Жыл бұрын
2 best ways in my opinion: 1st way: Just use the formula that was made by the same way he did it. -b/2a for the x value and -b^2/4a + c for the y value where a, b, and c are 1, -6, and 5. -(-6)/2(1) = 3 (-(-6)^2)/4(1) + 5 = -4 2nd way: Take the derivative and set equal to 0. f(x) = x^2 - 6x + 5 f'(x) = 2x - 6 = 0 2x = 6 x = 3 3^2 - 6(3) + 5 = -4
@Diogenes-ty9yy
Жыл бұрын
Egad! This brings back nightmares from HS math 60-odd years ago. I can only wish I had 5% of this man's mathematical savvy. I really envy him.
@benbeaton5410
Жыл бұрын
Nice ive literally only ever completed the square but this is cool too
@TheEulerID
Жыл бұрын
I just took the first derivative with respect to x, set that to 0 and it gives me 3. Then just substitute that into the original equation which gives a value of -4 for y. Of course if you just take the general case for a parabola of y = ax^2 + bx + c then the first derivative is 2ax + b. Set that to 0 and you get 2ax=-b, so x=-b/2a. Substitute a=1, b=-6 and d=5 to get x and then that value into the original equation. Thus x=6/2=3 and y=3^2-6*3+5=-4. Also, that method works with a parabola that doesn't cut the x axis, such as y=x^2-6x+15 (x=3, y=6)...
@AKKIKUN3
6 ай бұрын
That was some on point explaination sir! Thanks a lot ❤
@marier.dimankontay8783
9 ай бұрын
u did it so much better and a much faster technique😭 im having my exams tomorrow in math about quadratic equations and functions and deriving qf's! i converted the sf to vertex form then I made table of values and graphed😆
@panagiotisathanasiou7918
Жыл бұрын
Good job as always
@arifyesehehehehhewahahahah3445
Жыл бұрын
Four coordinates needed to draw a graph: 1. x = 0 2. y = 0 -> two coordinates 3. y min/max
@murphyslaw5150
Жыл бұрын
You make concepts that seemed unintelligible to me in Secondary School seem as obvious as breathing. An exceptional talent for teach maths.
@mrhtutoring
Жыл бұрын
Thank you for the very comment. I appreciate it!
@ooprigyan
9 ай бұрын
Thank you sir
@susancheah5364
8 ай бұрын
You are a Maths genius!!!
@amogelangmohono360
8 ай бұрын
That's so simple and yet so smart😭
@somebody_33
Жыл бұрын
There are many other ways to find the vertex of this parabola, like: a. Remembering that the coordinates of the vertex are (-b/2a, f(-b/2a)) b. Converting the function into vertex form by completing the square c. Finding the derivative of the function, then setting it equal to zero to find the vertex
@gangakesavadas.
4 ай бұрын
Your videos are great!! Love from India ❤
@mrhtutoring
4 ай бұрын
Glad you like them!
@nateanami7065
2 ай бұрын
Thank u so much made it so much easier
@Likee466
Ай бұрын
I love how you look and the way you teach😊😊😊
@mrhtutoring
Ай бұрын
Thank you! 😃
@user-vs3oj1tz7t
3 ай бұрын
What if x^2 has a coefficient of more than one???
@ahsans5350
8 ай бұрын
Makes so much more sense 10+ years after calculus 😂
@tom_something
Жыл бұрын
I didn't think of this solution, so I wound up using calculus. Thanks!
@jordisimon1451
Жыл бұрын
it is much easier and faster by just simply taking the derivative and make it equal to 0 so 3x-6 = 0 => x = 3 and substitute in the function to get y, which is 3^2-6*3+5 which equals -4. So (3, -4). I just did that in my head even before he started writing on the board
@dovbarleib3256
Жыл бұрын
Completing the square is more deeply explanatory for understanding the actual shape of the curve, and it is actually quicker. Of course setting the first derivative = 0 is the quickest way to just finding the x coordinate.
@mrhtutoring
Жыл бұрын
I can't argue with your comment. However, the video was just to show another method.
@lalitapatidar1939
Жыл бұрын
Sir do you know about JEE Advance Exam conducted in India Please take questions from that exam also Thanks
@AlpineSportsinUtah
3 ай бұрын
I have a test tomorrow thanks man this helped a lot
@AlpineSportsinUtah
3 ай бұрын
You are amazing teacher my math teacher doesn’t actually teach us
@mrhtutoring
3 ай бұрын
Best of luck!
@Biboo_o
Ай бұрын
where can i meet u, I WANT TO SAY THANK YOU!!!!!!!!!!!
@Zephyr_197
Жыл бұрын
Just differentiate and set that equal to 0.
@rashidhamad1138
Жыл бұрын
Beautiful
@A1ex337
Жыл бұрын
its already in standard form just do (-b/2a, f(-b/2a))
@mrhtutoring
Жыл бұрын
Did you read the comment pinned at the top?
@agnieszkaszafarczyk8999
11 ай бұрын
This is the smartest Algebra teacher in the world
@AlamLotfi-md5up
4 ай бұрын
شكرا لك أستاذي الفاضل 😊❤
@pierrettebalazut9407
Жыл бұрын
Ok, j'ai compris. Je suis heureuse de voir que mes études ressortent petit à petit de l'oubli...et même j'apprends des choses que je n'avais jamais vu dans mes vieux cours.
@sudhakarbabu9940
2 ай бұрын
Brilliant 😮
@charlesthomas3367
Жыл бұрын
Good to see a blackboard. The world went to hell with greenboards and white grease pen boards!
@renaultpontiac2766
Жыл бұрын
Or you can try rearrange the equation to mimic the form (x-alpha)^2 + beta where alpha and beta are the coordinates of the vertex meaning x^2-6x+5= x^2-6x+9-4= (x-3)^2-4 Hence the point S(3;-4) is the vertex of this parabola
@johnshepapa9074
11 ай бұрын
Excellent
@raskreiak1467
Жыл бұрын
What is that hand speed? I could have probably understand if it was on paper but on board no no.
@Mori_mee
11 ай бұрын
Yeah i learned this is good for using factored form
@user-pp4cj6ul2n
7 ай бұрын
Superb
@Dictator4454
8 ай бұрын
Y+4=(x-3)^2 then compare with x2 =4ay
@salerio61
Жыл бұрын
I'd have gone straight to calculus
@IlhanOktay-to8gb
Жыл бұрын
👍👍👍
@christianmosquera9044
Жыл бұрын
Excellent video
@Lucas-gx8ic
Жыл бұрын
You can also do -b/2a. Idk why it works but it does
@mychaelsmith6874
Жыл бұрын
It works because the first term of the quadratic equation is -b/2a
@carultch
Жыл бұрын
This is why it works. In general, a function shifted horizontally h units to the right, and k units vertically, becomes f(x - h) + k. Write it in vertex form: y = a*(x - h)^2 + k Expand: y = a*(x^2 - 2*x*h + h^2) + k y = a*x^2 - 2*a*h*x + a*h^2 + k Map to the standard form coefficients: y = a*x^2 + b*x + c a = a b = -2*a*h c = a*h^2 + k And from your b-term, you can solve for h, the horizontal shift: h = -b/(2*a).
@alexsinclair5358
Жыл бұрын
It's easier imo to just use the derivative to get x f(x) = x^2 -6x +5 f'(x) = 2x -6 = 0 2x = 6 x = 3 y = f(3) = 3^2 -6*3 +5 y = 9 -18 +5 y = -4 Vertex = (3,-4)
@seekknowledge2010
11 ай бұрын
Needs to be define vertex. Most people don’t know what the meaning of vertex.
@sampreetsandhu7166
7 ай бұрын
I love you sir, wish you could be my tutor
@sardarbekomurbekov1030
Жыл бұрын
Y- intercept is (0, 5) directly from given quadratic expression.
@mrhtutoring
Жыл бұрын
Nice one. I would like to add that the scale for x and y axes are different. 😅
@younissumaling8744
Жыл бұрын
What the fk i was never taught this method this is way faster than the vertex formula damn
@ericday4505
Жыл бұрын
What kind of real life situation would this, finding the vertex, come into play? Engineering? Just wondering.
@mrhtutoring
Жыл бұрын
Maximizing profits,minimizing costs, dimensions of a fenced area...
@mategombas771
Жыл бұрын
Should cross the y axes at (0,5)
@21N3m
Жыл бұрын
İngilizce bilmesem de matematiğin dilinden anladığım için mutluyum sjsjjs
@xpert_thiefgaming6195
Жыл бұрын
❤
@Eren15232
9 ай бұрын
Thanks ❤
@ariasirp3235
9 ай бұрын
Te amo señor
@francescofragolino3509
Жыл бұрын
Genius
@yishaithegift9953
5 ай бұрын
I use parabolic curves in my artwork. But i never knew it was a math equation to show my work. I honestly don't have a clue as to what im seeing. I would like to understand this in case someone ask.
@A.Hisham86
Жыл бұрын
for x equal to zero f(0) equal to 5, so it cut the ordinate axe
@JohnAmbruz
11 ай бұрын
The best
@haletahmasbipoor5522
Жыл бұрын
🙏🙏
@vandanasoni4536
Жыл бұрын
Formula is (-b/2a,-D/4a).
@swet98_playz26
5 ай бұрын
Sir how can we find its p value
@snowwhite280
10 ай бұрын
How about general form to standard form sir
@albinjose8272
Жыл бұрын
Great
@spookimonke3598
7 ай бұрын
thanks
@ankur19852005
Жыл бұрын
Can use derivative, slope as 0
@jakobnielsen9580
Жыл бұрын
My problem with integral calculations, i have no picture, no sense of what im calculate. Then i got the understanding of how many calculate, the understanding of why many make strange mistankes.
@carultch
Жыл бұрын
Integrals wouldn't help you with this one. You'd need to use the opposite operation of derivatives. Looking for places where the derivative equals zero, is how you can solve for the turning points of functions in general. For a parabola, it's very simple to do. Drop each exponent by 1, and have each original exponent join its coefficient. Simple use of the power rule, d/dx k*x^n = k*n*x^(n-1). d/dx (x^2 - 6*x + 5) = 2*x - 6 Set it equal to zero, and solve for x: 2*x - 6 = 0 x = 3
@youcefhhh7268
Жыл бұрын
orr find the derivative 2x - 6 and it equals 0 when x = 3 then do f(3)
@chayanikapradhan2410
6 ай бұрын
Thxx
@johnvincentbaquiran7855
9 ай бұрын
Wow im flabbergasted
@FunnyAnimatorJimTV
Жыл бұрын
Are you able to factor really fast just by doing it a lot?
@mrhtutoring
Жыл бұрын
Yup. Exactly. Many of the problems you see in school and SAT use the same numbers often.
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