Absolutely satisfied, I wish ncert also update its book with your explanation for a mirage..
@yasirshahmbbs
4 жыл бұрын
NCERT is not written by a single physicist but it has been written by many physicists........ So they what to give and what level should b given to students.....
@pratyushpandaentertainment8689
3 жыл бұрын
Wo khabhi nahi ho sakhata
@Thephysicsplace
3 жыл бұрын
@@yasirshahmbbs level. Does level means to teach wrong
@Thephysicsplace
3 жыл бұрын
Haliday resnik does not say mirage. Wikipedia does not say mirage. Madhav University page also does not say mirage
@ABHISHEKSINGH-tw3ti
3 жыл бұрын
@@Thephysicsplace Then what they say about this?
@MukeshVerma-bz6yu
3 жыл бұрын
Sir aapki video mil gyi toh bass . Dhanye ho gye 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
@GulabSingh-og1bd
2 жыл бұрын
सर जी आप बहुत महान है आप को कोटि कोटि नमन।
@rohitbishnoi1139
3 жыл бұрын
This is brilliant 👌
@dhruvinvekariya975
3 жыл бұрын
Best part Hum apni laboratory me mirage banayenge Which is usually can't done in schools... Thanks sir😍😍
@sciencebyrazasir4246
2 жыл бұрын
I think two rectification is needed to think in right direction. 1 The angle of incidence is not exactly 90degree but very close to 90 degree 2.considering the layer of atmoshpheric layer at micro level .then the confusion of TIR will be solved .TIR happen but with very large angles close to 90degree.then his concept of bending is right .the ultimate trajectory will be parabola symmetrical to x axis .
@ramanarayanmishra4233
2 жыл бұрын
Mr Verma is god of physics for me. Because Alakha sir follow verma sir .so for me he is legent of physics.....
@vardhanmalhotra8370
2 жыл бұрын
Wow wowwww legend of physics❤🔥💚
@ABCDAnyBodyCanDo
4 жыл бұрын
I want to make a humble point here! Both your method and total internal reflection method are correct. Your method explains why it has to bend, theoretically. TIR method tells how it bends, practically. So both are correct. The question of incident angle being 90deg has no meaning. Because in that case, the light ray is not touching surface at all. Also there's no need for the ray to get until 90deg to get totally reflected. So from my point of view, both styles of explanation are correct. If anybody has another point of view, we can discuss here 😊
@thecomedian9077
4 жыл бұрын
No...sir is ryt... Total internal reflection is not the cause here...because tir occurs when there is sharp difference in refractive index between two layers which is not the case here. ... Don't be oversmart.... Being curious is good but first try to understand what sir is saying
@ABCDAnyBodyCanDo
4 жыл бұрын
@@thecomedian9077 Don't get offended brother! Stay calm please! I'm not saying he is wrong. He is correct! But meanwhile TIR is also correct. That's my statement. Have you ever heard of index gradient reflection?! Normally, TIR refers to reflection at an interface between a high index material and a low index material. "index gradient reflection" occurs without need for an interface: instead, it requires only a refractive index that changes gradually. The light rays never need to encounter an interface where the index changes abruptly. Please read my first comment carefully once again. I hope I had a point. I may be wrong. But we can discuss on it with proofs. Thanks for the healthy discussion😍👍
@trsomas
3 жыл бұрын
If we assume that refractive index is continuously changing, then TIR cannot be correct. Here is why TIR says that there is some critical angle (let us say angle C) such that when angle of incidence is greater than C, then the light ray will not go into the second medium but will be fully reflected back into the first medium. As you can see here, the value of C must be less than 90 degree because angle of incidence has to be less than 90 deg. When refractive index changes continuously, then even if you take angle of incidence as 89.99 deg or any value less than 90 deg, there will not be reflection. So what will you take as the value of C? The light ray continuously bends till the angle of incidence becomes 90 degree. After that it moves up due to Huygen's principle (each point acts like a wave front). Then again it keeps on bending as it moves up.
@Amantheparadise
2 жыл бұрын
@@thecomedian9077 how can you think , refractive indices of air are continuously distributed ,,Verma sir case ,is not actually what going on.,and without TIR Mirage not possible,,the relationship btw deviation and incident rays in his book is parabolic for a certain domain because refractive index is smooth.
@poonamramawat7637
Жыл бұрын
@@ABCDAnyBodyCanDo sir ne practical bhi diya last me tir can happen only when there are 2 media involved , But air has technically lots o media(wiith varying n)
@abhi8055.
3 жыл бұрын
Sir sorry to say but u did not talk about the bending back of light at the vertex of the parabolic path. I think that if we are considering the refractive index to be changing gradually, then the ratio of refractive indices of two consecutive elemental layers will be close to 1. So if anywhere in this setup, Total Internal Reflection (TIR) has to happen, by snells law we can find that critical angle C = sin^-1 (n2/n1) where light is going from medium with refractive index n1 to medium with n2. As I've said earlier, since the variation in refractive index between two consecutive elemental layers will be very less, the ratio n2/n1 will tend to 1 ( a little less than one actually) . So critical angle C will tend to 90° (a little less than 90°actually). That means, if anywhere in this setup, TIR happens, it will happen only when incidence angle tends to 90°. So as u explained, initially only refraction will happen and the first half of the parabolic trajectory will be there. But then at the vertex, as soon as the tangent is about to become horizontal, the angle of incidence will tend to 90° and so TIR will happen. That's why light ray should bend up again JUST BEFORE reaching the vertex. If light ray had reached vertex of parabola and had become horizontal once, then it would have always remained horizontal forever bcoz there is no change in refractive index horizontally The method u used can help us find the trajectory of the part where REFRACTION is happening, but the light ray will bend up only bcoz of TIR, that's what I concluded. Am I correct?
@drjkbkgk826
3 жыл бұрын
Guru mujhe tuition padha dijye🤯🤯
@rajeshshekhawatshekhawat5186
3 жыл бұрын
@@drjkbkgk826 teko bhi aajaye ga bass iit crack kar le aur mathematics mai phd 😂
@rajeshshekhawatshekhawat5186
3 жыл бұрын
Ya bro you are correct somewhat I think same
@arunsaha5970
3 жыл бұрын
You are wrong
@abhi8055.
3 жыл бұрын
@@arunsaha5970 please explain how
@elamvaluthis7268
3 жыл бұрын
Agathiya muni and Ayyanar Lord Muruga blessed prof.H.C.Verma.
@TechnologyQuest369
Ай бұрын
🙏
@elamvaluthis7268
Ай бұрын
@@TechnologyQuest369 Thank you sir.
@akshatpandey9141
2 жыл бұрын
Love from Bhagalpur ,Bihar sir aapke lectures bahut acche hain. Best Physics teacher .
@shubhamdas5676
4 жыл бұрын
Awesomely explained...Thank u sir....U just sweeped away my doubts...
@prateeksharma8593
2 жыл бұрын
Congratulation sir for padma shri
@tunetrove5545
4 жыл бұрын
Sir you are one of world's best teacher
@deepakmandal9912
4 жыл бұрын
Then sir fir q hume glt pdaya jata hai...... Aap iss chiz ko aage bdao aur apne name se iss chiz ko explain kro sir ...
The law of refraction was discovered by the Arabic scientist Ibn Sahl in 984 AD. Snell wrote down the equation in 1621 AD. Earlier we did not know about Ibn Sahl so credit was given to Snell. But now that we know Ibn Sahl found the law more than 500 years earlier, it should properly be called Ibn Sahl's law. Look at the Wikipedia article on Ibn Sahl.
@justaguywhoisanidiot159
9 ай бұрын
Bhai pura western science hi toh eastern scientists ne discover kia. Ese to sabka name change karna parega
@rishabhyadav6705
2 ай бұрын
Wrong
@whaddoiknow6519
2 ай бұрын
@@rishabhyadav6705 Would you care to explain what is wrong?
@rabindranathpanda2655
4 жыл бұрын
If there is parabola, vertex is one point.So,the incidence angle must be less than 90 degree &greater than critical angle.So,it is formed due to the reason for TIR.Hope,this comment,HC Verma sir will see and reply.I respect him very much
@vibhansh_bhatia
3 жыл бұрын
Maybe this is a little bit late but anyways here's my opinion Sir as you know the axis that HC verma sir has taken to be tangent of parabola is y axis and the axis of parabola is x axis i.e it is normal at the vertex and we also know that the y axis is perpendicular to the x axis so the angle of incidence is 90°. Hope it helps
@chandramohankumhar2643
4 жыл бұрын
Thank you very much sir for explaining various topics on physics
@kumarprateek9942
3 жыл бұрын
rip the kid of 10th class who asked the question!!
@prathamrevankar8266
Жыл бұрын
It’s in iit syllabus
@Aditya_adi_1
10 ай бұрын
@@prathamrevankar8266 nahi hai bro
@himanshu788
2 жыл бұрын
Sir what if refractive index of air is not linearly increasing and there is no any critical point at the time of refraction and angle of incidence suddenly become greater than critical angle and the reflection occur
@dr.supritajha5077
4 жыл бұрын
Thank you sir Even I thought of a similar reason but in most of the books it was the wrong fact based on TIA
@ABCDAnyBodyCanDo
4 жыл бұрын
It was not wrong mam. Both the explanations are correct. TIR is a practical explanation whereas this is theoretical explanation.
@anshik.k.t
2 жыл бұрын
Sir, would have been better if you would have explained wheres the fault in TIR explanation and why have you assumed gradual variation of refractive index is linear?
@vineetsingh1403
Жыл бұрын
Baba thanks
@meghnatiwari2924
Жыл бұрын
Sir, I think angle of incidence 90° hone se pahle hi total internal reflection ho jayega isliye 90° vali situation nhi aayegi. Neeche se curve smooth nhi hoga
@poonamramawat7637
Жыл бұрын
Vertex toh hoga hi parabola(curve) ka
@ICSECHEMISTRY999
4 жыл бұрын
Very nice doubt clearing class.
@bipinmaurya3824
5 жыл бұрын
Thanks sir
@muktabardhan3400
4 жыл бұрын
But can TIR be totally ruled out? Small deviation from critical angle is quite possible. Gradually increasing and then decreasing ( after reflection) angle of incidences will also make a light ray traverse a path. similar to a parabola.
@black_jack_meghav
5 жыл бұрын
Amazing.
@uditpratapsingh555
5 жыл бұрын
Thanks ...Sir
@urbanbags5505
4 жыл бұрын
Awesome practical
@sachinpathak7872
Жыл бұрын
Sir , may be bending it light is due to internal reflection. as refractive index gradually decrease so reflected light is partially refractured and reflected when it fall on interfere of rarer and denser medium Refracted light shiws bending... I m
@physicsbyzaidhashmi
5 жыл бұрын
Sir please tell about the eddy current....... And also what is reason behind it for only circulating current
@mrsbimkibanerjee7298
3 жыл бұрын
thank you sir this vid helped me a lot :)
@r.kakelaofyou2016
4 жыл бұрын
Very good conseft.
@subhransudey
4 жыл бұрын
sir just ausummmm . we can not think those wrong concept which we study many of times . great explanation sir concept clear hay
@subhadipbardhan9711
4 жыл бұрын
Its bending can be explained by considering huygens principle i.e each point on wavefront behaves like point source.
@mahatojitendra
4 жыл бұрын
Very easy to understand sir. In simple words we can say Yahan Kai bar ek hi direction me dhire dhire rays ka refraction hua hai . am I right ?
@afifakimih8823
4 жыл бұрын
Beautiful explanation...!!
@PrashantKumar-ki8bh
5 жыл бұрын
Great explanation sir....👏👏👏 With all due respect i want to say something.... I think this kind of explanation will not help to the students of class 10.
@arabindodowary5880
5 жыл бұрын
Exactly
@black_jack_meghav
5 жыл бұрын
But I'm in 10th and it IS damn Helpful to me.
@atulsrmcem
4 жыл бұрын
concepts are not according to some class or standard. may a class 10 student will understand this in class 11, but the concept of mirage remains the same.
@SoumyajitMondal
4 жыл бұрын
Even in 12 CBSE boards we have to write the reason as T.I.R though it may be wrong
@mohdzaid4719
4 жыл бұрын
Right
@soumallyabanerjee221
3 жыл бұрын
Thank you sir this excellent explanation.
@kanadbamane1255
3 жыл бұрын
I am your great fan sir
@jitendramisra722
3 жыл бұрын
Great job
@aanchalmaurya3963
3 жыл бұрын
Wow
@saimsun7503
3 жыл бұрын
Great sir.....
@RahulKumar-st9ys
Жыл бұрын
That 10th class student thinking what this differentiation and Integration is!😂 just kidding though!
@subhashchandelia1872
4 жыл бұрын
Great teacher
@loveyouphysicsabhijitsanya8066
3 жыл бұрын
Sir due to curvature of space time continuum may we explain mirage phenomena? I think mirage actually accur due to variable space time with respect to x due to changing density. You say to keep n multiplied by sin theta constant the path of light follow that parabolic trajectory. Mathematics said that. I have no doubt about it. But if we consider here light is a collection of particle how we explain mirage phenomena? Which force is responsible here to bent the path of photon which have momentum? Please kindly reply sir.
@juxtapose4447
3 жыл бұрын
please learn some real physics before asking such questions.
@rajnisingh2232
4 жыл бұрын
Very good morning dear sir , Just needed to mention that the output of differentiation obtained is incorrect and so wrong is the integration ' s output obtained . Even the correct output does not resembles to any sort of parabolic equation. It is = -1 -------------- a( (ax)^2 + 2axc )^1/2 Where a =alpha C = n subscript o
@suparnasenmaity9639
4 жыл бұрын
Extraordinary Lecture...
@youknowwhere6890
5 жыл бұрын
Finally father of physics explained me this Thank you very much sir
@selfeducationzone5024
5 жыл бұрын
Thank you sir please make a video on relativity theory
@rajptrakht2091
2 жыл бұрын
Sir apne to isse aur complex bana kar confuse kar diya mujhe 😅😅 Ab NCERT aasan lag rahi hai 😂
@PrateekChauhan1995
5 жыл бұрын
Sir with due respect it will still not explain the behaviour of the ray at the vertex. I agree with the parabolic shape of the curve but why it bends is still unexplainable.
@santanuchatterjee654
4 жыл бұрын
True. Because if n sin (theta) remains constant then when the ray becomes horizontal it should stay like that for the rest of the path.
@gaurav1966
4 жыл бұрын
While the horizontal path at vertex satisfies Snell's law, it is not a stable path. Any perturbation in upward direction will result in further upwards bending, eventually causing the bent path as shown.
@swastikkanjilal2829
4 жыл бұрын
It's bending is understood from the trajectory of any differential part of light ray...
@subhadipbardhan9711
4 жыл бұрын
Its bending can be explained by considering huygens principle i.e each point on wavefront behaves like point source.
@abhirampande1974
4 жыл бұрын
Because the speed of light change with the change in medium due to the difference in the optical density of the media.
@rajkamal6062
4 жыл бұрын
God of physics...kaash ye hmare physics k teacher hote skul me...to physics se pyar ho jata hme
@NeevClassesBangalore
2 жыл бұрын
Sir, with due respect, I would request you to reconsider your explanation. You say, you have a problem at the vertex point in your diagram where i=90deg; Are you sure that incident rays are reaching 'your' vertex? Pls do consider that a few layers before your vertex, critical angle will be reached, where the rays will reflect AS WELL AS graze at your r=90. Real world (aka fluctiation in densities) may make your grazing rays rise up, but Mathematically they wont. If you say that the layer densities are so minutely changing that the index diff is very less and hence the critical angle is almost 90 deg; then too i will advise you to take help of REFLECTION to make your rays rise back. Btw then your calculated path will be very very close to the actual path (provided your proposed index variation is taken), but i know that you will know the big difference is the reasoning (i never reaches 90 deg). Btw i always tell my students, that refraction of a beam of light doesn't rule out reflection; reflection always happens; the only question is how much. To cut things short : If you consider parallel layers of varying densities, then a light ray going down can not come back upwards based on REFRACTION no matter what the refractive indices are. Only reflection can send the rays back. TIR WILL happen before i becomes 90deg. One may further note that the INTERNAL reflections happening before TIR will start superseding the intensity of refracted ray as the rays become more and more slant.
@tanishq314
7 ай бұрын
Plz sim make all video jee advance and jee mains
@harishankarpatel2926
4 жыл бұрын
Sir I agree with parabolic path for which nsina=constant but this is equally applicable If light go straight with making angle 90 degree because still nsina=constant there then why they change their path
@mayankyadav31
5 жыл бұрын
Wonderful !!!
@amongusussy
Ай бұрын
3 inch(1.5
@vrishalideshpande5999
8 ай бұрын
Sir after total reflection the light again travels back from rarer to denser medium so it moves towards the normal while passing thru every layer so it apears that it bends
@vrishalideshpande5999
8 ай бұрын
This is the understanding i had in my mind till today
@codernakul
5 жыл бұрын
Sir plz make videos for class 11 refering your book CONCEPTS OF PHYSICS
@AdityaSingh-tg3pd
3 жыл бұрын
Alakh Pandey sir ka channel check kar lete
@arpitatiwari1629
3 жыл бұрын
@@AdityaSingh-tg3pd he asked 2 years ago
@suryaterror5257
5 жыл бұрын
Sir , with all due respect, can you please make a video on the transverse nature of light..
@Dwizzz..
Жыл бұрын
Legend get to know about TIR in 12th😂
@narendratanty4604
3 жыл бұрын
Thank you so much sir
@balajiphysicswallah8289
4 жыл бұрын
Sir absolutely nice
@mayankyadav31
5 жыл бұрын
Thanks a lot sir!!
@arpitpandey3914
4 жыл бұрын
Wow wow wow...sir ...thank u so much..
@ayuschmannov2461
4 жыл бұрын
*WOW !!!!*
@poojakasaudhan4726
2 жыл бұрын
Sir please make a video for class 10 all chapter of physics in deeply sir please make video
@taheeramalik9911
Жыл бұрын
Sir how far the actual object is from the place where mirage occured?
@bailochanpadhi1164
5 жыл бұрын
Thnq so much sir 🙏🙏🙏
@Physicsforfun
4 жыл бұрын
Respected sir, in rainbow formation total internal reflection involved or not . I found contradiction in concept of physics part 1 2012 print and foundation science physics for class 10. Forth adition reprint 2012. Regards Nitin nagar class 10th.
@PrayaasPhysicsClassesDehradun
4 жыл бұрын
It is not Tir...it is internal reflection that happens along with refraction
@Thephysicsplace
3 жыл бұрын
@@PrayaasPhysicsClassesDehradun new edition of hc Verma has corrected it
@inderjitsingh3712
4 жыл бұрын
An Eye Opener for teachers too.
@bimaljha1464
4 жыл бұрын
God of physics
@aryanamarjeetyadav8533
4 жыл бұрын
nice sir
@thertist1225
5 жыл бұрын
Sir , but in the brachistocrome problem the path of light though a continuously variable refractive medium is a cycloid .
@yashdeole1413
5 жыл бұрын
Yeah right
@yashdeole1413
5 жыл бұрын
Maybe not neglecting alpha² x² leads to cycloid
@drayoncoolagon9257
3 жыл бұрын
the path isn't continously variable , the change in a small fraction is very small
@saurabh4597
5 жыл бұрын
Great great
@eminem4701
2 жыл бұрын
In simple words, Sir has considered critical angle to br 90° at "point" of turn which is only true if the two media have exactly same optical densities. So sir has considered the elemental(infinitesimal small) air-region at the point of turn, to have uniform optically density, but this is not exactly true bcz we know the air will be rearer below than above, though infinitesimally for elemental region, hence critical angle won't exactly be 90° which implies that at just before 90° TIR will indeed occur Also, i suppose, that the path won't be a perfect parabola🙄
@StudyPhysics2020
4 жыл бұрын
Sir , when light comes in water from air then its wavelength change but the colour is not change. While different wavelengths have different colours.
@shambhuyadav212
4 жыл бұрын
wavelength never change s only speed changes
@soumikdhole2523
3 жыл бұрын
@@shambhuyadav212 no. Both wavelength and speed changes. But the frequency remains constant. Speed of Light (in any medium) = frequency of the light wave multiplied with its wavelength.
@Allinone-jf8ro
4 жыл бұрын
It means TIR cause is wrong if it is wrong then how??
@intuitionworld1604
2 жыл бұрын
Sir I have a doubt,that the actual curve of a mirage should not be a parabolic its just seems to like parabolic...if that is right then in that case how one can able to explain that mirage concept of using your this explanation where as your final result shows that curve should be like a parabolic curve!?
@santanuchatterjee654
4 жыл бұрын
It is a great explanation, Sir. But I would like to clarify two points. 1) When you say n sin (theta) is constant, then once the ray becomes horizontal it should stay such as n is not changing anymore thus theta should remain 90 for the rest of the path. It should not bend again. 2) Snell's law is valid as long as light is traveling from one medium to another of different optical densities. But once the ray becomes horizontal, it travels in the same medium. So can we use Snell's law at that boundary?
@aeonian_harshul
4 жыл бұрын
The catch is that TIR only occur at the lowest most point where incident ray becomes greater than critical angle which tends to be 90° as the ratio refractive index at that point and just below it is very minute, when you put it in calculator it comes out be like 0.999999. And when you take aSin of it you get critical angle about 89.8744°. Hence ray can only reflect by mechanism TIR after it has attained almost 90°. After reflecting a little, it again follws the parabolic pathway like it did to come to lowest most point.
@trsomas
3 жыл бұрын
Yes. the light ray moves horizontally but it bends upward a little because of wave nature of light. The speed of the upper part of a wavefront is lower than the speed of the lower part. Because of this the upper part travels smaller distance in a given time than the lower part. This causes a light beam to bend. In order to understand mirage, we cannot ignore the wave nature of light (not even as an approximation).
@aadityakiran_s
3 жыл бұрын
Beautiful.
@biplabgon7837
2 жыл бұрын
Sir can't this be that their are infinite.interfaces as if we consider.dl^2 has one.interface then their will.be infinite interfaces so infinite lines will form.a curve...therefore the curve can be explained by tir
@user-ni8pm2fh1d
7 ай бұрын
He has done doctor in physics so why everyone is using their wrong effort
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