I don't think there is a better way to teach these concepts. You are a special teacher. Thank You
@coolwinder
3 жыл бұрын
01:25 - Intro 06:25 - Example with Capacitor at the Output 10:20 - Poles and Zeros - Bode's Rules 18:00 - Pole Frequency 21:10 - Finding Poles by Inspection 27:10 - Example with the CS Amplifier and Capacitor at the Inpiut 30:32 - Example with the CS Amplifier and Capacitor at the Output 34:40 - Combining Examples - Multiple Poles 40:28 - Plotting Frequency Response 44:35 - A Complication
@th3roc
3 ай бұрын
learned more in the first 10 minutes of this video than I learned in the first 1.5 semesters of my MSEE degree. Thank you for making this content available for everyone.
@teddy619
5 жыл бұрын
Wow! How easy you explain things. Can’t wait to learn about Miller effect
@srinivasan7790
5 жыл бұрын
its great to master analog design, but even more greater to make it understandable for the learners. really admire razavi
@claudioregis6078
5 жыл бұрын
I love this guy, every example on this lecture led us to the contruction of the complete small signal model of a MOSFET with the capacitances included. Brilliant!!
@ggmb1032
4 ай бұрын
Always thank you sir. Your attitude towards teaching the world is unmatched.
@muhammadsohaib6282
2 жыл бұрын
Behzad Razavi lectures always inspires me.King of Electronics..Great Prof. These Lectures Are Assets..Thanks ❤
@alexandrosanastasiou1964
5 жыл бұрын
I read past comments about how you teach us by simple steps the final outcome, but how this helped me has never been more obvious than this lecture. This is truly amazing. It took me only one hour to go from simple RC circuits to MOSFET ones
@indrashispowali
Жыл бұрын
Thank you very much, Professor!
@aidanb5021
8 ай бұрын
What a fantastic lecture, thank you so much!
@Sourav_Soumyajit
6 ай бұрын
What an explanation!
@fadiharb2023
3 жыл бұрын
Its just awesome .. u the best prof.
@vOvOv_
4 жыл бұрын
21:41 Finding poles by inspection
@Sorrel555
4 жыл бұрын
This is a Godsend. Thank you so much, you saved me!
@akashtanwar1939
2 жыл бұрын
This guy is special.
@mnada72
3 жыл бұрын
Waiting eagerly for circuit theory I & II and the rest of the series.
@DM1114-wd9rs
2 ай бұрын
can anyone tell me before this in which lecture prof. has discussed poles & zeros as I came to specifically look at that
@dennistsai5348
Жыл бұрын
OMG! It’s Razavi!
@praneshmajumder5141
Жыл бұрын
can anyone please give me the link of that basic circuit theory lecture in which the pole and zero concepts had been taught?
@ahmedmohamed-yo2hb
4 жыл бұрын
what's the first lecture which bode plot has been introduced ?
@mrpossible5696
5 жыл бұрын
Ty
@anafivp7897
5 жыл бұрын
nice explenation
@mhmd_rjb
2 жыл бұрын
that is great
@NaaJeevitham500
5 жыл бұрын
Can we also identify right-hand side poles by inspection?
@boya1827
4 жыл бұрын
I didn't get the reasoning at 9:40, shouldn't the gain be higher because the voltage drop is smaller?
@saicharanmarrivada5077
4 жыл бұрын
Capacitor acts as a short circuit at infinite frequency ,so Vout=0 =>Av=0
@chevestong
2 жыл бұрын
@Sai Charan Marrivada's reply is the real reasoning. Your logic is correct and Dr. Razavi didn't mention that properly.
@abhishekdhiman4
4 жыл бұрын
Love yousir
@MrBubblegumx
4 жыл бұрын
where did the j at 19:10 go? shouldnt the frequency be "1/(jRC)"?
@SuNguyen-wc6zi
2 жыл бұрын
he kept it in s land. He didnt convert to s=jw b/c its bode magnitude plot anyways, dont need the j , just w. Also H(jw) = 1/(jwRC) , you forgot the w if you are going to s=jw
@electronicsmadeeasy8385
2 жыл бұрын
Detailed Electronics Lectures available in Urdu Language
@vaibhavvajpai2353
2 жыл бұрын
Can you provide the link for quiz?
@varunnagpal2258
5 жыл бұрын
The reasoning at 9:20 is not correct even though conclusion is Id = const I = Id + Ic ; Vout = Vdd - I.Rd At w=0, I = Id => Vo = Vdd - Id.Rd At w !=0, I = (Id + Ic) > Id => Vo = (Vdd - (Id+Ic) Rd ) < (Vdd-IdRd), So as w increases, I increases, drop I.Rd increases and Vo decreases
@srinivasan7790
5 жыл бұрын
nice, was wondering about the same,
@NaaJeevitham500
5 жыл бұрын
You said Id is constant. So Id= Ir+Ic. If there is no capacitor, Id=Ir. Doesn't that mean drop across resistor decreased
@joshmeiyb
5 жыл бұрын
By using "Small-Signal Analysis": At w=0, Vout = Rd *(Id) At w!=0, Vout = Rd*(Id - Ic) I think you guys forget Vdd is "ac GND" at "Small-Signal Analysis",lol
@boya1827
4 жыл бұрын
@@joshmeiyb I think what you said is completely correct.
@OfficialAnarchyz
4 жыл бұрын
@@joshmeiyb Exactly. We're talking about AC input voltages. This is small-signal analysis.
@milindgoel405
Жыл бұрын
11:50 Bode's Rules
@mrpossible5696
5 жыл бұрын
27:40
@user-sb4id5vo6m
2 жыл бұрын
45:30
@technical_solution1990
5 жыл бұрын
There is a mistake 13:58 bode rule 20Db slope increases when approaches to poles.....
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